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Electrostatics
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Chapter 2 Electrostatics
2.0 New Notations 2.1 The Electrostatic Field 2.2 Divergence and Curl of Electrostatic Field 2.3 Electric Potential 2.4 Work and Energy in Electrostatics 2.5 Conductors Abeer Alshammari
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Fundamental Quantities
2.0 New Notations and some units R We will use the SI system – SI International System of Units Fundamental Quantities Length meter [m] Mass kilogram [kg] Time second [s] Other Units Current ampere [A] Derived Quantities Force newton N = 1 kg m / s2 Energy joule J = 1 N m Charge coulomb 1 C = 1 A s Electric Potential volt V = 1 J / C Resistance ohm = 1 V / A Abeer Alshammari
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2.1 The Electrostatic Field
2.1.1 Introduction 2.1.2 Coulomb’s Law 2.1.3 The Electric Field 2.1.4 Continuous Charge Distribution Abeer Alshammari
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Opposite charges attract.
Electrostatics is the study of electric charge at rest. (Or more or less at rest, in contrast with current electricity.) Electric charge is a fundamental property of matter. Two types of electric charges Positive charge - every proton has a single positive charge. Negative charge - every electron has a single negative charge. Like charges repel. Opposite charges attract. Abeer Alshammari
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Electric charge is conserved -
Electric charge moves from one place to another - no case of the net creation or destruction of electric charge has ever been observed. In solids, only electrons can move. In liquids, gasses, and plasmas, both positive and negative ions are free to move. Electric charge is quantized The smallest negative charge is the charge on the electron. In normal atoms, electrons orbit the nucleus. Protons carry the smallest positive charge. Protons and uncharged neutrons generally reside in an atom’s nucleus. Protons are held in the nucleus by the strong force. Abeer Alshammari
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Introduction The fundamental problem for electromagnetic to solve is to calculate the interaction of charges in a given configuration. That is, what force do they exert on another charge Q ? The simplest case is that the source charges are stationary. Principle of Superposition: The interaction between any two charges is completely unaffected by the presence of other charges. is the force on Q due to Abeer Alshammari
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the permittivity of free space
Coulomb’s Law The force on a charge Q due to a single point charge q is given by Coulomb`s law the permittivity of free space Abeer Alshammari
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2.1.3 The Electric Field the electric field of the source charge
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2.1.4 Continuous Charge Distributions
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2.1.4 (2) Example: the test point is at the source point is at
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2.1.4 (3) Example 2.1 Find the electric field a distance z above the midpoint of a straight of length 2L, which carries a uniform line charge Solution: (1) z>>L (2) Abeer Alshammari
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2.2.3 Application of Gauss’s Law 2.2.4 The Curl of E
2.2 Divergence and Curl of Electrostatic Fields 2.2.1 Field Lines and Gauss’s Law 2.2.2 The Divergence of E 2.2.3 Application of Gauss’s Law 2.2.4 The Curl of E Abeer Alshammari
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2.2.1 Fields lines and Gauss’s law
A single point charge q, situated at the origin Because the field falls off like ,the vectors get shorter as I go father away from the origin,and they always point radially outward. This vectors can be connect up the arrows to form the field lines. The magnitude of the field is indicated by the density of the lines. strength length of arrow strength density of field line Abeer Alshammari
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2.2.1 (2) 1.Field lines emanate from a point charge symmetrically in all directions. 2.Field lines originate on positive charges and terminate on negative ones. 3.They cannot simply stop in midair, though they may extend out to infinity. 4.Field lines can never cross. Abeer Alshammari
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2.2.1 (3) Since in this model the fields strength is proportional to the number of lines per unit area, the flux of ( ) is proportional to the the number of field lines passing through any surface . The flux of E through a sphere of radius r is: The flux through any surface enclosing the charge is According to the principle of superposition, the total field is the sum of all the individual fields: , A charge outside the surface would contribute nothing to the total flux,since its field lines go in one side and out other. Abeer Alshammari
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2.2.1 (4) Gauss’s Law in integral form
Turn integral form into a differential one , by applying the divergence theorem Gauss’s law in differential form Abeer Alshammari
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2.2.2 The Divergence of E Calculate the divergence of E directly From
, The r-dependence is contained in From Thus Abeer Alshammari
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2.2.3 Application of Gauss’s Law
Example Find the field outside a uniformly charged sphere of radius Sol: (a) E point radially outward ,as does (b)E is constant over the Gaussian surface Thus Abeer Alshammari
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2.2.3 (2) 1. Spherical symmetry. Make your Gaussian surface a
concentric sphere (Fig 2.18) 2. Cylindrical symmetry. Make your Gaussian surface a coaxial cylinder (Fig 2.19) 3. Plane symmetry Use a Gaussian surface a coaxial the surface (Fig 2.20) Abeer Alshammari
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2.2.3 (3) Example 2.3 Find the electric field inside the cylinder which contains charge density as Solution: The enclosed charge is (by symmetry) thus Abeer Alshammari
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2.2.3 (4) Example 2.4 An infinite plane carries a uniform surface charge. Find its electric field. Solution: Draw a ”Gaussian pillbox Apply Gauss’s law to this surface By symmetry, E points away from the plane thus, the top and bottom surfaces yields (the sides contribute nothing) Abeer Alshammari
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2.2.3 (5) Example 2.5 Two infinite parallel planes carry equal but opposite uniform charge densities Find the field in each of the three regions. Solution: The field is (σ/ε0 ), and points to the right, between the plane elsewhere it is zero. Abeer Alshammari
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2.2.4 The Curl of E A point charge at the origin. If we calculate
the line integral of this field from some point to some other point b : In spherical coordinate This integral is independent of path. It depends on the two end points ( if ra = rb ) Apply by Stokes’ theorem, Abeer Alshammari
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2.2.4 The principle of superposition so
must hold for any static charge distribution whatever. Abeer Alshammari
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2.3 Electric potential 2.3.1 Introduction to Potential
2.3.2 Comments on Potential 2.3.3 Poisson’s Equation and Laplace’s Equation 2.3.4 The Potential of a Localized Charge Distribution 2.3.5 Electrostatic Boundary Conditions Abeer Alshammari
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2.3.1 introduction to potential
Any vector whose curl is zero is equal to the gradient of some scalar. We define a function: Where is some standard reference point ; V depends only on the point P. V is called the electric potential. The fundamental theorem for gradients so Abeer Alshammari
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2.3.2 Comments on potential (1)The name
Potential is not potential energy V : Joule/coulomb U : Joule Abeer Alshammari
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2.3.2 (2) (2)Advantage of the potential formulation
V is a scalar function, but E is a vector quantity If you know V, you can easily get E: are not independent functions 1 2 3 so 1 2 3 Abeer Alshammari
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2.3.2 (3) (3)The reference point
Changing the reference point amounts to adds a constant to the potential (Where K is a constant) Adding a constant to V will not affect the potential difference between two point: Since the derivative of a constant is zero: For the different V, the field E remains the same. Ordinarily we set Abeer Alshammari
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2.3.2 (4) (4)Potential obeys the superposition principle
, Dividing through by Q Integrating from the common reference point to p , (5)Unit of potential Volt=Joule/Coulomb Joule/Coulomb Abeer Alshammari
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2.3.2 (5) Example Find the potential inside and outside a spherical shell of radius R, which carries a uniform surface charge (the total charge is q). solution: for r>R: _ for r<R: Abeer Alshammari
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2.3.3 Poisson’s Eq. & Laplace’s Eq.
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2.3.4 The Potential of a Localized Charge Distribution
Potential for a point charge Potential for a collection of charge Ri Abeer Alshammari
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Potential of a continuous distribution
2.3.4 (2) Potential of a continuous distribution for volume charge for a line charge for a surface charge [ ] Corresponding electric field Abeer Alshammari
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2.3.4 (3) Example 2.7 Find the potential of a uniformly charged spherical shell of radius R. Solution: r Abeer Alshammari
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2.3.4 (4) Abeer Alshammari
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2.3.5 Electrostatic Boundary Condition
Electrostatic problem Superposition Coulomb law The above equations are differential or integral. For a unique solution, we need boundary conditions. (e.q. , V()=0 ) (boundary value problem. Dynamics: initial value problem.) Abeer Alshammari
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2.3.5 (2) : = E‖ above= E‖ below B.C. at surface with charge ∥: +∥
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2.3.5 (3) Potential B.C. Abeer Alshammari
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2.4 Work and Energy in Electrostatics
2.4.1 The Work Done in Moving a Charge 2.4.2 The Energy of a Point Charge Distribution 2.4.3 The Energy of a Continuous Charge Distribution 2.4.4 Comments on Electrostatic Energy Abeer Alshammari
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2.4.1 The Work Done in Moving a charge
A test charge Q feels a force Q (from the stationary source charges). To move this test charge, we have to apply a force conservative The total work we do is So, bring a charge from to P, the work we do is Abeer Alshammari
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2.4.2 The Energy of a Point Charge Distribution
It takes no work to bring in first charges for q1 Work needed to bring in q2 is : Work needed to bring in q3 is : Work needed to bring in q4 is : Abeer Alshammari
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2.4.2 Total work W=W1+ W2+ W3 +W4 Dose not include the first charge
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2.4.3 The Energy of a Continuous Charge Distribution
Volume charge density F.T.for Abeer Alshammari
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2.4.3 Example 2.8 Find the energy of a uniformly charged spherical
shell of total charge q and radius R Sol.1: Sol.2: Abeer Alshammari
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2.4.4 Comments on Electrostatic Energy
A perplexing inconsistent or Only for point charge and are attractive Abeer Alshammari
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2.4.4 (2) is more complete the energy of a point charge itself,
does not include , , is the full potential There is no distinction for a continuous distribution, because Abeer Alshammari
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2.4.4 (3) (2)Where is the energy stored? In charge or in field ?
Both are fine in ES. But,it is useful to regard the energy as being stored in the field at a density Energy per unit volume (3)The superposition principle,not for ES energy Abeer Alshammari
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2.5 Conductors 2.5.1 Basic Properties of Conductors
2.5.2 Induced Charges 2.5.3 The Surface Charge on a Conductor; the Force on a Surface Charge 2.5.4 Capacitors Abeer Alshammari
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2.5.1 Basic Properties of Conductors
are free to move in a conductor inside a conductor (1) otherwise, the free charges that produce will move to make inside a conductor (2) ρ = 0 inside a conductor (3) Any net charge resides on the surface (4) V is constant, throughout a conductor. Abeer Alshammari
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2.5.1 (2) (5) is perpendicular to the surface, just outside a conductor. Otherwise, will move the free charge to make in terms of energy, free charges staying on the surface have a minimum energy. uniform uniform Abeer Alshammari
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2.5.1 (3) Example : A point charge q at the center of a spherical conducting shell. How much induced charge will accumulate there? Solution : q induced charge conservation Abeer Alshammari
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2.5.2 Induced Charge Example 2.9 Within the cavity is a charge +q.
What is the field outside the sphere? -q distributes to shield q and to make i.e., from charge conservation and symmetry. +q uniformly distributes at the surface a,b are arbitrary chosen a Faraday cage can shield out stray Abeer Alshammari
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2.5.3 The Surface Charge on a Conductor
if we know V, we can get s. Abeer Alshammari
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2.5.3 Force per unit area on a surface charge, why the average?
In case of a conductor electrostatic pressure Abeer Alshammari
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2.5.4 Capacitors (V is constant.) Consider 2 conductors (Fig 2.53)
The potential difference (V is constant.) Define the ratio between Q and V to be capacitance a geometrical quantity in mks 1 farad(F)= 1 Coulomb / volt inconveniently large ; Abeer Alshammari
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2.5.4 (2) Example 2.10 Find the capacitance of a “parallel-plate capacitor”? +Q -Q Solution: Abeer Alshammari
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2.5.4 (3) Example 2.11 Find capacitance of two concentric spherical shells with radii a and b . +Q -Q Solution: Abeer Alshammari
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2.5.4 (4) The work to charge up a capacitor Abeer Alshammari
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