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South Dakota School of Mines & Technology Introduction to Probability & Statistics Industrial Engineering
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Introduction to Probability & Statistics Continuous Review
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Expectations Continuous Review Mean and Variance
Cumulative and Inverse Functions Mean and Variance Expected Value properties for one variable Expected Value properties for two variables Central Limit Theorem
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Continuous Distribution
f(x) A x a b c d 1. f(x) > , all x 2. 3. P(A) = Pr{a < x < b} = 4. Pr{X=a} = f x dx a d ( ) 1 b c
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Normal Distribution f x e ( ) 1 2 65% 95%
1 2 65% 95% 99.7%
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Std. Normal Transformation
Standard Normal f(z) Z X f z e ( ) 1 2 N(0,1)
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Example Suppose the distribution of student grades for university are approximately normally distributed with a mean of 3.0 and a standard deviation of What percentage of students will graduate magna or summa cum laude? x 3.0 3.5
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Example Cont. ÷ ø ö ç è æ - ³ = 3 . 5 Pr s m X
3.0 3.5 Pr{magna or summa} = Pr{X > 3.5}} ÷ ø ö ç è æ - = 3 . 5 Pr s m X = Pr(z > 1.67) = =
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Example Suppose we wish to relax the criteria so that 10% of the student body graduates magna or summa cum laude. x 3.0 ? 0.1
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Example Suppose we wish to relax the criteria so that 10% of the student body graduates magna or summa cum laude. x 3.0 ? 0.1 0.1 = Pr{Z > z} z = 1.282
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Example x = m + sz = 3.0 + 0.3 x 1.282 = 3.3846 But s m - = X Z 3.0 ?
0.1 But s m - = X Z x = m + sz = x 1.282 =
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Example Let X = lifetime of a machine where the life is governed by the exponential distribution. determine the probability that the machine fails within a given time period a. , x > 0, > 0 f x e ( )
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Example f x e ( ) F a X ( ) Pr{ } e dx e 1 e a
Exponential Life 2.0 f x e ( ) 1.8 1.6 1.4 1.2 F a X ( ) Pr{ } f(x) Density 1.0 0.8 0.6 e dx x a 0.4 0.2 0.0 0.5 1 1.5 2 2.5 3 e x a a Time to Fail 1 e a
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Complementary F a X ( ) Pr{ } e dx e
Exponential Life Suppose we wish to know the probability that the machine will last at least a hrs? 2.0 1.8 1.6 1.4 1.2 f(x) Density 1.0 0.8 0.6 F a X ( ) Pr{ } 0.4 0.2 0.0 e dx x a 0.5 1 1.5 2 2.5 3 a Time to Fail e a
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Example Suppose for the same exponential distribution, we know the probability that the machine will last at least a more hrs given that it has already lasted c hrs. a c c+a Pr{X > a + c | X > c} = Pr{X > a + c X > c} / Pr{X > c} = Pr{X > a + c} / Pr{X > c} e c a ( )
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