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Integration 2a
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BAT Find integrals using rule for log functions
Integration I KUS objectives BAT Find integrals using rule for log functions BAT Solve problems where partial factions used with this rule; Starter: Differentiate π₯β3 7 Integrate π₯β3 7 Integrate π 4π₯+7
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Therefore you can use either x or βx in the Integral
Notes As we are integrating to find the Area, you can see for any 2 points, the area will be the same for either graphβ¦ Therefore you can use either x or βx in the Integral However, you cannot find ln of a negative, just use the positive value instead! This is saying when we Integrate either of the following, we get the same result:
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WB 5 Find the following integral 1 3π₯ + 2 ππ₯
1) Integrate the function using what you know from differentiation 2) Divide by the coefficient of x 3) Simplify if possible and add C We can extend the rule πβ²(ππ₯+π) ππ₯= 1 π ππ₯+π +πΆ To π β² π₯ π π₯ ππ₯= ln π(π₯) +πΆ
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WB 6 Find the following integrals: a) 1 4π₯β5 ππ₯ b) 3 3π₯+11 ππ₯ c) β2 7β6π₯ ππ₯
1 4π₯β5 ππ₯ = ln 4π₯β5 +πΆ 3 3π₯+11 ππ₯ = ln 3π₯ C = ln 3π₯+11 +πΆ β2 7β6π₯ ππ₯ = 1 β6 β2 ln 7β6π₯ +C = ln 7β6π₯ +πΆ
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WB 7 π β² π₯ = 5 5π₯β1 , Given that the curve π(π₯) passes through point (8, ln 16 ) find π(π₯)
Using point (8, ln 3 ) ln 16 = ln 8 +πΆ πΆ = ln 16 β ln 8 = ln 2 So (8, ln 3 ) π π₯ = ln 5π₯β1 + ln 2
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WB 8 Show that 2 7 2 4π₯β3 ππ₯ = ln 5 2 7 2 4π₯β3 ππ₯ = 1 4 2 ln 4π₯β3 7 2
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Skills 212 homework 212
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WB 9 Find the following integral π₯β5 π₯+1 π₯β2 ππ₯
Let x = 2 Let x = -1
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WB 10a Find the following integral π₯ 2 β3π₯+2 9 π₯ 2 β4 ππ₯ by rearranging to the form π+ π΄ 3π₯+2 + π΅ 3π₯β2
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Find the following integral:
WB 10b Find the following integral: =π₯ ln 3π₯β2 3π₯ πΆ
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WB 11a Find the following integral 3 π₯ 2 +4π₯β11 (π₯β2) (π₯+1) 2 ππ₯ by rearranging to partial fractions
3 π₯ 2 +4π₯β11 (π₯β2) (π₯+1) 2 = π΄ π₯β2 + π΅ π₯+1 + πΆ (π₯+1) 2 =π΄( π₯ π΅ π₯β2 π₯+1 +πΆ(π₯β2) π₯=2 gives 9A= solves to π΄=1 π₯=β1 gives -3C= solves to C=4 π₯=0 gives A-2B-2C=-11 solves to B=2 3 π₯ 2 +4π₯β11 (π₯β2) (π₯+1) 2 = 1 π₯β2 + 2 π₯ (π₯+1) 2
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= 1 π₯β2 + 2 π₯+1 + 4 (π₯+1) 2 ππ₯ = ln π₯β2 +2 ln π₯+1 β4 π₯+1 β1 +C
WB 11b Find the following integral π₯ 2 +4π₯β11 (π₯β2) (π₯+1) 2 ππ₯ by rearranging to partial fractions = π₯β2 + 2 π₯ (π₯+1) 2 ππ₯ A knotty integral! βKNOTβ a logarithm term = ln π₯β2 +2 ln π₯+1 β4 π₯+1 β1 +C
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WB 12 Show that 5 6 3π₯+2 (π₯+3)(π₯β4) ππ₯= ln 9 2
3π₯+2 (π₯+3)(π₯β4) = β¦= 1 π₯ π₯β4 5 6 3π₯+2 (π₯+3)(π₯β4) ππ₯ = π₯ π₯β4 dx = ln π₯ ln π₯β = ln 9 +2 ln 2 β ln ln 1 = ln 9 + ln 4 β ln 8 = ln 9Γ = ln 9 2
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WB 13 Show that π 2 π 4 5π₯β4 π₯ 2 βπ₯ ππ₯=8+ln π 4 β1 π 2 β1
5π₯β4 π₯ 2 βπ₯ = β¦= 4 π₯ + 1 π₯β1 π 2 π π₯β4 π₯ 2 βπ₯ ππ₯ = π 2 π π₯ + 1 π₯β1 ππ₯ = 4 ln π₯ + ln π₯β π 4 π 2 = 4 ln π 4 + ln π 4 β1 β 4 ln π ln (π 2 β1) = 16 + ln π 4 β1 β8 β ln (π 2 β1) = 8+ln π 4 β1 π 2 β1
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= 1 π₯β2 + 2 π₯+1 + 4 (π₯+1) 2 ππ₯ = ln π₯β2 +2 ln π₯+1 β4 π₯+1 β1 6 3
WB Show that π₯+2 (π₯+3)(π₯β4) ππ₯= ln β by rearranging to partial fractions From WB11 earlier = π₯β2 + 2 π₯ (π₯+1) 2 ππ₯ = ln π₯β2 +2 ln π₯+1 β4 π₯+1 β = ln 4 +2 ln 7 β 4 7 β ln 1 +2 ln 4 β 4 4 = ln 4 +2 ln 7 β 4 7 β0β2 ln 4 β1 = 2 ln 7 β ln 4 β = ln β QED
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Skills 213 homework 213
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KUS objectives BAT Find integrals using rule for log functions
BAT Solve problems where partial factions used with this rule; self-assess One thing learned is β One thing to improve is β
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WB 15 Integrate the following:
WB Integrate the following: Start by trying y = ln|denominator| Differentiate This is double what we want so multiply the βguessβ by 1/2
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