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Driving reactions to completion

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Presentation on theme: "Driving reactions to completion"— Presentation transcript:

1 Driving reactions to completion

2 Driving reactions to completion
Completion = 100% yield of product

3 Cl-(aq) + Ag+(aq) AgCl(s)

4 Cl-(aq) + Ag+(aq) AgCl(s)
AgCl precipitates from the solution.

5 Cl-(aq) + Ag+(aq) AgCl(s)
AgCl precipitates from the solution. As the AgCl precipitates, product is removed from solution.

6

7 Cl-(aq) + Ag+(aq) AgCl(s)

8 All gases N2 + 3 H NH3

9 All gases N2 + 3 H NH3 exothermic

10 All gases N2 + 3 H NH3 exothermic cool

11 All gases N2 + 3 H NH3 exothermic cool

12 N2 + 3 H NH3 Although a lower temperature favors more NH3 formed, the lower temperature also leads to a very slow reaction.

13 N2 + 3 H NH3 An increase in pressure should favor product.

14 N2 + 3 H NH3 An increase in pressure should favor product.

15 N2 + 3 H NH3 Ultimate solution: react at high Temperature to speed up reaction, cool until NH3 becomes liquid. Remove from reaction vessel and repeat.

16 C O N E T R A I (time)

17 Heterogeneous equilibrium

18 Heterogeneous equilibrium
Involves at least two phases.

19 Heterogeneous equilibrium
Involves at least two phases. What is the concentration of a pure liquid or a pure solid?

20 Concentrations are not a valid
way to define a pure liquid or solid.

21 Concentrations are not a valid
way to define a pure liquid or solid. Moles water = ? Liters solvent

22 The concentration of a pure liquid
or solid is defined as 1.

23 Law of Mass Action

24 Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres.

25 Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres. 2. Dissolved species enter as concentrations in mol L-1.

26 Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres. 2. Dissolved species enter as concentrations in mol L-1. 3. Pure solids and liquids are represented by 1 at equilibrium , a dilute solvent is 1.

27 Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres. 2. Dissolved species enter as concentrations in mol L-1. 3. Pure solids and liquids are represented by 1 at equilibrium , a dilute solvent is 1. 4. Partial pressures or concentrations of products appear in the numerator, reactants in the denominator. Each is raised to the power of its coefficient.

28 The partition coefficient:

29 The partition coefficient:
Materials are soluble to different degrees in different solvents.

30 The partition coefficient:
Materials are soluble to different degrees in different solvents. This allows for a method to separate that material from others.

31 Solvent a Solvent b Compound x

32 Solvent a Solvent b Compound x [x]a  [x]b

33 [x]a  [x]b Partition coefficient = K = [x]b [x]a

34 I2 H2O CCl4

35 I2 H2O and CCl4 are immiscible H2O CCl4

36 I2(H2O) I2(CCl4) H2O CCl4

37 I2(H2O) I2(CCl4) [I2]CCl4 K = [I2]H2O H2O CCl4

38 I2(H2O) I2(CCl4) [I2]CCl4 K = [I2]H2O H2O = 85 Partition coefficient CCl4

39 Acids and Bases

40 Acids and Bases Arrhenius Acids and Bases

41 Acids and Bases Arrhenius Acids and Bases Acid : increases H+ concentration in water.

42 Acids and Bases Arrhenius Acids and Bases Acid : increases H+ concentration in water. Base : increases OH- concentration in water.

43 Acids and Bases Brønsted-Lowrey Acids and Bases

44 Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+.

45 Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Base : substance that can accept H+.

46 Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Base : substance that can accept H+. Do not require aqueous solutions.

47 Acids and Bases Brønsted-Lowrey Acids and Bases Conjugate acid-base pairs.

48 Acids and Bases Brønsted-Lowrey Acids and Bases Conjugate acid-base pairs. Conjugate base: subtract H+ from acid formula.

49 Acids and Bases Brønsted-Lowrey Acids and Bases Conjugate acid-base pairs. Conjugate base: subtract H+ from acid formula. Conjugate acid: add H+ to the base formula.

50 Conjugate acid-base pairs.

51 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l)

52 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) Acetic acid is a monoprotic acid.

53 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq)

54 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid

55 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid H2O accepts H+ = base

56 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid CH3COO- = conjugate base H2O accepts H+ = base

57 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid CH3COO- = conjugate base H2O accepts H+ = base H3O+ = conjugate acid

58 Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) acid1 base2 H3O+(aq) + CH3COO-(aq) acid2 base1 CH3COOH donates H+ = acid CH3COO- = conjugate base H2O accepts H+ = base H3O+ = conjugate acid

59 Conjugate acid-base pairs.
H2O H2O H+ + OH-

60 Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid

61 Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid H2O + H H3O+

62 Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid H2O + H H3O+ H2O accepts H+ = base

63

64 +

65 + +

66 Conjugate acid-base pairs.
Conjugate base: subtract H+ from acid formula. Conjugate acid: add H+ to the base formula.

67 Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid Conjugate base = OH- H2O + H H3O+ H2O accepts H+ = base Conjugate acid = H3O+

68 Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid Conjugate base = OH- H2O + H H3O+ H2O accepts H+ = base Conjugate acid = H3O+ H2O can be both conjugate acid and base.

69 Trimethyl amine is a weak base.
What is the conjugate acid?

70 Trimethyl amine is a weak base.
What is the conjugate acid? (CH3)3N

71 Trimethyl amine is a weak base.
What is the conjugate acid? (CH3)3N

72 Trimethyl amine is a weak base.
What is the conjugate acid? [(CH3)3NH]+ Conjugate acid

73 NaCN dissolved in water gives
a basic solution. Why?

74 NaCN dissolved in water gives
a basic solution. Why? NaCN(s) + H2O(l) Na+(aq) + CN-(aq) + H2O(l)

75 NaCN dissolved in water gives
a basic solution. Why? NaCN(s) + H2O(l) Na+(aq) + CN-(aq) + H2O(l)

76 NaCN dissolved in water gives
a basic solution. Why? NaCN(s) + H2O(l) Na+(aq) + CN-(aq) + H2O(l) + H2O(l) HCN(aq) + OH-(aq)

77 Non-aqueous solutions

78 Non-aqueous solutions
NH3(l)

79 Non-aqueous solutions
HCl(NH ) + NH3(l) NH4+(NH ) + Cl-(NH ) 3 3 3

80 Non-aqueous solutions
HCl(NH ) + NH3(l) NH4+(NH ) + Cl-(NH ) 3 3 3 acid1 base2 acid2 base1

81 Non-aqueous solutions
HCl(NH ) + NH3(l) NH4+(NH ) + Cl-(NH ) 3 3 3 acid1 base2 acid2 base1 Ammonia is the solvent.

82 Amphoteric molecules

83 Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions.

84 Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions. water

85 Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions. water H3O+

86 Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions. water H3O+ OH-

87 Amphoteric molecules Hydrogen carbonate ion

88 Amphoteric molecules Hydrogen carbonate ion HCO3-

89 Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq)

90 Hydrogen carbonate ion
Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq) base1 acid2 acid1 base2

91 Hydrogen carbonate ion
Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq) base1 acid2 acid1 base2 HCO3-(aq) + H2O(l) CO32-(aq) + H3O+(aq)

92 Hydrogen carbonate ion
Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq) base1 acid2 acid1 base2 HCO3-(aq) + H2O(l) CO32-(aq) + H3O+(aq) acid1 base2 base1 acid2

93 Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Base : substance that can accept H+.

94 Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Dependant on strength of base present. Base : substance that can accept H+.

95 Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Dependant on strength of base present. Base : substance that can accept H+. Dependant on strength of acid present.

96 The pH scale

97 The pH scale Water always has some H3O+ and OH- present.

98 The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq)

99 The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq) [H3O+][OH-] KW = [H2O]2

100 The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq) [H3O+][OH-] [H3O+][OH-] KW = = [H2O]2

101 The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq) [H3O+][OH-] [H3O+][OH-] = 1.0 x10-14 KW = = [H2O]2 @ 25oC

102 KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC

103 KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC?

104 KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC? [X][X] = 1.0 x 10-14

105 KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC? [X][X] = 1.0 x 10-14 X2 = 1.0 x 10-14

106 KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC? [X][X] = 1.0 x 10-14 X2 = 1.0 x 10-14 X = 1.0 x 10-7

107 pH = -log10[H3O+]

108 pH = -log10[H3O+] [H3O+] = 1.0 x 10-7

109 pH = -log10[H3O+] [H3O+] = 1.0 x 10-7 -log10(1.0 x 10-7) =

110 pH = -log10[H3O+] [H3O+] = 1.0 x 10-7 -log10(1.0 x 10-7) = -1 x -7 = 7 pH neutral water = 7

111 pH of a water solution of a
strong acid.

112 pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)

113 pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%.

114 pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%. 0.1 M HCl M H3O+

115 pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%. 0.1 M HCl M H3O+ [H3O+] = 1.0 x 10-1 M

116 pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%. 0.1 M HCl M H3O+ [H3O+] = 1.0 x 10-1 M pH = 1

117 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l)

118 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M

119 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M KW = 1.0 x = [H3O+][OH-]

120 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M KW = 1.0 x = [H3O+][OH-] 1.0 x 10-14 [H3O+] = 0.1

121 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M KW = 1.0 x = [H3O+][OH-] 1.0 x 10-14 [H3O+] = = 1.0 x 10-13 0.1

122 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) 1.0 x 10-14 [H3O+] = = 1.0 x 10-13 0.1 pH = -log x =

123 pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) 1.0 x 10-14 [H3O+] = = 1.0 x 10-13 0.1 pH = -log x = 13

124 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-].

125 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14

126 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 (2x)(x) = 1.0 x 10-14

127 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 (2x)(x) = 1.0 x 10-14 2x2 = 1.0 x 10-14

128 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 (2x)(x) = 1.0 x 10-14 2x2 = 1.0 x 10-14 x2 = 0.5 x 10-14

129 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 x2 = 0.5 x 10-14 x = 7.07 x 10-08

130 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 x2 = 0.5 x 10-14 x = 7.07 x 10-08 2x = x 10-07

131 Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 x2 = 0.5 x 10-14 x = 7.07 x 10-08 2x = x 10-07 -log10 2x = 6.85

132 Calculating concentration from pH.

133 Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-]

134 Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-] [H3O+] =

135 Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-] [H3O+] = = 1.4 x 10-03

136 Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-] [H3O+] = = 1.4 x 10-03 [H3O+] = 1.4 x M

137 [H3O+] = 1.4 x M 1.0 x 10-14 [OH-] = = 1.4 x 10-03

138 [H3O+] = 1.4 x M 1.0 x 10-14 7.1 x 10-12 [OH-] = = 1.4 x 10-03

139 Acids and bases of varying strengths.

140 Acids and bases of varying strengths.
Strong acid = 100% ionization Strong acid = 100% donation of acidic proton.

141 HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)

142 HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
[H3O+][Cl-] K = [HCl]

143 HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
[H3O+][Cl-] large K = = [HCl]

144 Generic acid HA(aq) + H2O(l) H3O+(aq) + A-(aq)

145 Generic acid HA(aq) + H2O(l) H3O+(aq) + A-(aq) [H3O+][A-] = acidity constant = Ka [HA]

146 Generic acid HA(aq) + H2O(l) H3O+(aq) + A-(aq) [H3O+][A-] = acidity constant = Ka [HA] -log10 Ka = pKa

147 Acid Ka pKa HI  -11 HCl   -7 H2SO   -2 CH3COOH x Table page 332

148 Base strength

149 Base strength Inversely related to strength of conjugate acid.

150 Base strength Inversely related to strength of conjugate acid. H2O(l) + B(aq) HB+(aq) + OH-(aq) conjugate acid

151 H2O(l) + B(aq) HB+(aq) + OH-(aq)
[HB+][OH-] = Kb = basicity constant [B]

152 [HB+][OH-] = Kb = basicity constant [B] [H3O+][B] = acidity constant = Ka [HB+] [H3O+][OH-] = Kw

153 [HB+][OH-] = Kb = basicity constant [B] [H3O+][B] = acidity constant = Ka [HB+] Conjugate acid [H3O+][OH-] = Kw KbKa = Kw

154 [HB+][OH-] = Kb = basicity constant [B] [H3O+][B] = acidity constant = Ka [HB+] [H3O+][OH-] = Kw KbKa = Kw pKb + pKa = pKw

155 KbKa = Kw pKb + pKa = pKw Expressions can be used for any conjugate acid-base pair in water.

156 Indicators : Usually a weak organic acid that has a color different from its conjugate base.

157 Indicators : Usually a weak organic acid that has a color different from its conjugate base. HA + H2O H3O+ + A-

158


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