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Chapter 5 Chemical Reactions and Quantities

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1 Chapter 5 Chemical Reactions and Quantities
5.2 Chemical Equations

2 Chemical Equations A chemical equation gives the chemical formulas of the reactants on the left of the arrow and the products on the right. Reactants Product O2 (g) CO2 (g) C(s)

3 Symbols Used in Equations
Symbols used in chemical equations show the states of the reactants. the states of the products. the reaction conditions. TABLE 5.2

4 Chemical Equations are Balanced
In a balanced chemical reaction atoms are not gained or lost. the number of reactant atoms is equal to the number of product atoms.

5 A Balanced Chemical Equation
In a balanced chemical equation, there must be the same number of each type of atom on the reactant side and on the product side of a balanced equation. numbers called coefficients are used in front of one or more formulas. Al S  Al2S Not Balanced 2Al S  Al2S3 Balanced 2 Al = Al 3 S = S

6 Learning Check State the number of atoms of each element on the
reactant side and the product side for each of the following balanced equations. A. P4(s) Br2(l)  4 PBr3(g) B. 2Al(s) Fe2O3(s)  2Fe(s) Al2O3(s)

7 Solution A. P4(s) + 6Br2(l)  4 PBr3(g) 4 P 4 P 12 Br 12 Br
B. 2Al(s) Fe2O3(s)  2Fe(s) Al2O3(s) 2 Al 2 Al 2 Fe Fe 3 O 3 O

8 Learning Check Determine if each equation is balanced or not.
A. Na(s) N2(g)  Na3N(s) B. C2H4(g) H2O(l)  C2H5OH(l)

9 Solution Determine if each equation is balanced or not.
A. Na(s) N2(g)  Na3N(s) No. 2 N on reactant side, 1 N on product side. 1 Na on reactant side, 3 Na on product side. B. C2H4(g) H2O(l)  C2H5OH(l) Yes. 2 C = 2 C 6 H = 6 H 1 O = 1 O

10 Guide to Balancing a Chemical Equation
Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings

11 Steps in Balancing an Equation
To balance the following equation, Fe3O4(s) H2(g)  Fe(s) H2O(l) work on one element at a time. use only coefficients in front of formulas. do not change any subscripts. Fe: Fe3O4(s) H2(g)  3Fe(s) H2O(l) O: Fe3O4(s) + H2(g)  3Fe(s) H2O(l) H: Fe3O4(s) + 4H2(g)  3Fe(s) H2O(l)

12 Balancing Chemical Equations
1. Write the equation with the correct formulas. NH3(g) O2(g)  NO(g) H2O(g) 2. Determine if the equation is balanced. No, not all atoms are balanced. 3. Balance with coefficients in front of formulas. 4NH3(g) O2(g)  4NO(g) H2O(g) 4. Check that atoms of each element are equal in reactants and products. 4 N (4 x 1 N) = N (4 x 1 N) 12 H (4 x 3 H) = 12 H (6 x 2 H) 10 O (5 x 2 O) = 10 O (4 O + 6 O)

13 Equation for A Chemical Reaction

14 Checking a Balanced Equation
Reactants Products 1 C atom = 1 C atom 4 H atoms = 4 H atoms 4 O atoms = 4 O atoms

15 Learning Check Check the balance of atoms in the following.
Fe3O4(s) H2(g)  3Fe(s) H2O(l) A. Number of H atoms in products. 1) 2 2) 4 3) 8 B. Number of O atoms in reactants. C. Number of Fe atoms in reactants. 1) 1 2) 3 3) 4

16 Solution Fe3O4(s) + 4H2(g)  3Fe(s) + 4H2O(l)
A. Number of H atoms in products. 3) 8 (4H2O) B. Number of O atoms in reactants. 2) 4 (Fe3O4) C. Number of Fe atoms in reactants. 2) 3 (Fe3O4)

17 Learning Check Balance each equation and list the coefficients in the balanced equation going from reactants to products: A. __Mg(s) + __N2(g)  __Mg3N2(s) 1) 1, 3, ) 3, 1, ) 3, 1, 1 B. __Al(s) + __Cl2(g)  __AlCl3(s) 1) 3, 3, 2 2) 1, 3, ) 2, 3, 2

18 Solution A. 3) 3, 1, 1 3Mg(s) + 1N2(g)  1Mg3N2(s) B. 3) 2, 3, 2
2Al(s) Cl2(g)  2AlCl3(s)

19 Equations with Polyatomic Ions

20 Balancing with Polyatomic Ions
MgCl2(aq) + Na3PO4(aq)  NaCl(aq) + Mg3(PO4)2(s) Balance PO43- as a unit MgCl2(aq) + 2Na3PO4(aq)  NaCl(aq) + Mg3(PO4)2(s) 2 PO = PO43- Balance Mg and Cl 3MgCl2(aq) + 2Na3PO4(aq)  6NaCl(aq) + Mg3(PO4)2(s) 3 Mg = Mg2+ 6 Na = Na+ 6 Cl = Cl-

21 Learning Check Balance and list the coefficients from reactants to products. A. __Fe2O3(s) __C(s)  __Fe(s) __CO2(g) 1) 2, 3, 2, ) 2, 3, 4, ) 1, 1, 2, 3 B. __Al(s) + __FeO(s)  __Fe(s) __Al2O3(s) 1) 2, 3, 3, ) 2, 1, 1, ) 3, 3, 3, 1 C. __Al(s) + __H2SO4(aq)  __Al2(SO4)3(aq) + __H2(g) 1) 3, 2, 1, ) 2, 3, 1, ) 2, 3, 2, 3

22 Solution A. 2) 2, 3, 4, 3 2Fe2O3(s) + 3C(s)  4Fe(s) + 3CO2(g)
B. 1) 2, 3, 3, 1 2Al(s) + 3FeO(s)  3Fe(s) + 1Al2O3(s) C. 2) 2, 3, 1, 3 2Al(s) + 3H2SO4(aq)  1Al2(SO4)3(aq) + 3H2(g)


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