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4.3 Parallel and perpendicular lines
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What we will learn Identify and write equations of parallel lines
Identify and write equations of perpendicular lines
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Needed vocab Parallel lines: two lines in the same plane that never intersect Perpendicular lines: two lines in the same plane that intersect to form right angles
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Ex. 1 identifying parallel lines
Parallel lines have the same slope Find slope of each line Use slope formula π= π¦ 2 β π¦ 1 π₯ 2 β π₯ 1 π π = 2β3 1β(β4) = 2β3 1+4 = β1 5 π π = β1β0 1β β3 = β1β0 1+3 = β1 4 π π = β5β(β4) 2β(β3) = β = β1 5 So, line a is parallel to line c πβ₯π is symbolic way to say
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Your practice Line a goes through (-5,3) and (-6,-1). Line b goes through (3,-2) and (2,-7). Are a and b parallel? π π = β1β3 β6β(β5) = β1β3 β6+5 = β4 β1 =4 π π = β7β(β2) 2β3 = β7+2 2β3 = β5 β1 =5 no
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Ex. 2 write equation of parallel lines
Write equation of a line through (5,-4) and parallel to π¦=2π₯+3. New slope: m = 2 Finding b: π¦=ππ₯+π β4=2 5 +π β4=10+π β10 β10 β14=π Write parallel equation: π¦=2π₯β14 Steps 1. put given equation into π¦=ππ₯+π form 2. find slope of new line from old m = slope Will be the same as the old slope 3. find b Plug in m, x, and y into π¦=ππ₯+π and solve for b x and y come from given point in problem 4. write π¦=ππ₯+π by plugging in new m and b
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Ex. 2 Continued Write equation through (-4,2) and parallel to βπ₯+4π¦=4.
Get into y = mx + b form: βπ₯+4π¦=4 +π₯ π₯ 4π¦=π₯+4 4π¦ 4 = π₯ π¦= 1 4 π₯+1 New slope: m = 1 4 Finding b: 2= 1 4 β4 +π 2=β1+π +1 +1 3=π Parallel equation: π¦= 1 4 π₯+3
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Your practice Write an equation of a line through (18,2) and parallel to 3y β x = -12. 3π¦βπ₯=β12 +π₯ π₯ 3π¦=π₯β12 3π¦ 3 = π₯ 3 β 12 3 π¦= 1 3 π₯β4 New slope: m = 1 3 Finding b: 2= π 2=6+π β6β6 β4=π Parallel equation: π¦= 1 3 π₯β4
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Ex. 3 Perpendicular lines
Slopes of perpendicular lines are negative reciprocals of each other For example: m = 2 and m = β 1 2 ; m = and m = β2 3 Find slopes π π = 3β1 0β(β2) = 3β1 0+2 = 2 2 =1 π π = 4β1 6β4 = 3 2 π π = 1β3 4β1 = β2 3 So b is perpendicular to c πβ₯π is symbolic way to write Line a (-2,1) and (0,3) Line b (4,1) and (6,4) Line c (1,3) and (4,1) Which are perpendicular?
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Ex. 4 Writing equations of perpendicular lines
Write equation through (-3,1) and perpendicular to π¦= 1 2 π₯+3. New Slope: π=β2 Finding b: 1=β2 β3 +π 1=6+π β6 β6 β5=π New Perpendicular equation: π¦=β2π₯β5 Steps 1. put given equation into π¦=ππ₯+π form 2. find slope of new line from old m = slope Will be negative reciprocal of the old slope 3. find b Plug in m, x, and y into π¦=ππ₯+π and solve for b x and y come from given point in problem 4. write π¦=ππ₯+π by plugging in new m and b
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Your practice Write equation through (8,1) perpendicular to 2π¦+4π₯=12.
β4π₯ β4π₯ 2π¦=β4π₯+12 2π¦ 2 = β4π₯ π¦=β2π₯+6 New slope: π= 1 2 Finding b: 1= π 1=4+π β4β4 β3=π New Equation: π¦= 1 2 π₯β3
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Ex. 5 Story Problems Slope of shoreline first:
The position of a helicopter search and rescue crew is shown in the graph. The shortest flight path to the shoreline is one that is perpendicular to the shoreline. Write an equation that represents this path. Slope of shoreline first: m = β2 3 Slope of perpendicular line: m = 3 2 Use point - slope with point of helicopter π¦β4= 3 2 π₯β14 π¦β4= 3 2 π₯β21 π¦= 3 2 π₯β17
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