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Ch. 3 & 7 – The Mole II. Concentration (p. 412-415)

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Presentation on theme: "Ch. 3 & 7 – The Mole II. Concentration (p. 412-415)"— Presentation transcript:

1 Ch. 3 & 7 – The Mole II. Concentration (p )

2 II. Concentration Measures the relative amounts of the two substances making up a solution. solute: the substance being dissolved solvent: the liquid doing the dissolving solution: the combination of the two

3 substance being dissolved
A. Molarity 1. Concentration of a solution. substance being dissolved total combined volume

4 A. Molarity 2M HCl 1. What does this mean?

5 2. Molarity Calculations
6.02  1023 (particles/mol) molar mass (g/mol) MASS IN GRAMS MOLES NUMBER OF PARTICLES LITERS SOLUTION Molarity (mol/L)

6 2. Molarity Calculations
How many grams of NaCl are required to make 0.500L of 0.25M NaCl? 0.500 L 0.25 mol 1 L 58.44 g 1 mol = 7.3 g NaCl

7 2. Molarity Calculations
Find the molarity of a 250 mL solution containing 10.0 g of NaF. 10.0 g 1 mol 41.99 g = mol NaF 0.238 mol 0.25 L M = = 0.95M NaF

8 substance being dissolved
A. Molality 1. Concentration of a solution. substance being dissolved Mass of solvent

9 A. Molality 2m HCl 1. What does this mean?

10 2. Molality Calculations
6.02  1023 (particles/mol) molar mass (g/mol) MASS IN GRAMS MOLES NUMBER OF PARTICLES kg SOLVENT Molality (mol/kg)

11 2. Molality Calculations
How many grams of NaCl are required to make 0.50m NaCl with 1.50kg of H2O? 1.50kg 0.50 mol 1.00 kg 58.44 g 1 mol = 44 g NaCl

12 2. Molality Calculations
Find the molality of solution containing 10.0 g of NaF and kg H2O. 10.0 g 1 mol 41.99 g = mol NaF 0.238 mol kg m = = 4.76 m NaF


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