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Inscribed Angles Chapter 10-4
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Find measures of inscribed angles.
Find measures of angles of inscribed polygons. intercepted Standard Students prove and use theorems involving the properties of parallel lines cut by a transversal, the properties of quadrilaterals, and the properties of circles. (Key) Standard Students prove and solve problems regarding relationships among chords, secants, tangents, inscribed angles, and inscribed and circumscribed polygons of circles. (Key) Lesson 4 MI/Vocab
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Inscribed Angles Def: An angle whose vertex is on a circle and whose sides contain chords The arc that lies in the interior of an inscribed angle and has endpoints on the angle is called the Intercepted Arc of the angle
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Inscribed Angles X = ½ Y Y = 2X
The measure of an inscribed angle is one half of its intercepted arc. X Y X = ½ Y Y = 2X
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Measures of Inscribed Angles
20 40 a a = 360 2a = 360 2a = 192 a = 96 a 108 Lesson 4 Ex1
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Measures of Inscribed Angles
20 40 m1 = m2 = m3 = m4 = m5 = 96 96 180 – ( ) = 106 108 Lesson 4 Ex1
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A. 30 B. 60 C. 15 D. 120 A B C D Lesson 4 CYP1
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A. 110 B. 55 C. 125 D. 27.5 A B C D Lesson 4 CYP1
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A. 30 B. 80 C. 40 D. 10 A B C D Lesson 4 CYP1
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A. 110 B. 55 C. 125 D. 27.5 A B C D Lesson 4 CYP1
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A. 110 B. 55 C. 125 D. 27.5 A B C D Lesson 4 CYP1
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Inscribed Angles mX = m Y
If two inscribed angles of a circle intercept the same arc (or arcs), then the angles are . X Y mX = m Y
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Proof with Inscribed Angles
Given: Prove: ΔPJK ΔEHG
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Proof with Inscribed Angles
Statements Reasons 1. Given 1. 2. 2. If 2 chords are , corr. minor arcs are . 3. 3. Definition of intercepted arc 4. 4. Inscribed angles of arcs are . 5. 5. Right angles are congruent. 6. ΔPJK ΔEHG 6. AAS Lesson 4 Ex2
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Choose the best reason to complete the following proof.
Given: Prove: ΔCEM ΔHJM Lesson 4 CYP2
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3. Vertical angles are congruent. 4. Radii of a circle are congruent.
1. Given 2. ______ 3. Vertical angles are congruent. 4. Radii of a circle are congruent. 5. ASA Proof: Statements Reasons 1. 2. 3. 4. 5. ΔCEM ΔHJM Alternate Interior Angle Theorem Substitution C. Definition of angles D. Inscribed angles of arcs are . Lesson 4 CYP2
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9th and 10th grade teachers should cover this topic briefly.
Inscribed Arcs and Probability This Topic will not be on the chapter 10 test. But Geometric probability will appear on the CST. 9th and 10th grade teachers should cover this topic briefly. Lesson 4 Ex3
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9th and 10th grade teachers should cover this topic briefly.
Inscribed Arcs and Probability This Topic will not be on the chapter 10 test. But Geometric probability will appear on the CST. 9th and 10th grade teachers should cover this topic briefly. The probability that is the same as the probability of L being contained in Lesson 4 Ex3
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9th and 10th grade teachers should cover this topic briefly.
This Topic will not be on the chapter 10 test. But Geometric probability will appear on the CST. 9th and 10th grade teachers should cover this topic briefly. A. B. C. D. A B C D Lesson 4 CYP3
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Inscribed Angles A 90o inscribed angle intercepts a 180o arc
C is a right AB is a diameter of the circle C B A R = 2.5 5 3 4
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Lesson 4 TH3
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Lesson 4 Ex4
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A. 45 B. 90 C. 180 D. 80 A B C D Lesson 4 CYP4
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A. 17 B. 76 C. 60 D. 42 A B C D Lesson 4 CYP4
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A. 17 B. 76 C. 60 D. 42 A B C D Lesson 4 CYP4
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A. 73 B. 30 C. 60 D. 48 A B C D Lesson 4 CYP4
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Inscribed Polygons Reminder: If all the vertices of a polygon lie on the circle The polygon is inscribed in the circle The circle is circumscribed about the polygon A quadrilateral can be inscribed in a circle its opposite angles are supplementary Supplementary—adds up to 180o
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3x + 2 2x-7 Inscribed Polygons (3x + 2) + (2x –7) =180 5x – 5 = 180
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Angles of an Inscribed Quadrilateral
Draw a sketch of this situation. Lesson 4 Ex5
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Angles of an Inscribed Quadrilateral
To find we need to know To find first find Inscribed Angle Theorem Sum of arcs in circle = 360 Subtract 174 from each side. Lesson 4 Ex5
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Angles of an Inscribed Quadrilateral
Inscribed Angle Theorem Substitution Divide each side by 2. Since we now know three angles of a quadrilateral, we can easily find the fourth. mQ + mR + mS + mT = ° in a quadrilateral mT = 360 Substitution mT = 78 Subtraction Answer: mS = 93; mT = 78 Lesson 4 Ex5
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A. 99 B. 104 C. 81 D. 76 A B C D Lesson 4 CYP5
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A. 99 B. 104 C. 81 D. 76 A B C D Lesson 4 CYP5
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Homework Chapter 10-4 Pg 583 6 – 8, 15 – 21, 24 – 31 all
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