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The Circle x2+y2+2gx+2fy+c = 0 (x-a)2 + (y-b)2 = r2 x2 + y2 = r2

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Presentation on theme: "The Circle x2+y2+2gx+2fy+c = 0 (x-a)2 + (y-b)2 = r2 x2 + y2 = r2"— Presentation transcript:

1 The Circle x2+y2+2gx+2fy+c = 0 (x-a)2 + (y-b)2 = r2 x2 + y2 = r2
Graph Sketching b2 - 4ac < 0 2 pts of intersection Move the circle from the origin a units to the right b units upwards Used for intersection problems between circles and lines Factorisation b2 - 4ac < 0 No intersection x2+y2+2gx+2fy+c = 0 Centre (a,b) Centre (-g,-f) b2 - 4ac = 0 1 pt of intersection TANGENT to circle The Circle (x-a)2 + (y-b)2 = r2 Straight line Theory Pythagoras Theorem rotated through 360o x2 + y2 = r2 Perpendicular Equation m1xm2 = -1 Two circles touch externally if the distance C1C2=(r1 + r2) Distance Formula Two circles touch internally if the distance C1C2=(r1 - r2) Centre (0,0)


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