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32 Optical Images image formation reflection & refraction

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1 32 Optical Images image formation reflection & refraction
mirror & lens equations Ch.32 homework: 25, 30-33,35,55-57, 78, 81(ans should be negative). (43 removed)

2 image formation real image: rays converge to a point magnifier used to start paper on fire movie projector virtual image: rays diverge from source “seeing” any real object or light source

3 Plane Mirror Image distances measured from mirror & axis
image height y’ = object height y object distance s = image distance s’

4 Concave Mirror Image distances measured from axis & from plane tangent to mirror at V focal distance is half of curvature radius

5 principal rays 1) parallel ray 2) focal ray 3) radial ray
image is real, inverted, and smaller in this situation 1 2 3

6 convex mirror parallel and radial rays shown
image is upright, virtual, and smaller

7 Mirror Equations you must learn the sign conventions to use these formulas

8 imbedded object image distance < object distance

9 thin lenses have equidistant focal points on either side
converging & diverging types

10 lens equations

11 human eye average index of refraction ~ 1.4

12 Far Sighted Eye correction requires converging lens

13 near sighted eye correction requires diverging lens

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16 summary sections 1 & 2 human eye & refractive corrections
(omitting sections 3, 4)

17 Calculating Focal Length for a Thin Lens
Example: A double convex, thin glass lens with n = 1.5 has radii of curvature of 10 and 15cm. Find its focal length.

18 I O

19 Question: Reverse the designations in the example above
Question: Reverse the designations in the example above. Object is now the fish, so n1 = 1.33 (fish location). Let the fish be 10cm from bowl surface. Where is the image of the fish formed that the cat will see? Answer: s = 10cm , s’ = ?, r = -15cm, n1 = 1.33, n2 = 1.00.  /s’ =  1/s’ =  s’ = -9.00cm

20 2. A document is sealed in a glass cube (n=1
2. A document is sealed in a glass cube (n=1.5) at a depth of 10cm from one surface. Calculate s’ and m. Object is in n1=1.5. Viewer is in air n2=1.00. Radius of surface is r = infinity.  1/s’ =  s’ = -6.67cm. .

21 32-3 Aberrations

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23 32-4 Optical Instruments

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26 s, cat’s nose n1 holds object, here equal to 1.00 /s’= 0.022 1.33/s’ = s’ = -17.1cm

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