Download presentation
Presentation is loading. Please wait.
1
Concavity and the Second Derivative Test
Section 3.4
2
Definition of Concavity
The graph of a differentiable function π¦=π(π₯) is 1) Concave upward on an open interval πΌ if πβ² is increasing on πΌ. 2) Concave downward on an open interval πΌ if πβ² is decreasing on πΌ. Concave upward πβ² is increasing Concave downward πβ² is decreasing ***NOTE: The graph of π lies above its tangent line. ***NOTE: The graph of π lies below its tangent line.
3
LETβS EXAMINE THESE GRAPHS AND STUDY THEIR RELATIONSHIPS
Concave Downward Concave Upward π π = π π π π βπ π πβ²β² π β² π = π π β1 πβ² π β²β² (π)>π πβ²β² π <π π β² is decreasing π β² is increasing
4
Theorem 3.7- Test for Concavity
Let π be a function whose second derivative exist on an open interval πΌ. 1) If πβ²β²(π₯)>0 for all π₯ in πΌ, then the graph of π is concave upward on πΌ. 2) If πβ²β²(π₯)<0 for all π₯ in πΌ, then the graph of π is concave downward on πΌ.
5
Example: 1) Determine open intervals on which the graph of π π₯ =5β π₯ 1 3 is concave upward or downward. Concave Upward Concave Downward
7
Definition of Point of Inflection
Let π be a function that is continuous on an open interval and let π be a point in the interval. If the graph of π has a tangent line at this point π, π π , then this point is a point of inflection of the graph of π if the concavity of changes from upward to downward (or downward to upward) at the point. Concave Upward Concave Upward Concave Downward Concave Downward Concave Upward Concave Downward The concavity of π changes at a point of inflection. Note that the graph crosses its tangent line at the point of inflection.
8
Theorem 3.8- Points of Inflection
If π,π π is a point of inflection of the graph of π, then either π β²β² π =0 or πβ²β² does not exist at π₯=π. True or False: If π β²β² π =0, then π,π π is a point of inflection. Justify why or why not.
11
Example: 2) Determine the points of inflection and discuss the concavity of the graph π π₯ =β π₯ 4 +2 π₯ 3 π π =β π π +π π π Concave Upward Concave Downward Point of Inflections Concave Downward
12
Example: 2) Given the graph of π β² , (a) determine intervals when π is increasing or decreasing, (b) identify π₯-values where π has a relative maximum or minimum, and (c) identify intervals where π is concave upward or concave downward. Increasing Decreasing Rel. Max Rel. Min Concave Concave Downward Upward π πβ² AP type question- (d) Identify intervals where π is increasing and concave up.
13
Theorem 3.9- Second Derivative Test
Let π be a function such that π β² π =π and the second derivative of π exist on an open interval containing π. 1) If πβ²β²(π)>π, then π has a relative minimum at π, π π . 2) If πβ²β²(π)<π, then π has a relative maximum at π, π π . If π β²β² π =π, then the test fails. That is, π may have a relative maximum, a relative minimum, or neither. In such cases, you can use the First Derivative Test.
14
Theorem 3.9- Second Derivative Test
Let π be a function such that π β² π =π and the second derivative of π exist on an open interval containing π. π β²β² π <π π β²β² (π)>π Concave Upward π π Concave Downward If π β² π =π and π β²β² (π)>π, π(π) is a relative minimum. If π β² π =π and π β²β² (π)<π, π(π) is a relative maximum. If π β²β² π =0, the test fails. That is, π may have a relative maximum, a relative minimum, or neither. In such cases, you can use the First Derivative Test.
17
Example: 3) Use the second derivative test to find relative extrema for π π₯ =β π₯ 5 +5 π₯ 3 .
Relative Maximum Neither Relative Minimum
18
Example: Given π π₯ = π₯ +2. Use the equation of the tangent line at π₯= 1 to approximate π Is this an overestimate or an underestimate? Explain your reasoning.
19
Work on 4.3 Practice
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.