1. Squaring a Number- Speed Maths

2. Square of no. ending with 5
A quick way to square numbers that end in 5 using the formula.
BY ONE MORE THAN THE ONE BEFORE. 75^2 = ^2 means 75 x 75. The answer is in two parts: 56 and The last part is always 25. The first part is the first number, 7, multiplied by the number “one more”, which is 8: so 7 x 8 = 56

3. First figures are the same and the last figures add up to 10
Method for multiplying numbers where the first figures are the same and the last figures add up to 10.
32 x 38 = Both numbers here start with 3 and the last figures (2 and 8) add up to 10. So we just multiply 3 by 4 (the next number up) to get 12 for the first part of the answer. And we multiply the last figures: 2 x 8 = 16 to get the last part of the answer.

4. Squares of no from 26 to 75
There are lots of method– but i will discuss only one which is applicable to all & the easiest one.
For numbers close to 50 i.e. for numbers from 30 to 75: Here we find the surplus (or deficit) of the number from 50, denoted by x in the following expression and then use the following to find the square. (50 + x)^2 = 25 + x | x^2 The answer is arrived at in two parts, separated by ‘|’ in the above expression. The right hand part of the answer has to be exactly two digits. Any extra digit has to be carried forwarded to the left hand part. And if the right hand part is a single digit, it has to be superseded with 0. E.g. 51^2 = (50 + 1)^2 = | 1^2 = 26 | 01 = ^2 = (50 + 9)2 = | 9^2 = 3481

5. Numbers close to 100 i.e. for numbers from 75 to 130
Expression and then use the following to find the square. (100 + x)^2 = x | x^2 The answer is arrived at in two parts, separated by ‘|’ in the above expression. The right hand part of the answer has to be exactly two digits. Any extra digit has to be carried forwarded to the left hand part. And if the right hand part is a single digit, it has to be superseded with E.g. 103^2 = ( )^2 = x 3 | 3^2 = 106 | 09 = ^2 = ( )^2 = x 8 | 8^2 = 116 | 64 = ^2 = ( )^2 = 128 | 196 = 12996

6. Numbers close to 200 i.e. for numbers from 175 to 230
Expression and then use the following to find the square. (100 + x)^2 = ( x)*2 | x^2
The answer is arrived at in two parts, separated by ‘|’ in the above expression. The right hand part of the answer has to be exactly two digits. Any extra digit has to be carried forwarded to the left hand part. And if the right hand part is a single digit, it has to be superseded with e.g. 203^2 = ( )^2 = ( x 3)*2 | 32 = 412 | 09 = 41209

7. Numbers close to 300 i.e. for numbers from 275 to 330:
Expression and then use the following to find the square. (300 + x)^2 = ( x)*3 | x^2
The answer is arrived at in two parts, separated by ‘|’ in the above expression. The right hand part of the answer has to be exactly two digits. Any extra digit has to be carried forwarded to the left hand part. And if the right hand part is a single digit, it has to be superseded with E.g. 303^2 = ( )^2 = ( x 3 )*3| 3^2 = 918 | 09 = 91809

8. For a base of 1000,2000,3000 & so on Last part must be 3 digit no.
For a base of 10000,20000,30000 & so on— last part must be 4 digit no.; & so on.

9. Thank you!