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Notes 14 ECE 6340 Intermediate EM Waves Fall 2016

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Presentation on theme: "Notes 14 ECE 6340 Intermediate EM Waves Fall 2016"— Presentation transcript:

1 Notes 14 ECE 6340 Intermediate EM Waves Fall 2016
Prof. David R. Jackson Dept. of ECE Notes 14

2 Plane Wave: Lossless Media
z x y E Assume Then Lossless region: or Solution:

3 Plane Wave: Lossless Media (cont.)
The H field is found from: so

4 Plane Wave: Lossless Media (cont.)
or But (real number) Hence TEMz

5 Plane Wave: Lossless Media (cont.)
so Lossless:  Is real. There is no reactive power.

6 Plane Wave: Lossy Media

7 Plane Wave: Lossy Media (cont.)
The “depth of penetration” dp is defined. Hence

8 Plane Wave: Lossy Media (cont.)

9 Plane Wave in a Good Conductor

10 Plane Wave in Good Conductor (cont.)
Assume The we have Hence Therefore

11 Plane Wave in Good Conductor (cont.)
Denote “skin depth” Then we have

12 Surface Impedance x z Equivalent surface current Actual Model z x

13 Surface Impedance (cont.)
Actual current through y Surface current model Hence

14 Surface Impedance (cont.)
Define Integrating, we have

15 Surface Impedance (cont.)
Hence Hence,

16 Surface Impedance (cont.)
Define “surface resistance” and “surface reactance” so

17 Impedance of a Bulk Conductor
z x Electrodes + - y Assume no x or y variation Electrodes are attached at the outer (top) surface.

18 Impedance of a Bulk Conductor (cont.)
jX

19 DC Equivalent Model DC problem Hence
The thickness in the DC problem is chosen as the skin depth in the high-frequency bulk conductor problem. Hence

20 DC Equivalent Model (cont.)
High-frequency problem (R) DC current problem (RDC)

21 Example Find the high-frequency resistance and inductance for a solid wire. + - Ring electrode The current is uniform along the boundary ( direction), and therefore we can treat this as a “rolled-up” version of a bulk conductor (w = 2 a).

22 Example (cont.) We can also get the same result by using the equivalent DC model. Equivalent DC Model:

23 Example (cont.) High-frequency equivalent circuit: R jX

24 Find the high-frequency resistance and inductance for a hollow tube.
Example Find the high-frequency resistance and inductance for a hollow tube. The electrodes are attached from the outside. + - Ring electrode

25 Find the high-frequency resistance and inductance for a hollow tube.
Example Find the high-frequency resistance and inductance for a hollow tube. The electrodes are attached from the inside. + - Ring electrode

26 Power Dissipation x S z = time-average power dissipated / m2 on S
Fields are evaluated on this plane. = time-average power dissipated / m2 on S

27 Power Dissipation (cont.)
Use where Note:

28 Power Dissipation (cont.)
We then have In general,

29 Power Dissipation (cont.)
For a good conductor, (exactly true for a PEC) Hence, using this approximation, we have

30 Power Dissipation (cont.)
For the reactive power absorbed by the conducting surface (VARS/m2) we have: Hence VARS / m2 = Watts / m2


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