1. Energy = m x c x θ Energy = 5 x 300 x 10 Energy = 15,000 J
speed = wavelength
frequency
Energy = x x
= m
1.0
Energy = ,000 J

2. Energy = m x c x θ Energy = 5 x 300 x 10 Energy = 15,000 J
speed = wavelength
frequency
Energy = x x
= m
1.0
Energy = ,000 J

3. Energy = m x c x θ
= x c x
c = J/kgC
E = m x c x θ
E = x x
E = 40,000 J

4. Energy = m x c x θ
= x c x
c = J/kgC
E = m x c x θ
E = x x
E = 40,000 J

5. Energy = m x c x θ
E = x x
E = 88,000 J
Energy = POWER X TIME
5a Energy = W X 10 s = 20,000 J
5b Energy = W X 60s = ,000 J

6. Energy = m x c x θ
E = x x
E = 88,000 J
Energy = POWER X TIME
5a Energy = W X 10 s = 20,000 J
5b Energy = W X 60s = ,000 J

7. 6a Energy = POWER X TIME
Energy = W X 120 s = 6,000 J
6b E = m x c x θ
6, = x c x 1
c = J/kgC

8. 6a Energy = POWER X TIME
Energy = W X 120 s = 6,000 J
6b E = m x c x θ
6, = x c x 1
c = J/kgC

9. E /min = m x c x θ/min
E /min = x x
E /min = ,000 J /min
Power = Joules / sec or Watts !
Power = 63,000 J /min so divide by 60 to get J/sec
Power = J /sec = about 1 kW

10. E /min = m x c x θ/min
E /min = x x
E /min = ,000 J /min
Power = Joules / sec or Watts !
Power = 63,000 J /min so divide by 60 to get J/sec
Power = J /sec = about 1 kW

11. The jam will have a higher specific heat capacity and take a longer time to cool down than the pastry pudding part.

12. The jam will have a higher specific heat capacity and take a longer time to cool down than the pastry pudding part.

13. Heat lost by hot water cooling = heat gained by cold water warming
mh x c x θh = mc x c x θc
x c x ( ) = mc x c x ( )
x c x ( 30 ) = mc x c x ( 40 )
= mc x
45 kg = mc

14. Heat lost by hot water cooling = heat gained by cold water warming
mh x c x θh = mc x c x θc
x c x ( ) = mc x c x ( )
x c x ( 30 ) = mc x c x ( 40 )
= mc x
45 kg = mc