1. raffle_snaffle
Recall from homework set #2, air in a closed system undergoes two processes in series.
First the air is compressed from state 1 to state 2 in a polytropic manner with n=1.3.
Next the air is expanded at constant pressure from state 2 back to state 3, which is at the original volume.
The following state point properties are known:
P1=110 kPa, v1=0.8m3/kg,
v2=0.4 m3/kg.
Using state point information from homework set #2, determine the following. a.
Draw the processes and label the state points on a single T-‐‐s diagram. b.
Determine the entropy produced per mass from state 1 to state 2. Use a b
Some specific values of n correspond to particular cases:
n=0 is an isobaric process,
n=∞ is an isochoric process.
In addition, when the ideal gas law applies:
n=1 is an isothermic process,
n=γ is an isentropic process.

2. State 1 to state 2 is adiabatic with specific heat ratio 1.3 ?
Because it’s adiabatic it is isentropic. On the T-S diagram.
If it’s an isentropic/adiabatic compression, then the temperature will rise. Hence the numbering.
State 2 to 3 is isobaric.
Slope is contained in this equation.
The slope is less than it would be if the process were to have been constant volume aka isochoric.