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Driving reactions to completion
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Driving reactions to completion
Completion = 100% yield of product
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Cl-(aq) + Ag+(aq) AgCl(s)
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Cl-(aq) + Ag+(aq) AgCl(s)
AgCl precipitates from the solution.
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Cl-(aq) + Ag+(aq) AgCl(s)
AgCl precipitates from the solution. As the AgCl precipitates, product is removed from solution.
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Cl-(aq) + Ag+(aq) AgCl(s)
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All gases N2 + 3 H NH3
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All gases N2 + 3 H NH3 exothermic
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All gases N2 + 3 H NH3 exothermic cool
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All gases N2 + 3 H NH3 exothermic cool
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N2 + 3 H NH3 Although a lower temperature favors more NH3 formed, the lower temperature also leads to a very slow reaction.
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N2 + 3 H NH3 An increase in pressure should favor product.
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N2 + 3 H NH3 An increase in pressure should favor product.
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N2 + 3 H NH3 Ultimate solution: react at high Temperature to speed up reaction, cool until NH3 becomes liquid. Remove from reaction vessel and repeat.
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C O N E T R A I (time)
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Heterogeneous equilibrium
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Heterogeneous equilibrium
Involves at least two phases.
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Heterogeneous equilibrium
Involves at least two phases. What is the concentration of a pure liquid or a pure solid?
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Concentrations are not a valid
way to define a pure liquid or solid.
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Concentrations are not a valid
way to define a pure liquid or solid. Moles water = ? Liters solvent
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The concentration of a pure liquid
or solid is defined as 1.
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Law of Mass Action
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Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres.
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Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres. 2. Dissolved species enter as concentrations in mol L-1.
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Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres. 2. Dissolved species enter as concentrations in mol L-1. 3. Pure solids and liquids are represented by 1 at equilibrium , a dilute solvent is 1.
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Law of Mass Action 1. Gases enter equilibrium expressions as partial pressures in atmospheres. 2. Dissolved species enter as concentrations in mol L-1. 3. Pure solids and liquids are represented by 1 at equilibrium , a dilute solvent is 1. 4. Partial pressures or concentrations of products appear in the numerator, reactants in the denominator. Each is raised to the power of its coefficient.
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The partition coefficient:
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The partition coefficient:
Materials are soluble to different degrees in different solvents.
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The partition coefficient:
Materials are soluble to different degrees in different solvents. This allows for a method to separate that material from others.
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Solvent a Solvent b Compound x
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Solvent a Solvent b Compound x [x]a [x]b
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[x]a [x]b Partition coefficient = K = [x]b [x]a
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I2 H2O CCl4
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I2 H2O and CCl4 are immiscible H2O CCl4
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I2(H2O) I2(CCl4) H2O CCl4
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I2(H2O) I2(CCl4) [I2]CCl4 K = [I2]H2O H2O CCl4
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I2(H2O) I2(CCl4) [I2]CCl4 K = [I2]H2O H2O = 85 Partition coefficient CCl4
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Acids and Bases
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Acids and Bases Arrhenius Acids and Bases
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Acids and Bases Arrhenius Acids and Bases Acid : increases H+ concentration in water.
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Acids and Bases Arrhenius Acids and Bases Acid : increases H+ concentration in water. Base : increases OH- concentration in water.
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Acids and Bases Brønsted-Lowrey Acids and Bases
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Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+.
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Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Base : substance that can accept H+.
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Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Base : substance that can accept H+. Do not require aqueous solutions.
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Acids and Bases Brønsted-Lowrey Acids and Bases Conjugate acid-base pairs.
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Acids and Bases Brønsted-Lowrey Acids and Bases Conjugate acid-base pairs. Conjugate base: subtract H+ from acid formula.
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Acids and Bases Brønsted-Lowrey Acids and Bases Conjugate acid-base pairs. Conjugate base: subtract H+ from acid formula. Conjugate acid: add H+ to the base formula.
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Conjugate acid-base pairs.
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l)
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) Acetic acid is a monoprotic acid.
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq)
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid H2O accepts H+ = base
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid CH3COO- = conjugate base H2O accepts H+ = base
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) CH3COOH donates H+ = acid CH3COO- = conjugate base H2O accepts H+ = base H3O+ = conjugate acid
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Conjugate acid-base pairs.
CH3COOH(aq) + H2O(l) acid1 base2 H3O+(aq) + CH3COO-(aq) acid2 base1 CH3COOH donates H+ = acid CH3COO- = conjugate base H2O accepts H+ = base H3O+ = conjugate acid
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Conjugate acid-base pairs.
H2O H2O H+ + OH-
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Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid
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Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid H2O + H H3O+
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Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid H2O + H H3O+ H2O accepts H+ = base
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+
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+ +
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Conjugate acid-base pairs.
Conjugate base: subtract H+ from acid formula. Conjugate acid: add H+ to the base formula.
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Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid Conjugate base = OH- H2O + H H3O+ H2O accepts H+ = base Conjugate acid = H3O+
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Conjugate acid-base pairs.
H2O H2O H+ + OH- H2O donates H+ = acid Conjugate base = OH- H2O + H H3O+ H2O accepts H+ = base Conjugate acid = H3O+ H2O can be both conjugate acid and base.
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Trimethyl amine is a weak base.
What is the conjugate acid?
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Trimethyl amine is a weak base.
What is the conjugate acid? (CH3)3N
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Trimethyl amine is a weak base.
What is the conjugate acid? (CH3)3N
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Trimethyl amine is a weak base.
What is the conjugate acid? [(CH3)3NH]+ Conjugate acid
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NaCN dissolved in water gives
a basic solution. Why?
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NaCN dissolved in water gives
a basic solution. Why? NaCN(s) + H2O(l) Na+(aq) + CN-(aq) + H2O(l)
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NaCN dissolved in water gives
a basic solution. Why? NaCN(s) + H2O(l) Na+(aq) + CN-(aq) + H2O(l)
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NaCN dissolved in water gives
a basic solution. Why? NaCN(s) + H2O(l) Na+(aq) + CN-(aq) + H2O(l) + H2O(l) HCN(aq) + OH-(aq)
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Non-aqueous solutions
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Non-aqueous solutions
NH3(l)
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Non-aqueous solutions
HCl(NH ) + NH3(l) NH4+(NH ) + Cl-(NH ) 3 3 3
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Non-aqueous solutions
HCl(NH ) + NH3(l) NH4+(NH ) + Cl-(NH ) 3 3 3 acid1 base2 acid2 base1
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Non-aqueous solutions
HCl(NH ) + NH3(l) NH4+(NH ) + Cl-(NH ) 3 3 3 acid1 base2 acid2 base1 Ammonia is the solvent.
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Amphoteric molecules
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Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions.
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Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions. water
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Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions. water H3O+
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Amphoteric molecules An amphoteric molecule or ion can be either an acid or a base depending on conditions. water H3O+ OH-
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Amphoteric molecules Hydrogen carbonate ion
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Amphoteric molecules Hydrogen carbonate ion HCO3-
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Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq)
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Hydrogen carbonate ion
Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq) base1 acid2 acid1 base2
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Hydrogen carbonate ion
Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq) base1 acid2 acid1 base2 HCO3-(aq) + H2O(l) CO32-(aq) + H3O+(aq)
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Hydrogen carbonate ion
Amphoteric molecules Hydrogen carbonate ion HCO3-(aq) + H2O(l) H2CO3(aq) + OH-(aq) base1 acid2 acid1 base2 HCO3-(aq) + H2O(l) CO32-(aq) + H3O+(aq) acid1 base2 base1 acid2
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Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Base : substance that can accept H+.
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Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Dependant on strength of base present. Base : substance that can accept H+.
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Acids and Bases Brønsted-Lowrey Acids and Bases Acid : substance that can donate H+. Dependant on strength of base present. Base : substance that can accept H+. Dependant on strength of acid present.
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The pH scale
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The pH scale Water always has some H3O+ and OH- present.
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The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq)
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The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq) [H3O+][OH-] KW = [H2O]2
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The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq) [H3O+][OH-] [H3O+][OH-] KW = = [H2O]2
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The pH scale Water always has some H3O+ and OH- present. 2 H2O(l) H3O+(aq) + OH-(aq) [H3O+][OH-] [H3O+][OH-] = 1.0 x10-14 KW = = [H2O]2 @ 25oC
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KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC
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KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC?
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KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC? [X][X] = 1.0 x 10-14
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KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC? [X][X] = 1.0 x 10-14 X2 = 1.0 x 10-14
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KW = [H3O+][OH-] = 1.0 x10-14 @ 25oC If [H3O+] = [OH-] what are their concentrations at 25oC? [X][X] = 1.0 x 10-14 X2 = 1.0 x 10-14 X = 1.0 x 10-7
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pH = -log10[H3O+]
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pH = -log10[H3O+] [H3O+] = 1.0 x 10-7
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pH = -log10[H3O+] [H3O+] = 1.0 x 10-7 -log10(1.0 x 10-7) =
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pH = -log10[H3O+] [H3O+] = 1.0 x 10-7 -log10(1.0 x 10-7) = -1 x -7 = 7 pH neutral water = 7
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pH of a water solution of a
strong acid.
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pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
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pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%.
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pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%. 0.1 M HCl M H3O+
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pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%. 0.1 M HCl M H3O+ [H3O+] = 1.0 x 10-1 M
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pH of a water solution of a
strong acid. HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq) Assume HCl dissociates 100%. 0.1 M HCl M H3O+ [H3O+] = 1.0 x 10-1 M pH = 1
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l)
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M KW = 1.0 x = [H3O+][OH-]
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M KW = 1.0 x = [H3O+][OH-] 1.0 x 10-14 [H3O+] = 0.1
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) [KOH] = 0.1 M KW = 1.0 x = [H3O+][OH-] 1.0 x 10-14 [H3O+] = = 1.0 x 10-13 0.1
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) 1.0 x 10-14 [H3O+] = = 1.0 x 10-13 0.1 pH = -log x =
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pH of a water solution of a
strong base. KOH(aq) + H2O(l) K+(aq) + OH-(aq) + H2O(l) 1.0 x 10-14 [H3O+] = = 1.0 x 10-13 0.1 pH = -log x = 13
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-].
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 (2x)(x) = 1.0 x 10-14
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 (2x)(x) = 1.0 x 10-14 2x2 = 1.0 x 10-14
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 (2x)(x) = 1.0 x 10-14 2x2 = 1.0 x 10-14 x2 = 0.5 x 10-14
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 x2 = 0.5 x 10-14 x = 7.07 x 10-08
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 x2 = 0.5 x 10-14 x = 7.07 x 10-08 2x = x 10-07
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Exercise page 330 Compute pH of aqueous solution having [H3O+] = 2x[OH-]. KW = [H3O+][OH-] = 1.0 x 10-14 x2 = 0.5 x 10-14 x = 7.07 x 10-08 2x = x 10-07 -log10 2x = 6.85
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Calculating concentration from pH.
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Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-]
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Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-] [H3O+] =
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Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-] [H3O+] = = 1.4 x 10-03
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Calculating concentration from pH.
Example 8-4, page 330 pH = 2.85, calculate [H3O+] [OH-] [H3O+] = = 1.4 x 10-03 [H3O+] = 1.4 x M
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[H3O+] = 1.4 x M 1.0 x 10-14 [OH-] = = 1.4 x 10-03
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[H3O+] = 1.4 x M 1.0 x 10-14 7.1 x 10-12 [OH-] = = 1.4 x 10-03
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Acids and bases of varying strengths.
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Acids and bases of varying strengths.
Strong acid = 100% ionization Strong acid = 100% donation of acidic proton.
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HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
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HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
[H3O+][Cl-] K = [HCl]
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HCl(aq) + H2O(l) H3O+(aq) + Cl-(aq)
[H3O+][Cl-] large K = = [HCl]
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Generic acid HA(aq) + H2O(l) H3O+(aq) + A-(aq)
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Generic acid HA(aq) + H2O(l) H3O+(aq) + A-(aq) [H3O+][A-] = acidity constant = Ka [HA]
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Generic acid HA(aq) + H2O(l) H3O+(aq) + A-(aq) [H3O+][A-] = acidity constant = Ka [HA] -log10 Ka = pKa
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Acid Ka pKa HI -11 HCl -7 H2SO -2 CH3COOH x Table page 332
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Base strength
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Base strength Inversely related to strength of conjugate acid.
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Base strength Inversely related to strength of conjugate acid. H2O(l) + B(aq) HB+(aq) + OH-(aq) conjugate acid
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H2O(l) + B(aq) HB+(aq) + OH-(aq)
[HB+][OH-] = Kb = basicity constant [B]
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[HB+][OH-] = Kb = basicity constant [B] [H3O+][B] = acidity constant = Ka [HB+] [H3O+][OH-] = Kw
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[HB+][OH-] = Kb = basicity constant [B] [H3O+][B] = acidity constant = Ka [HB+] Conjugate acid [H3O+][OH-] = Kw KbKa = Kw
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[HB+][OH-] = Kb = basicity constant [B] [H3O+][B] = acidity constant = Ka [HB+] [H3O+][OH-] = Kw KbKa = Kw pKb + pKa = pKw
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KbKa = Kw pKb + pKa = pKw Expressions can be used for any conjugate acid-base pair in water.
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Indicators : Usually a weak organic acid that has a color different from its conjugate base.
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Indicators : Usually a weak organic acid that has a color different from its conjugate base. HA + H2O H3O+ + A-
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