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First Fit Coloring of Interval Graphs
William T. Trotter Georgia Institute of Technology October 14, 2005
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Interval Graphs
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First Fit with Left End Point Order Provides Optimal Coloring
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Interval Graphs are Perfect
Χ = ω = 4
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What Happens with Another Order?
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On-Line Coloring of Interval Graphs
Suppose the vertices of an interval graph are presented one at a time by a Graph Constructor. In turn, Graph Colorer must assign a legitimate color to the new vertex. Moves made by either player are irrevocable.
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Optimal On-Line Coloring
Theorem (Kierstead and Trotter, 1982) There is an on-line algorithm that will use at most 3k-2 colors on an interval graph G for which the maximum clique size is at most k. This result is best possible. The algorithm does not need to know the value of k in advance. The algorithm is not First Fit. First Fit does worse when k is large.
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Dynamic Storage Allocation
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How Well Does First Fit Do?
For each positive integer k, let FF(k) denote the largest integer t for which First Fit can be forced to use t colors on an interval graph G for which the maximum clique size is at most k. Woodall (1976) FF(k) = O(k log k).
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Upper Bounds on FF(k) Theorem: Kierstead (1988) FF(k) ≤ 40k
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Upper Bounds on FF(k) Theorem: Kierstead and Qin (1996) FF(k) ≤ 26.2k
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Upper Bounds on FF(k) Theorem: Pemmaraju, Raman and Varadarajan(2003)
FF(k) ≤ 10k
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Upper Bounds on FF(k) Theorem: Brightwell, Kierstead
and Trotter (2003) FF(k) ≤ 8k
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Upper Bounds on FF(k) Theorem: Narayansamy and Babu (2004)
FF(k) ≤ 8k - 3
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Analyzing First Fit Using Grids
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The Academic Algorithm
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Academic Algorithm - Rules
A Belongs to an interval B Left neighbor is A C Right neighbor is A D Some terminal set of letters has more than 25% A’s F All else fails.
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A Pierced Interval A B C D
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The Piercing Lemma Lemma: Every interval J is pierced by a column of passing grades. Proof: We use a double induction. Suppose the interval J is at level j. We show that for every i = 1, 2, …, j, there is a column of grades passing at level i which is under interval J
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Double Induction
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Initial Segment Lemma Lemma: In any initial segment of n letters all of which are passing, a ≥ (n – b – c)/4
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A Column Surviving at the End
b ≤ n/4 c ≤ n/4 n ≥ h+3 h ≤ 8a - 3
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Lower Bounds on FF(k) Theorem: Kierstead and Trotter (1982)
There exists ε > 0 so that FF(k) ≥ (3 + ε)k when k is sufficiently large.
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Lower Bounds on FF(k) Theorem: Chrobak and Slusarek (1988)
FF(k) ≥ 4k - 9 when k ≥ 4.
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Lower Bounds on FF(k) Theorem: Chrobak and Slusarek (1990)
FF(k) ≥ 4.4 k when k is sufficiently large.
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Lower Bounds on FF(k) Theorem: Kierstead and Trotter (2004)
FF(k) ≥ 4.99 k when k is sufficiently large.
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A Likely Theorem Our proof that FF(k) ≥ 4.99 k is computer assisted. However, there is good reason to believe that we can actually write out a proof to show: For every ε > 0, FF(k) ≥ (5 – ε) k when k is sufficiently large.
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Tree-Like Walls
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A Negative Result and a Conjecture
However, we have been able to show that the Tree-Like walls used by all authors to date in proving lower bounds will not give a performance ratio larger than 5. As a result it is natural to conjecture that As k tends to infinity, the ratio FF(k)/k tends to 5.
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