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Lecture 28 OUTLINE The BJT (cont’d) Small-signal model
Cutoff frequency Transient (switching) response Reading: Pierret 12; Hu
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Small-Signal Model Common-emitter configuration, forward-active mode:
R. F. Pierret, Semiconductor Device Fundamentals, Fig.12.1(a) “hybrid pi” BJT small signal model: Transconductance: EE130/230A Fall 2013 Lecture 28, Slide 2
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Small-Signal Model (cont.)
where QF is the magnitude of minority-carrier charge stored in the base and emitter regions forward transit time EE130/230A Fall 2013 Lecture 28, Slide 3
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Example A BJT is biased at IC = 1 mA and VCE = 3V. bdc = 90, tF = 5ps, T = 300K. Find (a) gm , (b) rp , (c) Cp . Solution: (a) (b) rp = bdc / gm = 90/0.039 = 2.3 kW (c) EE130/230A Fall 2013 Lecture 28, Slide 4
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Cutoff Frequency, fT The cutoff frequency is defined to be the frequency (f = w/2p) at which the short-circuit a.c. current gain equals 1: EE130/230A Fall 2013 Lecture 28, Slide 5
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fT is commonly used as a metric for the speed of a BJT.
For the full BJT equivalent circuit: fT is commonly used as a metric for the speed of a BJT. Si/SiGe HBT by IBM To maximize fT: increase IC minimize CJ,BE, CJ,BC minimize re, rc minimize tF EE130/230A Fall 2013 Lecture 28, Slide 6
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Base Widening at High IC: Kirk Effect
For a NPN BJT: At very high current densities (>0.5mA/mm2), the density of mobile charge passing through the collector depletion region exceeds the ionized dopant charge density: increasing IC The base width (W) is effectively increased (referred to as “base push out”) tF increases and hence fT decreases. This effect can be avoided by increasing NC increased CJ,BC , decreased VCE0 EE130/230A Fall 2013 Lecture 28, Slide 7 C. C. Hu, Modern Semiconductor Devices for Integrated Circuits, Figure 8-18
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Summary: BJT Small Signal Model
Hybrid pi model for the common-emitter configuration, forward-active mode: EE130/230A Fall 2013 Lecture 28, Slide 8
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BJT Switching - Qualitative
R. F. Pierret, Semiconductor Device Fundamentals, Figs EE130/230A Fall 2013 Lecture 28, Slide 9
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Turn-on Transient Response
The general solution is: Initial condition: QB(0)=0 since transistor is in cutoff where IBB=VS/RS EE130/230A Fall 2013 Lecture 28, Slide 10 R. F. Pierret, Semiconductor Device Fundamentals, Fig. 12.5
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Turn-off Transient Response
The general solution is: Initial condition: QB(0)=IBBtB EE130/230A Fall 2013 Lecture 28, Slide 11 R. F. Pierret, Semiconductor Device Fundamentals, Fig. 12.5
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Reducing tB for Faster Turn-Off
The speed at which a BJT is turned off is dependent on the amount of excess minority-carrier charge stored in the base, QB, and also the recombination lifetime, tB. By reducing tB, the carrier removal rate is increased Example: Add recombination centers (Au atoms) in the base EE130/230A Fall 2013 Lecture 28, Slide 12
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Schottky-Clamped BJT When the BJT enters the saturation mode, the Schottky diode begins to conduct and “clamps” the C-B junction voltage at a relatively low positive value. reduced stored charge in quasi-neutral base EE130/230A Fall 2013 Lecture 28, Slide 13 R. F. Pierret, Semiconductor Device Fundamentals, Fig. 12.7
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