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Section 9.4 Day 1 Solving Quadratic Equations by Completing the Square
Algebra 1
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Complete the square to write a perfect square trinomial
Convert standard form to vertex form by completing the square Solve a quadratic equation by using the square root property Solve a quadratic equation by completing the square Learning Targets
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Completing the Square Procedure
1. Determine π & π 2. Find πΆ= π 2π 2 3. Write π 2π 2 on both sides of the equation 4. Rewrite into π₯+ π 2π 2 Completing the Square Procedure
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Completing the Square β Example 1
Find the value of π that makes π₯ 2 +4π₯+π a perfect square trinomial 1. π=1, π=4, π=? 2. π 2 = =2 and π = 2 2 =4 3. Rewrite: π₯+2 2 = π₯ 2 +4π₯+4 4. π=4 Completing the Square β Example 1
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Completing the Square β Example 2
Find the value of π that makes π 2 β8π+π a perfect square trinomial 1. π 2 = β 8 2 =β4 and π =(β 4) 2 =16 2. π=16 3. π 2 β8π+16= πβ4 2 Completing the Square β Example 2
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Standard to Vertex Form β Example 1
Convert π¦= π₯ 2 β6π₯+12 into vertex form 1. Complete the square: π = β3 2 =9 2. Add the number to both sides π¦+9= π₯ 2 β6π₯+9+12 3. Group: π¦+9= π₯β 4. Simplify: π¦= π₯β Standard to Vertex Form β Example 1
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Standard to Vertex Form β Example 2
Convert π¦= π₯ 2 β12π₯+3 into vertex form 1. Complete the square: π = β6 2 =36 2. Add the number to both sides π¦+36= π₯ 2 β12π₯+36+3 3. Group together: π¦+36= π₯β 4. Simplify: π¦= π₯β6 2 β33 Standard to Vertex Form β Example 2
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Solving using the Square Root Property β Example 1
Solve π₯ 2 =16 1. Take the square root of each side 2. π₯=Β± 16 3. π₯=Β±4 Key Note: The symbol does not represent taking the square root. It represents the positive square root. Solving using the Square Root Property β Example 1
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Solving using the Square Root Property β Example 2
Solve π₯β6 2 =81 1. Take the square root of both sides π₯β6=Β± 81 2. Simplify and solve: π₯β6=Β±9 π₯β6= and π₯β6=β9 π₯=15 and π₯=β3 Solving using the Square Root Property β Example 2
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Solving using the Square Root Property β Example 3
Solve π₯+3 2 =25 π₯+3=Β± 25 π₯+3=Β±5 π₯+3= and π₯+3=β5 π₯=2 and π₯=β8 Solving using the Square Root Property β Example 3
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Solving by Completing the Square β Example 1
Solve π₯ 2 β12π₯+3=16 by completing the square. 1. Complete the square: π = β6 2 =36 2. Add to both sides π₯ 2 β12π₯+36+3=16+36 3. Group: π₯β =52 4. Solve: π₯β6 2 =49 5. π₯β6=Β±7 6. π₯=13 and π₯=β1 Solving by Completing the Square β Example 1
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Solving by Completing the Square β Example 2
Solve π₯ 2 +6π₯+5=12 by completing the square 1. Complete the square: π = =9 2. Add to both sides π₯ 2 +6π₯+9+5=12+9 π₯ =21 3. Solve: π₯+3 2 =16 π₯+3=Β±4 π₯=1 and π₯=β7 Solving by Completing the Square β Example 2
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