Download presentation
Presentation is loading. Please wait.
1
HW #8 due Thursday, Nov 4 at 11:59 p.m.
Recitation Quiz #8 tomorrow Last Time: Center of Gravity, Equilibrium Problems Today: Moment of Inertia, Torque and Angular Acceleration B. Plaster is in contact this week. Send with any questions and/or concerns. His office hours are cancelled this week.
2
Recall: The See-Saw m Q: Suppose our familiar see-saw is initially perfectly balanced (not rotating). You place a mass m on one end. What happens ? A: We know that the see-saw rotates about the pivot, due to the torque of the weight mg about the center ! Summary: The see-saw initially had an angular speed of zero. The torque caused the see-saw to acquire some non-zero angular speed. A change in the angular speed means there was an angular acceleration. The torque caused an angular acceleration.
3
Torque and Angular Acceleration
An object of mass m connected to a massless rod of length r is rotating horizontally. A tangential force Ft acts perpendicular to the rod, causing a tangential acceleration (i.e., an increase in the angular speed and tangential velocity). By Newton’s Second Law: 1 4 But Ft∙r is the torque ! Multiply by r : 2 α is proportional to τ 3 Recall: at = rα Proportionality constant mr2 called “moment of inertia”
4
Torque and Angular Acceleration
Consider a RIGID rotating disc. Think of the disc as made up of a LARGE number of particles, with mass m1, m2, m3, etc. Suppose the disc is undergoing an angular acceleration α. Disc is rigid All of these masses are undergoing the same acceleration α. The net torque on the disc is: Moment of Inertia Define: [ Analog to ΣF = ma !! ]
5
Rotational vs. Linear Dynamics
For a given net force: For a given net torque: The larger the mass m, the smaller the magnitude of a (“inertia”). The larger the moment of inertia I, the smaller the magnitude of α (“rotational inertia”).
6
Moments of Inertia Moment of inertia of a single object rotating about some axis is: m r : distance from axis of rotation r [ SI: kg-m2 ] For a composite object (made up of many masses): Key difference between ΣF = ma and Στ = Iα : In ΣF = ma, m does not depend on how the mass is distributed. m DOES NOT change depending on its location. In Στ = Iα, I DOES depend on how the mass is distributed I depends on the distance of each mass from the rotation axis.
7
Example Consider a baton to be made up of a 1.0-m long massless rod, with two 1.0-kg masses at both ends. 1.0 kg 1.0 kg Suppose it rotates about an axis through its center. 0.5 m 0.5 m (a) Calculate the baton’s mass of inertia. (b) Suppose a constant torque of 1.0 N-m is applied to the baton. What is its angular acceleration α ? (c) If the baton starts from rest (ωi = 0 rad/s), what is its angular speed ω after t = 2 s ? (d) Suppose, instead, the baton was shorter, but the torque was the same. Would ω at t = 2 s be larger or smaller ?
8
“Extended” Objects For an “extended” solid object, such as a sphere, calculus techniques are used to calculate the object’s moment of inertia. (take PHY 231, 404, …) R One simple example (which doesn’t require calculus) … Consider a solid hoop of mass M and radius R. Think of it as being made up of many small masses m1, m2, m3, …, with M = Σm. The moment of inertia due to all of these masses is: R m1 m2 m3
9
“Extended” Objects Moments of inertia for some common “extended” objects : Table 8.1 of your textbook Don’t worry, you don’t need to “memorize” these formulas … But you need to know how to apply/use them !
10
Example A solid cylinder with radius m rotates on a frictionless, vertical axle. A constant tangential force of 250 N applied to its edge causes an angular acceleration of rad/s2. (a) What is the moment of inertia ? (b) What is the mass ? (c) If the cylinder starts from rest, what is the angular speed after 5.00 s have elapsed (assuming the force is acting the entire time) ?
11
Example F A 150-kg merry-go-round in the shape of a uniform, solid, horizontal disc of radius 1.50-m is set spinning by wrapping a rope about the rim of the disc, and pulling on the rope. 1.5 m What constant force must be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.5 rev/s in a time of 2.0 s ?
12
Next Class 8.6 : Rotational Kinetic Energy
+ The “Race of the Shapes” !!
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.