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Published byBeatrix Craig Modified over 6 years ago
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As lithography continues to shrink, the problem of driving
Min L NMOS transistor As lithography continues to shrink, the problem of driving Large currents increases.
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For Current Drivers Large Cascaded Transistors are needed
Such circuits require large amounts of chip area and have slow Signal transition time. Example: Driving a milliamp With 50 microamp CMOS Area=30 transistors Delay=11 gates Current= 1 mA 50 135 369 1000 Staging Delay The number of stages necessary and minimum delay in driving a current Il, when the minimum transistor size has a current drive Im can be computed from the capacitance of the gate of the minimum transistor size Cm. If a single stage is used, the delay will be proportional to: Im[(Il/ Im)(Cm)]= Il Cm as compared to the minimum delay proportional to Im Cm. If a number of stages N is used, and the loading factor of each is constant, then the delay will be proportional to: Taking the derivative of this quantity with respect to N and setting it to zero to minimize the delay, the number of stages is: This implies that each stage should be a factor of e (2.718) larger than the previous stage and the delay associated with driving a large current is 2.718*N times larger than the minimum delay of the MOS gate. These stages can add up to an unacceptable delay in providing large amplitude current signals.
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Ovonic Threshold Switches can withstand well over
KDF2009-2B devices 800 angstrom diameter 2.9X108 A/cm2 Device Failure Ovonic Threshold Switches can withstand well over 100 million Amperes per square centimeter. Two orders of Magnitude higher than Bipolar silicon devices.
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Using this device in conjunction with normal CMOS
Area= 8 transistors Delay=1-2 gates Current > 10mA 1/3 area , 1/5 delay, 10 X current
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Timing Signals for OTS Driver Circuit
time time time
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