1. Reaction Stoichiometry
Mass A to Mass B

2. The Key to Reaction Conversions
Mass A  Mole A  Mole B  Mass B

3. Mass A  Mole A  Mole B  Mass B
Aluminum metal and chlorine gas react to produce aluminum chloride.

4. Mass A  Mole A  Mole B  Mass B
2 Al (s) + 3 Cl2 (g)  2 AlCl3
a. How many moles of chlorine gas are needed to react with 1.5 moles of aluminum?

5. Mass A  Mole A  Mole B  Mass B
2 Al (s) + 3 Cl2 (g)  2 AlCl3
b. How many grams of AlCl3 will be produced if 2.50 moles of Al react?

6. Mass A  Mole A  Mole B  Mass B
2 Al (s) + 3 Cl2 (g)  2 AlCl3
c. How many moles of Cl2 must react to produce 12.3 g of AlCl3?

7. Mass A  Mole A  Mole B  Mass B
2 Al (s) + 3 Cl2 (g)  2 AlCl3
d. If 17 grams of aluminum react, how many grams of aluminum chloride will be produced?