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Today’s lecture – review Chapters 9-14, problem solving techniques
Announcements Remember -- Tuesday, Oct. 28th, 9:30 AM – Second exam (covering Chapters 9-14 of HRW) – Bring the following: 1 equation sheet Calculator Pencil Clear head Note: If you have kept up with your HW, you may drop your lowest exam grade Today --Thursday, Oct. 23th, 4 PM – Physics Colloquium by Professor Bernd Schüttler, Dept. of Physics, U. Ga – will discuss the analysis of biological systems in terms of a physical and mathematical model Today’s lecture – review Chapters 9-14, problem solving techniques 12/7/2018 PHY Lecture 14R
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Gravitational forces and energy
m r v0 Energy needed to escape Earth’s gravitational field, assuming an initial velocity : v0 12/7/2018 PHY Lecture 14R
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Energy needed to go from one stable circular orbit to another:
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Energy needed to go from one stable circular orbit to another --
Example: How much energy is needed to take a satellite of mass m=100kg from the international space station (R1=RE+390 km) to its usual orbit (R2=RE+600 km)? R1 R2 12/7/2018 PHY Lecture 14R
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Problem solving skills
Equation Sheet Math skills Advice: Keep basic concepts and equations at the top of your head. Practice problem solving and math skills Develop an equation sheet that you can consult. 12/7/2018 PHY Lecture 14R
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Visualize problem – labeling variables
Problem solving steps Visualize problem – labeling variables Determine which basic physical principle applies Write down the appropriate equations using the variables defined in step 1. Check whether you have the correct amount of information to solve the problem (same number of knowns and unknowns. Solve the equations. Check whether your answer makes sense (units, order of magnitude, etc.). 12/7/2018 PHY Lecture 14R
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Center of mass ri rj 12/7/2018 PHY Lecture 14R
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Position of the center of mass:
Velocity of the center of mass: Acceleration of the center of mass: 12/7/2018 PHY Lecture 14R
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Physics of composite systems:
Center-of-mass velocity: Note that: 12/7/2018 PHY Lecture 14R
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A new way to look at Newton’s second law:
Define linear momentum p = mv Consequences: If F = p = constant For system of particles: 12/7/2018 PHY Lecture 14R
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Statement of conservation of momentum:
If mechanical (kinetic) energy is conserved, then: 12/7/2018 PHY Lecture 14R
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Snapshot of a collision:
Pi Impulse: Pf 12/7/2018 PHY Lecture 14R
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angular “displacement” q(t) angular “velocity”
Angular motion angular “displacement” q(t) angular “velocity” angular “acceleration” s “natural” unit == 1 radian Relation to linear variables: sq = r (qf-qi) vq = r w aq = r a 12/7/2018 PHY Lecture 14R
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Special case of constant angular acceleration: a = a0:
v1=r1w w r2 v2=r2w Special case of constant angular acceleration: a = a0: w(t) = wi + a0 t q(t) = qi + wi t + ½ a0 t2 ( w(t))2 = wi2 + 2 a0 (q(t) - qi ) 12/7/2018 PHY Lecture 14R
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Newton’s second law applied to center-of-mass motion
Newton’s second law applied to rotational motion ri mi di Fi 12/7/2018 PHY Lecture 14R
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Object rotating with constant angular velocity (a = 0)
v=Rw v=0 Kinetic energy associated with rotation: “moment of inertia” 12/7/2018 PHY Lecture 14R
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Kinetic energy associated with rolling without slipping:
Distance to axis of rotation Rolling: 12/7/2018 PHY Lecture 14R
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Torque and angular momentum Define angular momentum:
For composite object: L = Iw Newton’s law for torque: If ttotal = 0 then L = constant In the absence of a net torque on a system, angular momentum is conserved. 12/7/2018 PHY Lecture 14R
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Center-of-mass Torque on an extended object due to gravity (near surface of the earth) is the same as the torque on a point mass M located at the center of mass. mi ri rCM 12/7/2018 PHY Lecture 14R
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Notion of equilibrium:
Notion of stability: T- mg cos q = 0 -mg sin q = -maq F=ma r q T t=I a r mg sin q = mr2 a = mraq Example of stable equilibrium. mg(-j) 12/7/2018 PHY Lecture 14R
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Analysis of stability:
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12/7/2018 PHY Lecture 14R
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