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Lesson 8.3 Pythagorean Theorem pp. 323-327.

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Presentation on theme: "Lesson 8.3 Pythagorean Theorem pp. 323-327."— Presentation transcript:

1 Lesson 8.3 Pythagorean Theorem pp

2 Objectives: 1. To prove the Pythagorean theorem.
2. To apply the Pythagorean theorem to right triangles. 3. To develop a formula for the area of an equilateral triangle.

3 Theorem 8.7 Pythagorean Theorem. In a right triangle, the sum of the squares of the length of the legs is equal to the square of the length of the hypotenuse: a2 + b2 = c2.

4 The Pythagorean Theorem can also be thought of as
leg2 + leg2 = hypotenuse2

5 The following illustrates the Pythagorean theorem.

6 b a c

7 b a c Area of large square: A = (a+b)2 Area of small square: A = c2
Area of triangle: A = ½ab

8 b a c Area of large square = Area of small square + 4 x Area of triangle.

9 b a c (a+b)2 = c2 + 4(½ab) a2 + 2ab + b2 = c2 + 2ab a2 + b2 = c2

10 The converse of the Pythagorean theorem is also true
The converse of the Pythagorean theorem is also true. If the sum of the squares of the lengths of two sides of a triangle equals the square of the length of the third side, then the triangle is a right triangle.

11 Theorem 8.8 The area of an equilateral triangle is
times the square of the length of one side: A = s2 4 3

12 A D B C s h ½s h2 + (½s)2 = s2 h2 + ¼s2 = s2 4h2 + s2 = 4s2 4h2 = 3s2 h2 = ¾s2 h = s 3 2

13 A D B C s h A = ½bh s 3 2 A = 1 (s) s2 3 4 A =

14 EXAMPLE Find the area of equilateral LMN.
A = s2 3 4 L M N 7 cm A = 72 3 4 A = sq. cm 49 3 4

15 Practice: A screen door measures 36 in. by 80 in
Practice: A screen door measures 36 in. by 80 in. Find the length of a diagonal brace for the screen door. 80 in. 36 in. c = c2 7,696 = c2 c ≈ 87.7 in.

16 Homework pp

17 85 5 13 2 x2 + 25 ►A. Exercises a(units) b(units) c(units) 1. 3 5
Complete the table. Consider ABC to be a right triangle with c as the hypotenuse. a(units) b(units) c(units) 3. 9 2 5. 2 3 7. 6 4 9. x 5 4 85 5 13 2 x2 + 25

18 x2 + 25 ►A. Exercises a(units) b(units) c(units) 1. 3 5 3. 9 2 5. 2 3
Complete the table. Consider ABC to be a right triangle with c as the hypotenuse. a(units) b(units) c(units) 3. 9 2 5. 2 3 7. 6 4 9. x 5 4 85 or 9.2 5 or 2.2 52 or 7.2 x2 + 25

19 Tell which of the following triangles are right triangles. 11.
►A. Exercises Tell which of the following triangles are right triangles. 11.  92 9 6 8

20 Tell which of the following triangles are right triangles. 13.
►A. Exercises Tell which of the following triangles are right triangles. 13. = 292 20 21 29

21 ►B. Exercises Find each area. 15. A right triangle has a leg measuring 5 inches and a hypotenuse measuring 8 inches. 5 8

22 ►B. Exercises 17. Find the area. 15 12 5

23 ►B. Exercises 19. Find the area. 5

24 ►B. Exercises 21. The bases of an isosceles trapezoid are 6 inches and inches. Find the area if the congruent sides are 5 inches. 6 12 5

25 ►B. Exercises 22. The perimeter of a rhombus is 52 and one diagonal is 24. Find the area. 24 13

26 ►B. Exercises 22. The perimeter of a rhombus is 52 and one diagonal is 24. Find the area. 12 5 13

27 ►B. Exercises 22. The perimeter of a rhombus is 52 and one diagonal is 24. Find the area. A = ½d1d2 = ½(10)(24) = 120 24 10 13

28 ■ Cumulative Review Find the area of each rectangle. 29. 7 3

29 ■ Cumulative Review Find the area of each rectangle. 30. 7 4

30 ■ Cumulative Review 31. Give bounds for c if b  5. c b 7

31 ■ Cumulative Review 32. The consecutive sides of a rectangle have a ratio 4:5. If the area is 5120 m2, what are the dimensions of the rectangle?

32 ■ Cumulative Review 33. The figure is made up of 8 congruent squares and has a total area of cm2. Find the perimeter.

33 Analytic Geometry Heron’s Formula

34 Definition The semiperimeter of a triangle is one-half the perimeter of a triangle: s . 2 c b a + =

35 Heron’s Formula If ABC has sides of lengths a, b, and c and semiperimeter s, then the area of the triangle is A = s(s - a)(s - b)(s - c) .

36 Find the area of a triangle with sides 9, 10, and 15.
2 15 10 9 s + = 17 =

37 Find the area of a triangle with sides 9, 10, and 15.
A = s(s – a)(s – b)(s – c) = 17(17 – 9)(17 – 10)(17 – 15) = 17(8)(7)(2) = ≈ 43.6 sq. units

38 ►Exercises 1. 3 units, 8 units, 9 units
Find the area of each triangle that has the given side measures. Round you answers to the nearest tenth. 1. 3 units, 8 units, 9 units

39 ►Exercises 2. 6 units, 18 units, 21 units
Find the area of each triangle that has the given side measures. Round you answers to the nearest tenth. 2. 6 units, 18 units, 21 units

40 ►Exercises 3. 27 units, 13 units, 18 units
Find the area of each triangle that has the given side measures. Round you answers to the nearest tenth. 3. 27 units, 13 units, 18 units


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