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POLAR CURVES Intersections.

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1 POLAR CURVES Intersections

2 Sketch these graphs: r=4 cos ΞΈ π‘Ÿ=10 cos πœƒ π‘Ÿ= 1 4 sin πœƒ r=2 sin 4ΞΈ
Polar curves KUS objectives BAT Find points of intersection of Polar curves BAT Find Areas bounded by parts of Polar curves Starter: Sketch these graphs: π‘Ÿ=10 cos πœƒ r=4 cos ΞΈ π‘Ÿ= 1 4 sin πœƒ r=2 sin 4ΞΈ π‘Ÿ=6 cos πœƒ +8 sin πœƒ r=1+ cos ΞΈ π‘₯=π‘Ÿπ‘π‘œπ‘ πœƒ 𝑦=π‘Ÿπ‘ π‘–π‘›πœƒ πœƒ=π‘Žπ‘Ÿπ‘π‘‘π‘Žπ‘› 𝑦 π‘₯ π‘Ÿ 2 = π‘₯ 2 + 𝑦 2

3 WB16 a) On the same diagram, sketch the curves with equations:
π‘Ÿ=3+2 cos πœƒ and π‘Ÿ=5 βˆ’2 cos πœƒ for βˆ’πœ‹β‰€πœƒβ‰€πœ‹ b) Find the polar coordinates of the intersection of these curves To find the intersection, we can use the two equations we were given: 3+2π‘π‘œπ‘ πœƒ=5βˆ’2π‘π‘œπ‘ πœƒ 2=4π‘π‘œπ‘ πœƒ 0.5=π‘π‘œπ‘ πœƒ πœƒ= πœ‹ 3 , βˆ’ πœ‹ 3 Using these values of ΞΈ, we get r = 2.5 at both points

4 Using these values of ΞΈ, we get
WB17 a) On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ and r = 5cosΞΈ b) Find the polar coordinates of the intersection of these curves To find the intersection, we can use the two equations we were given: 2+π‘π‘œπ‘ πœƒ=5π‘π‘œπ‘ πœƒ 2=4π‘π‘œπ‘ πœƒ Ο€ 2 0.5=π‘π‘œπ‘ πœƒ (2.5,Ο€/3) πœƒ= πœ‹ 3 , βˆ’ πœ‹ 3 𝒓=𝟐+π’„π’π’”πœ½ Ο€ 0, 2Ο€ Using these values of ΞΈ, we get r = 2.5 at both points 𝒓=πŸ“π’„π’π’”πœ½ (2.5,-Ο€/3) 3Ο€ 2

5 POLAR CURVES Areas

6 WB18a To find the area enclosed by the curve, and the half lines ΞΈ = Ξ± and ΞΈ = Ξ², you can use the formula : π΄π‘Ÿπ‘’π‘Ž= 1 2 𝛼 𝛽 π‘Ÿ 2 π‘‘πœƒ 0, 2Ο€ Ο€ 2 Ο€ 3Ο€ 2 𝒓=𝟏+π’„π’π’”πœ½ Ο€ 6 Ο€ 3 Find the area enclosed by the curve, r=1+cosΞΈ, and the half lines ΞΈ = Ο€ 6 and ΞΈ = Ο€ 3 , = πœ‹ 6 πœ‹ π‘π‘œπ‘ πœƒ 2 π‘‘πœƒ notice the 1/2r2ΞΈ being familiar as the formula for the area of a sector

7 WB18b Find the area enclosed by the curve, r=1+cosΞΈ, and the half lines ΞΈ = Ο€ 6 and ΞΈ = Ο€ 3 , 1 2 πœ‹ 6 πœ‹ π‘π‘œπ‘ πœƒ 2 π‘‘πœƒ = πœ‹ 6 πœ‹ 3 (1+2 cos πœƒ + π‘π‘œπ‘  2 πœƒ )π‘‘πœƒ = πœ‹ 6 πœ‹ 3 (1+2 cos πœƒ cos 2πœƒ +1 )π‘‘πœƒ = πœ‹ 6 πœ‹ cos πœƒ cos 2πœƒ π‘‘πœƒ = πœƒ+2 sin πœƒ sin 2πœƒ πœ‹ 3 πœ‹ 6 = πœ‹ 6 +2 sin πœ‹ sin 2 πœ‹ 3 βˆ’ πœ‹ 6 +2 sin πœ‹ sin 2 πœ‹ 6 =1.047

8 Now we can think about actually Integrating!
WB19a Find the area enclosed by the cardioid with equation: r = a(1 + cosΞΈ) 0, 2Ο€ Ο€ 2 Ο€ 3Ο€ 2 As the curve has reflective symmetry, we can find the area above the x-axis, then double it… Sketch the graph (you won’t always be asked to do this, but you should do as it helps visualise the question…) So for this question: π‘Ÿ=π‘Ž(1+π‘π‘œπ‘ πœƒ) 𝛼=0 𝛽=πœ‹ We will now substitute these into the formula for the area, given earlier: π΄π‘Ÿπ‘’π‘Ž= 1 2 𝛼 𝛽 π‘Ÿ 2 π‘‘πœƒ = 0 πœ‹ π‘Ž 1+π‘π‘œπ‘ πœƒ 2 π‘‘πœƒ =π‘Ž 2 0 πœ‹ 1+2π‘π‘œπ‘ πœƒ+ π‘π‘œπ‘  2 πœƒ π‘‘πœƒ We will need to rewrite the cos2 term so we can integrate it =π‘Ž 2 0 πœ‹ π‘π‘œπ‘ πœƒ+ 1 2 π‘π‘œπ‘ 2πœƒ π‘‘πœƒ = π‘Ž 2 0 πœ‹ 1+2π‘π‘œπ‘ πœƒ+ 1 2 π‘π‘œπ‘ 2πœƒ π‘‘πœƒ Now we can think about actually Integrating!

9 WB19b Find the area enclosed by the cardioid with equation: r = a(1 + cosΞΈ)
=π‘Ž 2 0 πœ‹ π‘π‘œπ‘ πœƒ+ 1 2 π‘π‘œπ‘ 2πœƒ π‘‘πœƒ 0 πœ‹ 3 2 πœƒ 𝑠𝑖𝑛2πœƒ = π‘Ž 2 + 2π‘ π‘–π‘›πœƒ 3 2 πœ‹+0+0 βˆ’ = π‘Ž 2 0+0+0 = 3πœ‹ π‘Ž 2 2 Show full workings, even if it takes a while. It is very easy to make mistakes here!

10 So we would plot r for the following ranges of 4ΞΈ
WB20a Find the area of one loop of the curve with polar equation : r = asin4ΞΈ Think about plotting r = asin4ΞΈ From the patterns you have seen, you might recognise that this will have 4 β€˜loops’ SinΞΈ Ο€/2 1 -1 Ο€ 2Ο€ 3Ο€/2 From the Sine graph, you can see that r will be positive between 0 and Ο€ As the graph repeats, r will also be positive between 2Ο€ and 3Ο€, 4Ο€ and 5Ο€, and 6Ο€ and 7Ο€ So we would plot r for the following ranges of 4ΞΈ 0 ≀ 4ΞΈ ≀ Ο€ 2Ο€ ≀ 4ΞΈ ≀ 3Ο€ 4Ο€ ≀ 4ΞΈ ≀ 5Ο€ 6Ο€ ≀ 4ΞΈ ≀ 7Ο€ 0 ≀ ΞΈ ≀ Ο€/4 Ο€/2 ≀ ΞΈ ≀ 3Ο€/4 Ο€ ≀ ΞΈ ≀ 5Ο€/4 3Ο€/2 ≀ ΞΈ ≀ 7Ο€/4 So the values we need to use for one loop are: 3Ο€/4 Ο€/2 Ο€/4 Sometimes it helps to plot the β€˜limits’ for positive values of r on your diagram! 𝛽= πœ‹ 4 π‘Ÿ=π‘Žπ‘ π‘–π‘›4πœƒ 𝛼=0 Ο€ 5Ο€/4 3Ο€/2 7Ο€/4

11 WB20b Find the area of one loop of the curve with polar equation : r = asin4ΞΈ
π΄π‘Ÿπ‘’π‘Ž= 1 2 𝛼 𝛽 π‘Ÿ 2 π‘‘πœƒ πœ‹ 4 π‘Žπ‘ π‘–π‘›4πœƒ 2 π‘‘πœƒ = πœ‹ 4 π‘Ž 2 𝑠𝑖𝑛 2 4πœƒ π‘‘πœƒ 1 2 π‘Ž πœ‹ 4 𝑠𝑖𝑛 2 4πœƒ π‘‘πœƒ We will need to write sin24ΞΈ so that we can integrate it 1 4 π‘Ž πœ‹ 4 1βˆ’π‘π‘œπ‘ 8πœƒ π‘‘πœƒ Now this has been set up, we can actually Integrate it! 1 4 π‘Ž 2 πœƒβˆ’ 1 8 𝑠𝑖𝑛8πœƒ 0 πœ‹ 4 1 4 π‘Ž 2 πœ‹ 4 βˆ’ 1 8 𝑠𝑖𝑛2πœ‹ = πœ‹π‘Ž 2 16 Important points: You sometimes have to do a lot of rearranging/substitution before you can Integrate Your calculator might not give you exact values, so you need to find them yourself by manipulating the fractions

12 The region we are finding the area of is highlighted in green
WB21a On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves Ο€ 2 And b) were done in WB 17 (2.5,Ο€/3) 𝒓=𝟐+π’„π’π’”πœ½ Ο€ 0, 2Ο€ The region we are finding the area of is highlighted in green οƒ  We can calculate the area of just the top part, and then double it (since the area is symmetrical) 𝒓=πŸ“π’„π’π’”πœ½ (2.5,-Ο€/3) 3Ο€ 2

13 WB20b 𝒓=𝟐+π’„π’π’”πœ½ 𝒓=πŸ“π’„π’π’”πœ½ For the red curve: For the blue curve: π‘Ÿ=2+π‘π‘œπ‘ πœƒ
On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves Ο€ 2 Ο€ 3 𝒓=𝟐+π’„π’π’”πœ½ Ο€ You need to imagine the top part as two separate sections Draw on the β€˜limits’, and a line through the intersection, and you can see that this is two different areas The area under the red curve with limits 0 and Ο€/3 The area under the blue curve with limits Ο€/3 and Ο€/2 We need to work both of these out and add them together! 𝒓=πŸ“π’„π’π’”πœ½ 3Ο€ 2 For the red curve: For the blue curve: π‘Ÿ=2+π‘π‘œπ‘ πœƒ π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛼=0 𝛼= πœ‹ 3 𝛽= πœ‹ 3 𝛽= πœ‹ 2

14 WB21c For the red curve: For the blue curve: π‘Ÿ=2+π‘π‘œπ‘ πœƒ π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛽= πœ‹ 3
On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves For the red curve: For the blue curve: π‘Ÿ=2+π‘π‘œπ‘ πœƒ π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛽= πœ‹ 3 𝛼= πœ‹ 3 𝛽= πœ‹ 2 𝛼=0 1 2 𝛼 𝛽 π‘Ÿ 2 π‘‘πœƒ For the red curve: Sub in the values from above οƒ  Also, remove the β€˜1/2’ since we will be doubling our answer anyway! 0 πœ‹ π‘π‘œπ‘ πœƒ 2 π‘‘πœƒ Square the bracket 0 πœ‹ π‘π‘œπ‘ πœƒ+ π‘π‘œπ‘  2 πœƒ π‘‘πœƒ Replace the cos2ΞΈ term with an equivalent expression (using the equation for cos2ΞΈ above) 0 πœ‹ π‘π‘œπ‘ πœƒ+ 1 2 π‘π‘œπ‘ 2πœƒ π‘‘πœƒ Group like terms, and then we can integrate! 0 πœ‹ π‘π‘œπ‘ πœƒ+ 1 2 π‘π‘œπ‘ 2πœƒ π‘‘πœƒ

15 WB21d For the red curve: For the blue curve: π‘Ÿ=2+π‘π‘œπ‘ πœƒ π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛽= πœ‹ 3
On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves For the red curve: For the blue curve: π‘Ÿ=2+π‘π‘œπ‘ πœƒ π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛽= πœ‹ 3 𝛼= πœ‹ 3 𝛽= πœ‹ 2 𝛼=0 0 πœ‹ π‘π‘œπ‘ πœƒ+ 1 2 π‘π‘œπ‘ 2πœƒ π‘‘πœƒ For the red curve: Integrate each term, using β€˜standard patterns’ where needed… 9 2 πœƒ+4π‘ π‘–π‘›πœƒ+ 1 4 𝑠𝑖𝑛2πœƒ 0 πœ‹ 3 Sub in the limits separately (as subbing in 0 will give 0 overall here, we can just ignore it!) 9 2 πœ‹ 3 +4𝑠𝑖𝑛 πœ‹ 𝑠𝑖𝑛 2πœ‹ 3 Calculate each part (your calculator may give you a decimal answer if you type the whole sum in) 3πœ‹ Write with a common denominator 12πœ‹ Group up 12πœ‹

16 WB21e For the red curve: For the blue curve: π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛼= πœ‹ 3 𝛽= πœ‹ 2
On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves For the red curve: For the blue curve: π‘Ÿ=5π‘π‘œπ‘ πœƒ π΄π‘Ÿπ‘’π‘Ž= 12πœ‹ 𝛼= πœ‹ 3 𝛽= πœ‹ 2 1 2 𝛼 𝛽 π‘Ÿ 2 π‘‘πœƒ For the blue curve: Sub in the values from above οƒ  Also, remove the β€˜1/2’ since we will be doubling our answer anyway! πœ‹ 3 πœ‹ π‘π‘œπ‘ πœƒ 2 π‘‘πœƒ Square the bracket πœ‹ 3 πœ‹ π‘π‘œπ‘  2 πœƒ π‘‘πœƒ Replace the cos2ΞΈ term with an equivalent expression (using the equation for cos 2ΞΈ above) πœ‹ 3 πœ‹ π‘π‘œπ‘ 2πœƒ π‘‘πœƒ We can move the β€˜1/2’ and the 25 outside to make the integration a little easier πœ‹ 3 πœ‹ 2 π‘π‘œπ‘ 2πœƒ+1 π‘‘πœƒ

17 WB21f For the red curve: For the blue curve: π‘Ÿ=5π‘π‘œπ‘ πœƒ 𝛼= πœ‹ 3 𝛽= πœ‹ 2
On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves For the red curve: For the blue curve: π‘Ÿ=5π‘π‘œπ‘ πœƒ π΄π‘Ÿπ‘’π‘Ž= 12πœ‹ 𝛼= πœ‹ 3 𝛽= πœ‹ 2 πœ‹ 3 πœ‹ 2 π‘π‘œπ‘ 2πœƒ+1 π‘‘πœƒ For the blue curve: Integrate each term, using β€˜standard patterns’ if needed… 𝑠𝑖𝑛2πœƒ+πœƒ πœ‹ 3 πœ‹ 2 Sub in the limits (we do need to include both this time as neither will cancel a whole section out!) π‘ π‘–π‘›πœ‹+ πœ‹ 2 βˆ’ 1 2 𝑠𝑖𝑛 2πœ‹ 3 + πœ‹ 3 Calculate each part as an exact value πœ‹ 2 βˆ’ πœ‹ 3 Write with common denominators πœ‹ 12 βˆ’ πœ‹ 12 Group up and multiply by 25/2 50πœ‹βˆ’

18 Add these two areas together to get the total area!
WB21g On the same diagram, sketch the curves with equations: r = 2 + cosΞΈ r = 5cosΞΈ Find the polar coordinates of the intersection of these curves Find the exact value of the finite region bounded by the 2 curves For the red curve: For the blue curve: π΄π‘Ÿπ‘’π‘Ž= 12πœ‹ π΄π‘Ÿπ‘’π‘Ž= 50πœ‹βˆ’ Add these two areas together to get the total area! 12πœ‹ πœ‹βˆ’ Write with a common denominator 36πœ‹ πœ‹βˆ’ Add the numerators 86πœ‹βˆ’ Divide all by 2 43πœ‹βˆ’ These questions are often worth a lot of marks! Your calculate might not give you exact values for long sums, so you will need to be able to deal with the surds and fractions yourself!

19 One thing to improve is –
KUS objectives BAT Find Areas bounded by parts of Polar curves BAT Find points of intersection of Polar curves self-assess One thing learned is – One thing to improve is –

20 Practice Ex 7D

21 END


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