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Algebra 1 Section 5.3
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Graphs t is the independent variable. h is the dependent variable.
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Graphs D = {t | 0 ≤ t ≤ 3} R = {h | 6 ≤ h ≤ 20}
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Vertical Line Test The vertical line test tells us that if a vertical line intersects the relation’s graph in more than one point, the relation is not a function.
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Example 1a D = {0, ±1, ±2, ±3} R = {0, 0.5, 2, 4.5} The relation is a function; no vertical line intersects the graph at more than one point.
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Example 1b D = {0, ±1, ±2, ±3} R = {-2, -1, 0, 1, 2, 3, 4, 5}
The relation is not a function; a vertical line crossing the x-axis at -1 contains both (-1, -2) and (-1, 3).
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Example 1c D = {x | x ≥ 0} R = all real numbers
The relation is not a function; any vertical line crossing the positive x-axis crosses the graph at more than one point.
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Equations An equation is often used to clearly define the rule that determines the values of the range associated with each member of the domain.
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Example 2 A = {(x, y) | y = x + 2; x = 1, 2, 3, 4}
x y = x ordered pair 1 2 3 4 3 4 5 6 (1, 3) (2, 4) (3, 5) (4, 6)
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Example 2 A = {(x, y) | y = x + 2; x = 1, 2, 3, 4} y (1, 3) (2, 4)
(3, 5) (4, 6) x
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Example 2 A = {(x, y) | y = x + 2; x = 1, 2, 3, 4} y
This relation is a function. No vertical line will intersect more than one point. x
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What if...? A = {(x, y) | y = x + 2; x = 1, 2, 3, 4}
What if no domain had been stated for this function? x
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What if...? A = {(x, y) | y = x + 2} y
Then the entire line would satisfy the equation. x
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What if...? A = {(x, y) | y = x + 2} y
The coordinates of every point on the line satisfy the equation. x
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Example 3 If x is just an integer from 1 to 5, then the graph consists of just five points. If x can be any number from 1 to 5, then the graph would be a segment from (1, 3) to (5, 3). In either case, it is a function.
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Example 4 D = {(x, y) | y = ± x; x = 1, 4, 9} Domain: D = {1, 4, 9}
Range: R = {-3, -2, -1, 1, 2, 3} This relation is not a function. It fails the vertical line test.
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Graphing Functions Because functions are relations, they are graphed using the same methods. If the domain is not restricted, then a smooth curve connecting the ordered pairs should be drawn.
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Example 5 f(x) = -x2 (-2, -4) (-1, -1) (0, 0) (1, -1) (2, -4) y x
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Example 5 The domain is all real numbers. The range is {y | y ≤ 0}. y
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Homework: pp
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