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HW3
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58. What is the density of each of these gases at STP?
Ne NO2
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58. What is the density of each of these gases at STP?
C3H8 molar mass = 44 g Ne molar mass = 20.2 NO2 molar mass = 46 g Molar volume is 22.4 L
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58. What is the density of each of these gases at STP?
C3H8 44g / 22.4L= 1.96 g/L Ne 20.2g / 22.4L= .90 g/L NO2 46g / 22.4L= 2.05 g/L
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60. Calculate the percent composition of each compound
H2S (NH4)2C2O4 Mg(OH)2 Na3PO4
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60. Calculate the percent composition of each compound
H2S Molar mass is 34g Percent composition of an element is mass of that element divided by the molar mass of the compound X 100 % H is 2/34 X 100 = 6% % S is 32/34 X 100 = 94%
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60. Calculate the percent composition of each compound
B. (NH4)2C2O4 Molar mass = 124g %N is 28/124 X 100 = 22.6% %H is 8/124 X 100 = 6.5% % C is 24/124 X 100 = 19.3% % O is 64/124 X 100 = 51.6%
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60. Calculate the percent composition of each compound
C. Mg(OH)2 Molar mass = 58.3g %Mg is 24/58 X 100 = 41% %O is 32/58 X 100 = 55% %H is 2/58 X 100 =4%
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60. Calculate the percent composition of each compound
D. Na3PO4 Molar mass = 164 % Na is 69/164 X 100 = 42% % P is 31/164 X 100 = 19% % O is 64/164 X 100 = 39%
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62. Which of the following compounds has the highest iron content?
FeCL2 Fe(C2H3O2)3 Fe(OH)2 FeO
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62. Which of the following compounds has the highest iron content?
FeCL2 Fe(C2H3O2)3 Fe(OH)2 FeO What are the molar masses? What are the percent compositions of Fe in each?
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62. Which of the following compounds has the highest iron content?
FeCL2 Molar mass = 127g %Fe + 56/127 X 100 = 44%
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62. Which of the following compounds has the highest iron content?
B. Fe(C2H3O2)3 Molar mass = 233g %Fe is 56/233 X 100 = 24%
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62. Which of the following compounds has the highest iron content?
C. Fe(OH)2 Molar mass = 90g %Fe is 56/90 X 100 = 62%
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62. Which of the following compounds has the highest iron content?
D. FeO Molar mass = 72g %Fe is 56/72 X 100 = 78%
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64. Classify each formula as an empirical or a molecular formula
S2Cl2 C6H10O4 Na2SO3 C5H10O5 C17H19NO3 (NH4)2CO3
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64. Classify each formula as an empirical or a molecular formula
S2Cl2 M C6H10O4 M Na2SO3 E C5H10O5 M C17H19NO3 E (NH4)2CO3 E
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66. Determine the molecular formula for each compound
94.1% O ; 5.9% H; molar mass = 34g 40.0% C ; 6.6% H; 53.4% O; molar mass = 120g
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66. Determine the molecular formula for each compound
94.1% O ; 5.9% H; molar mass = 34g .94 X 34g = 32 g O .059 X 34g = 2 g H There are two moles of both H and O, so the molecular formula must be H2O2
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66. Determine the molecular formula for each compound
40.0% C ; 6.6% H; 53.4% O; molar mass = 120g .4 X 120 = 48 g C .066 X 120 = 7.92 g H .534 X 120 = 64 g O There are 4 moles of C, 8 moles of H, and 4 moles of O, so the formula must be C4H8O4
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