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2-4 Solving Multi-Step Equations

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1 2-4 Solving Multi-Step Equations

2 Solve the following equations
1) 4 + x = 13 2) w – 5 = 11 3) 3 + n = 0 4) -3 = 7 + a 5) 10x = 100 6) 256 = 16c 1) x = 9 2) w = 16 3) n = -3 4) a = -10 5) x = 10 6) c = 16

3 Solve: 5t = 4t + 3 5t = 4t + 3 Since 4t is positive, subtract 4t from both sides in order to get all the t’s on one side. Check your answer by plugging 3 back into the original equation. 5(3) = 4(3) + 3 15 = 15 = 15 TRUE

4 Solve: 5q – 13 = 37 Original Equation Add 13 to both sides Simplify
Divide both sides by 5 to get q by itself Solution  Check it.

5 Solve: 3 + a = -2 Original Equation
Subtract 3 from both sides to get a by itself. Simplify and solve for a. Check your solution: 3 + (-5) = -2 3 – 5 = -2 -2 = -2 True

6 Solve: 5x + 3(x + 4) = 28 5x + 3(x + 4) = 28
5x + 3x + 12 = 28 Distribute 8x + 12 = 28 Combine like terms (the 5x & 3x) 8x + 12 – 12 = 28 – 12 Subtract 12 from both sides 8x = Simplify 8x/8 = 16/8 Divide both sides by 8 X = 2 Simplify Check 5(2) + 3(2 + 4) = (8) = 28 = = 28

7 Solve: Multiply both sides by -3 Cancel the -3s on the left side
Simplify Subtract 8 from both sides Simplify Check

8 Find three consecutive odd integers whose sum is 57.
Consecutive odd integer examples: 3,5,7 Let n = 1st odd integer n + 2 = 2nd odd integer n + 4 = 3rd odd integer Equation: n + n n + 4 = 57 3n + 6 = 57 3n + 6 – 6 = 57 – 6 3n = 51 3n/3 = 51/3 n = 17 n + 2 = = 19 n + 4 = = 21

9 Homework #13 p odd, 47-49


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