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GROUP Closure Associativity Identity
A group is a mathematical system that has the following properties: Closure Associativity Identity every element has an Inverse
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example 1
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 3 4 = the remainder when 12 is divided by 5
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 The system has CLOSURE
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 The system has an IDENTITY = 1
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 The system has an IDENTITY = 1 The INVERSE of 2 is 3 The INVERSE of 4 is 4
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 The system has ASSOCIATIVITY 4 ( 2 3 ) (4 2 ) 3
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 The system has ASSOCIATIVITY 4 ( 2 3 ) (4 2 ) 3 4 ( 1 ) (3 ) 3
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G = { 1, 2, 3, 4 } operation defined: x y = the remainder when xy is divided by 5 1 2 3 4 The system has ASSOCIATIVITY = 4 ( 2 3 ) (4 2 ) 3 4 ( 1 ) (3 ) 3 4 4 etc.
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example 2
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G = { i, k, m, p, r, s } is a group with operation * as defined below:
G has CLOSURE: for all x and y in G, x*y is in G. The IDENTITY is i : for all x in G, ix = xi = x Every element in G has an INVERSE: k*m = i p*p = i r*r = i s*s = i
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G has ASSOCIATIVITY: for every x, y, and z in G, (x*y)*z = x*(y*z) for example: ( k*p )* r ( s )* r m = k* ( p* r ) k* ( k ) m
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G = { i, k, m, p, r, s } is a group with operation * as defined below:
G does NOT have COMMUTATIVITY: p*r = r*p
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H = { i, k, m } is a SUBGROUP
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example 3
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M = { A,B,C,D,E,F,G,H } is a noncommutative group.
N = { B, C, E, G } is a subgroup of M
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example 4
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Q is a commutative group
R = { c, f, I } is a subgroup of Q
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Theorem: Every group has the cancellation property.
No element is repeated in the same row of the table. No element is repeated in the same column of the table. If then
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EXERCIZE
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COMPLETE THE TABLE TO MAKE A GROUP:
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What is the IDENTITY? If r were the identity, then rw would be w If s were the identity, then sv would be v If w were the identity, then wr would be r
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The IDENTITY is t tr = r r
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The IDENTITY is t tr = r ts = s r s
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tr = r ts = s tt = t tu = u tv = v tw = w The IDENTITY is t t u r s w
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rt = r st = s tt = t ut = u vt = v wt = w r s u v w The IDENTITY is t
and rt = r r st = s s tt = t t ut = u u r s u v w vt = v v wt = w w
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sv = t s and v are INVERSES vs = t t
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u is its own inverse
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INVERSES: sv = t tt = t uu = t What about w and r ? w and r are
not inverses. w w = t and rr = t t
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CANCELLATION PROPERTY:
no element is repeated in any row or column u and w are missing in yellow column There is a u in blue row u uv must be w rv must be u w
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u and v are missing in yellow column
There is a u in blue row uw must be v vw must be u v u
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u is missing u r and s are missing s r r and w are missing w r s and u are missing u s
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Why is the cancellation property useless in completing the remaining
four spaces? v and w are missing from each row and column with blanks. We can complete the table using the associative property.
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( r s ) w = r ( s w ) ASSOCIATIVITY ( r s ) w = r ( s w ) ( r s ) w = r ( r ) ( r s ) w = t ( r s ) w = t w w
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w v w v
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