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GRAPH EXPONENTIAL DECAY FUNCTIONS

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Presentation on theme: "GRAPH EXPONENTIAL DECAY FUNCTIONS"— Presentation transcript:

1 GRAPH EXPONENTIAL DECAY FUNCTIONS
SECTION 7.2 GRAPH EXPONENTIAL DECAY FUNCTIONS

2 EXPONENTIAL GRAPHS Exponential Growth Exponential Decay
y = a•bx (b > 1) y = 3(2)x y = a•bx (0 < b < 1) y = 3(0.5)x

3 Graph y = b for 0 < b < 1 x
EXAMPLE 1 Graph y = 1 2 x SOLUTION STEP 1 Make a table of values STEP 2 Plot the points from the table. STEP 3 Draw, from right to left, a smooth curve that begins just above the x-axis, passes through the plotted points, and moves up to the left.

4 Graph y = ab for 0 < b < 1 x
EXAMPLE 2 Graph the function. a. Graph y = 2 1 4 x SOLUTION Plot (0, 2) and then , from right to left, draw a curve that begins just above the x-axis, passes through the two points, and moves up to the left. 1, 1 2 a.

5 EXPONENTIAL DECAY MODEL
y = a(1-r)t Decay Factor: 1-r a: initial amount r: percent decrease as a decimal t: time

6 EXAMPLE 4 Solve a multi-step problem A new snowmobile costs $4200. The value of the snowmobile decreases by 10% each year. Snowmobiles • Write an exponential decay model giving the snowmobile’s value y (in dollars) after t years. Estimate the value after 3 years. • Graph the model. • Use the graph to estimate when the value of the snowmobile will be $2500.

7 EXAMPLE 4 Solve a multi-step problem SOLUTION STEP 1 The initial amount is a = 4200 and the percent decrease is r = So, the exponential decay model is: y = a(1 – r) t Write exponential decay model. = 4200(1 – 0.10) t Substitute 4200 for a and 0.10 for r. = 4200(0.90) t Simplify. When t = 3, the snowmobile’s value is y = 4200(0.90)3 = $

8 The graph passes through the points (0, 4200) and (1, 3780).
EXAMPLE 4 Solve a multi-step problem STEP 2 The graph passes through the points (0, 4200) and (1, 3780). It has the t-axis as an asymptote. Plot a few other points. Then draw a smooth curve through the points. STEP 3 Using the graph, you can estimate that the value of the snowmobile will be $2500 after about 5 years.


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