Presentation is loading. Please wait.

Presentation is loading. Please wait.

LESSON 10–3 Arcs and Chords.

Similar presentations


Presentation on theme: "LESSON 10–3 Arcs and Chords."— Presentation transcript:

1 LESSON 10–3 Arcs and Chords

2 Five-Minute Check (over Lesson 10–2) TEKS Then/Now Theorem 10.2
Example 1: Real-World Example: Use Congruent Chords to Find Arc Measure Example 2: Use Congruent Arcs to Find Chord Lengths Theorems Example 3: Use a Radius Perpendicular to a Chord Example 4: Real-World Example: Use a Diameter Perpendicular to a Chord Theorem 10.5 Example 5: Chords Equidistant from Center Lesson Menu

3 A. 105 B. 114 C. 118 D. 124 5-Minute Check 1

4 A. 35 B. 55 C. 66 D. 72 5-Minute Check 2

5 A. 125 B. 130 C. 135 D. 140 5-Minute Check 3

6 A. 160 B. 150 C. 140 D. 130 5-Minute Check 4

7 A. 180 B. 190 C. 200 D. 210 5-Minute Check 5

8 Dianne runs around a circular track that has a radius of 55 feet
Dianne runs around a circular track that has a radius of 55 feet. After running three quarters of the distance around the track, how far has she run? A ft B. 165 ft C ft D ft 5-Minute Check 6

9 Mathematical Processes G.1(B), G.1(G)
Targeted TEKS G.12(A) Apply theorems about circles, including relationships among angles, radii, chords, tangents, and secants, to solve non-contextual problems. Mathematical Processes G.1(B), G.1(G) TEKS

10 You used the relationships between arcs and angles to find measures.
Recognize and use relationships between arcs and chords. Recognize and use relationships between arcs, chords, and diameters. Then/Now

11 Concept

12 Use Congruent Chords to Find Arc Measure
Jewelry A circular piece of jade is hung from a chain by two wires around the stone. JM  KL and = 90. Find Example 1

13 Use Congruent Chords to Find Arc Measure
Example 1

14 A. 42.5 B. 85 C D. 170 Example 1

15 Use Congruent Arcs to Find Chord Lengths
Example 2

16 WX = YZ Definition of congruent segments 7x – 2 = 5x + 6 Substitution
Use Congruent Arcs to Find Chord Lengths WX = YZ Definition of congruent segments 7x – 2 = 5x + 6 Substitution 7x = 5x + 8 Add 2 to each side. 2x = 8 Subtract 5x from each side. x = 4 Divide each side by 2. So, WX = 7x – 2 = 7(4) – 2 or 26. Answer: WX = 26 Example 2

17 A. 6 B. 8 C. 9 D. 13 Example 2

18 Concept

19 Use a Radius Perpendicular to a Chord
Answer: Example 3

20 A. 14 B. 80 C. 160 D. 180 Example 3

21 Use a Diameter Perpendicular to a Chord
CERAMIC TILE In the ceramic stepping stone below, diameter AB is 18 inches long and chord EF is 8 inches long. Find CD. Example 4

22 Step 1 Draw radius CE. This forms right ΔCDE.
Use a Diameter Perpendicular to a Chord Step 1 Draw radius CE. This forms right ΔCDE. Example 4

23 Use a Diameter Perpendicular to a Chord
Step 2 Find CE and DE. Since AB = 18 inches, CB = 9 inches. All radii of a circle are congruent, so CE = 9 inches. Since diameter AB is perpendicular to EF, AB bisects chord EF by Theorem So, DE = (8) or 4 inches. __ 1 2 Example 4

24 Step 3 Use the Pythagorean Theorem to find CD.
Use a Diameter Perpendicular to a Chord Step 3 Use the Pythagorean Theorem to find CD. CD2 + DE2 = CE2 Pythagorean Theorem CD = 92 Substitution CD = 81 Simplify. CD2 = 65 Subtract 16 from each side. Take the positive square root. Answer: Example 4

25 In the circle below, diameter QS is 14 inches long and chord RT is 10 inches long. Find VU.
Example 4

26 Concept

27 Chords Equidistant from Center
Since chords EF and GH are congruent, they are equidistant from P. So, PQ = PR. Example 5

28 PQ = PR 4x – 3 = 2x + 3 Substitution x = 3 Simplify.
Chords Equidistant from Center PQ = PR 4x – 3 = 2x + 3 Substitution x = 3 Simplify. So, PQ = 4(3) – 3 or 9 Answer: PQ = 9 Example 5

29 A. 7 B. 10 C. 13 D. 15 Example 5

30 LESSON 10–3 Arcs and Chords


Download ppt "LESSON 10–3 Arcs and Chords."

Similar presentations


Ads by Google