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BHASVIC MΞ±THS Skills 1 A1 DOUBLES ASSIGNMENT 20B
Use the substitutions given to find: (a) π₯ 1+π₯ dπ₯;π’=1+π₯ (b) sin π₯ cos π₯ dπ₯;π’= sin π₯ (c) sin 3 π₯ dπ₯;π’= cos π₯ (d) π₯ (π₯β4) dπ₯;π’= π₯ (e) sec 2 π₯ tan π₯ 1+ tan π₯ dπ₯; π’ 2 =1+ tan π₯ (f) sec 4 π₯ dπ₯;π’= tan π₯
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BHASVIC MΞ±THS Skills 2 A1 DOUBLES ASSIGNMENT 20B
Find the following integrals (a) 3 ln π₯ dπ₯ (b) π₯ ln π₯ dπ₯ (c) ln π₯ π₯ 3 (d) ( ln π₯) 2 dπ₯ (e) π₯ ln π₯ dπ₯
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BHASVIC MΞ±THS Skills 1 - Answers A1 DOUBLES ASSIGNMENT 20B
2 5 (1+π₯) β π₯ π β ln 1β sin π₯ +π cos 3 π₯ 3 β cos π₯+π ln π₯ β2 π₯ +2 +π 2 5 (1+ tan π₯ ) β 2 3 (1+ tan π₯) π tan π₯ tan 3 π₯+π
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BHASVIC MΞ±THS Skills 2 β Answers A1 DOUBLES ASSIGNMENT 20B
3π₯ ln π₯β3π₯+π π₯ ln π₯β π₯ π β ln π₯ 2 π₯ 2 β 1 4 π₯ 2 +π π₯ ( ln π₯) 2 β2π₯ ln π₯+2π₯+π π₯ ln π₯β π₯ π₯ ln π₯βπ₯+3
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BHASVIC MΞ±THS 1 A1 DOUBLES ASSIGNMENT 20B
Find the set of values of π’ that satisfy 3 π’ 2 +2β€ β7 π’ , π’β 0 Hence find the set of values of π’ that satisfy 3 (π’β1) 2 +2β€ β7 (π’β1) , π’β 0
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BHASVIC MΞ±THS 2 A1 DOUBLES ASSIGNMENT 20B
A ball is thrown in the air. After π‘ seconds, its height, π , in metres above the ground is given by the equation 2π =β 10π‘ 2 +16π‘+3. (a) Find π‘ when the ball is 4.5 metres above the ground. (b) Show that π =π (π‘+π) 2 +π where π,π and π are constants to be found. (c) Hence find the maximum height of the ball and the value of t for which this occurs.
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BHASVIC MΞ±THS 3 A1 DOUBLES ASSIGNMENT 20B
Solve the following inequalities π₯β1 π₯β2 β₯4 2 π 2 3π+2 <1
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BHASVIC MΞ±THS 4 A1 DOUBLES ASSIGNMENT 20B
The points A, B, C and D have co-ordinates (-5,6) and (5,1) and (8,3) and (k,-13), respectively, where k is a constant. (a) Find an equation of the straight line through A and B. (b) Given that CD is perpendicular to AB, find the value of k
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BHASVIC MΞ±THS 5 A1 DOUBLES ASSIGNMENT 20B
A smooth bead Y is threaded on a light inextensible string. The ends of the string are attached to two fixed points X and Z on the same horizontal level. The bead is held in equilibrium by a horizontal force of magnitude 8N acting parallel to ZX. The bead Y is vertically below X and angle XZY = 30Β° Find (a) the tension in the string, (b) the weight of the bead.
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BHASVIC MΞ±THS 6 A1 DOUBLES ASSIGNMENT 20B
A particle P is projected with velocity 3π’i+4π’j m s-1 from a fixed point O on a horizontal plane. Given that P strikes the plane at a point 750 m from O, (a) show that u = 17.5, (b) calculate the greatest height above the plane reached by P, (c) find the angle the direction of motion of P makes with i when t = 5.
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BHASVIC MΞ±THS 7 A1 DOUBLES ASSIGNMENT 20B
The curve C has equation π¦= π₯ π₯ 2 +1 (a) Show that there is no point on C where the gradient is -1 (b) Find the co-ordinates of the points on C where the gradient is
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BHASVIC MΞ±THS 8 A1 DOUBLES ASSIGNMENT 20B
(a) A curve has parametric equations π₯= π‘ 2 β1, π¦=π‘β π‘ 3 . Draw this curve for when β2β€π‘β€2. (b) Find the Cartesian equation of the curve when t > 0
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BHASVIC MΞ±THS 9 A1 DOUBLES ASSIGNMENT 20B
The curve C shown in Figure 4 has parametric equations # π₯= tan π, π¦=5 sec π, β π 2 <π< π 2 The curve C crosses the y-axis at A and has a minimum turning point at B, as shown in Figure 4. (a) Find the exact coordinates of A. (b) Show that ππ¦ ππ₯ =π sin π , giving the exact value of the constant π (c) Find the coordinates of B. (d) Show that the Cartesian equation for the curve C can be written in the form π¦=π π₯ 2 β2π₯+4 where k is a simplified surd to be found.
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BHASVIC MΞ±THS 10 A1 DOUBLES ASSIGNMENT 20B
The figure above shows the graph of the curve with equation π¦=8π₯β4π₯ ln π₯ , 0<π₯β€ π 2 The region π
is bounded by the curve, the π₯ axis and the line with equation π₯=1 Determine the exact area of π
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BHASVIC MΞ±THS 11 A1 DOUBLES ASSIGNMENT 20B
Using a suitable trigonometric substitution for x, find π₯ 2 1β π₯ 2 dπ₯
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 20B 12 Find: 3βπ₯ 2 π₯ 3 β π₯ 2 ππ₯
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BHASVIC MΞ±THS 1 - Answers A1 DOUBLES ASSIGNMENT 20B
β3β€π’ β€ β1 2 (you must include a sketch) β2β€π’ β€ 1 2
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BHASVIC MΞ±THS 2 - Answers A1 DOUBLES ASSIGNMENT 20B π‘= 3 5 or π‘=1
π=β5, π= 4 5 , π=4.7 Max is 4.7 metres when π‘=0.8 seconds.
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BHASVIC MΞ±THS 3 - Answers A1 DOUBLES ASSIGNMENT 20B 9 5 β€π₯β€ 7 3
9 5 β€π₯β€ 7 3 β 1 2 <π<2
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 20B 4 - Answers x + 2y = 7 k = 0
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BHASVIC MΞ±THS 5 - Answers A1 DOUBLES ASSIGNMENT 20B T=9.24N (3sf)
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BHASVIC MΞ±THS 6 - Answers A1 DOUBLES ASSIGNMENT 20B (b) 250 m
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BHASVIC MΞ±THS 7 - Answers A1 DOUBLES ASSIGNMENT 20B
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BHASVIC MΞ±THS 8 - Answers A1 DOUBLES ASSIGNMENT 20B Check desmos
π¦= π₯+1 β π₯+1 3
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BHASVIC MΞ±THS 9 - Answers A1 DOUBLES ASSIGNMENT 20B π΄ 0, 10 3 3 π= 5 3
π΄ 0, π= 5 3 π΅(1, 5) π=
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 20B 10 - Answers π 4 β5
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BHASVIC MΞ±THS A1 DOUBLES ASSIGNMENT 20B 11 - Answers 2π
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BHASVIC MΞ±THS 12 - Answers A1 DOUBLES ASSIGNMENT 20B
β5 ln π₯ +3 π₯ β1 +5 ln 2π₯β1 +π
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