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Simultaneous Equations –

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1 Simultaneous Equations –
goteachmaths.co.uk Simultaneous Equations – Elimination

2 Simultaneous Equations
05 December 2018 Simultaneous Equations

3

4 How can we check we’re correct?
How do we find x? How do we find y? 9y - 12 = 15 6x + 35 = 95 (-35) (- 35) (+12) (+12) 6x = 60 9y = 27 (÷6) (÷6) (÷9) (÷9) x = 10 y = 3 How can we check we’re correct?

5 Simultaneous Equations
05 December 2018 = £3.50 = £2.50 How much is a packet of quavers?

6 We can find the difference
between two sums.

7 = £3.50 - = £2.50 £1 £1 = £1 How much is a Dairy Milk?

8 = £7 - = £5 £2 £2 50p 50p = £2 Cost of 1 Pringles? Cost of 1 apple?

9 - = £8 = £6 X X X X Y Y 8 4x + 2y = 8 4x + 1y = 6 0 + 1y = 2 y = 2
Put y back in. 4x + 2 = 6 4x = 4 x = 1

10 = £11 = £7 3x + 4y = 11 3x + 2y = 7 Put y back in. 0 + 2y = 4
3x + (2x2) = 7 y = 2 3x + 4 = 7 3x = 3 x = 1

11 Simultaneous Equations
Elimination Method 5x + 3y = 65 6x + 4y = 36 6x + 2y = 20 5x + 2y = 60 6x + 2y = 30 4x + 2y = 16 0x + y = 5 2y = 6 2x + 0y = 4 y = 3 y = 5 2x = 4 x = 2 Put y back in. Put y back in. Put x back in. 5x + (2x5) = 60 6x + (2x3) = 30 (4x2) + 2y = 16 6x + 6 = 30 5x + 10 = 60 8 + 2y = 16 6x = 24 5x = 50 2y = 8 x = 4 x = 10 y = 4

12 We can’t simply subtract. We need to change one equation first
6x + 6y = 30 We can’t simply subtract. 3x + 2y = 13 We need to change one equation first 3x + 2y = 13 (x2) (x2) 6x + 6y = 30 6x + 4y = 26 6x + 4y = 26

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14 Copy the question and process into your book!
3x + 4y = 17 3x + 4y = 39 3x + 4y = 18 1) 7) 13) 3x - 3y = 3 3x + 3y = 32 6x + 3y = 21 4x + 5y = 46 5x + 8y = 44 4x + 5y = 40 14) 2) 8) 4x - 2y = 4 5x + 6y = 38 8x + 2y = 48 3x + 2y = 23 7x + 11y = 80 3x + 2y = 17 15) 3) 9) 6x - 1y = 26 7x + 9y = 68 9x + 1y = 16 2x - 2y = 0 5x + 2y = 16 2x + 2y = 10 16) 4) 10) 8x - 4y = 8 2x + 2y = 10 10x + 3y = 43 4x - 2y = 30 9x + 3y = 51 4x + 2y = 12 17) 5) 11) 5x - 6y = 13 6x + 3y = 36 6x + 4y = 20 8x - 2y = 16 11x + 6y = 57 2x + 3y = 38 18) 6) 12) 7x - 7y = -7 9x + 6y = 51 5x + 9y = 107

15 Copy the question and process into your book!
x = 3 3x + 4y = 39 x = 5 3x + 4y = 18 x = 2 3x + 4y = 17 1) 7) 13) y = 2 3x + 3y = 32 y = 6 3x - 3y = 3 6x + 3y = 21 y = 3 4x + 5y = 46 x = 4 5x + 8y = 44 x = 4 4x + 5y = 40 x = 5 14) 2) 8) 4x - 2y = 4 y = 6 5x + 6y = 38 y = 3 8x + 2y = 48 y = 4 x = 5 7x + 11y = 80 x = 2 3x + 2y = 17 x = 1 3x + 2y = 23 15) 3) 9) 7x + 9y = 68 y = 6 9x + 1y = 16 y = 7 6x - 1y = 26 y = 4 2x - 2y = 0 x = 2 5x + 2y = 16 x = 2 2x + 2y = 10 x = 4 16) 4) 10) 8x - 4y = 8 y = 2 2x + 2y = 10 y = 3 10x + 3y = 43 y = 1 4x - 2y = 30 x = 11 9x + 3y = 51 x = 5 4x + 2y = 12 x = 2 17) 5) 11) 5x - 6y = 13 y = 7 6x + 3y = 36 y = 2 6x + 4y = 20 y = 2 8x - 2y = 16 x = 3 11x + 6y = 57 x = 3 2x + 3y = 38 x = 7 18) 6) 12) 7x - 7y = -7 y = 4 9x + 6y = 51 y = 4 5x + 9y = 107 y = 8

16 Extension @ TESCO, Jimmy bought 14 cakes and
12 hotdogs for the party and paid £27.60. @ TESCO, Sally paid £10.80 for 3 hotdogs and 8 cakes for the party. Use this information to make a pair of equations. How much is 1 hotdog at TESCO? Hotdog = 90p Cake = £1.20

17 5x + 4y = 33 x = 5 5x + 2y = 29 y = 2 3x + 5y = 27 x = 4 6x + 2y = 30 y = 3 2x + 2y = 12 x = 1 8x - 3y = -7 y = 5

18 I can solve simultaneous questions with positive coefficients.
Comment in your book. I need more practice. I can solve simultaneous questions with positive coefficients. I can solve simultaneous questions with negative coefficients.


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