Download presentation
Presentation is loading. Please wait.
1
Standard Reduction (Half-Cell) Potentials
Cell EMF Standard Reduction (Half-Cell) Potentials Consider Zn(s) Zn2+(aq) + 2e-. We measure Ecell relative to the SHE (cathode): Ecell = Ered(cathode) + Eox (anode) 0.76 V = 0 V + Eox(anode). Therefore, Eox(anode) = V. Standard reduction potentials must be written as reduction reactions: Zn2+(aq) + 2e- Zn(s), Ered = V.
2
2Zn2+(aq) + 4e- 2Zn(s), Ered = -0.76 V.
Since Ered = V we conclude that the reduction of Zn2+ in the presence of the SHE is not spontaneous. The oxidation of Zn with the SHE is spontaneous. Changing the stoichiometric coefficient does not affect Ered. Therefore, 2Zn2+(aq) + 4e- 2Zn(s), Ered = V. Reactions with Ered > 0 are spontaneous reductions relative to the SHE.
3
Reactions with Ered < 0 are spontaneous oxidations relative to the SHE.
The larger the difference between Ered values, the larger Ecell. In a voltaic (galvanic) cell (spontaneous) Ered(cathode) is more positive than Ered(anode). Recall
4
Examples – Balance the following equations, and calculate E°cell for each:
Cr3+ + Cl2 (g) Cr2O72- + Cl- Cu2+ + Mg (s) Mg2+ + Cu (s) IO3- + Fe2+ Fe3+ + I2 Zn (s) + Ag+ Zn2+ + Ag
5
Oxidizing and Reducing Agents
The more positive Ered the stronger the oxidizing agent on the left. The more negative Ered the stronger the reducing agent on the right. A species on the higher to the left of the table of standard reduction potentials will spontaneously oxidize a species that is lower to the right in the table. That is, F2 will oxidize H2 or Li; Ni2+ will oxidize Al(s).
7
Spontaneity of Redox Reactions
In a voltaic (galvanic) cell (spontaneous) Ered(cathode) is more positive than Ered(anode) since Or More generally, for any electrochemical process A positive E indicates a spontaneous process (galvanic cell). A negative E indicates a nonspontaneous process.
8
Examples – Sketch the cells containing the following reactions
Examples – Sketch the cells containing the following reactions. Include E°cell, the direction of electron flow, direction of ion migration through salt bridge, and identify the anode and cathode: Cr3+ + Cl2 (g) Cr2O72- + Cl- Cu2+ + Mg (s) Mg2+ + Cu (s) IO3- + Fe2+ Fe3+ + I2
9
EMF and Free-Energy Change
We can show that G is the change in free-energy, n is the number of moles of electrons transferred, F is Faraday’s constant, and E is the emf of the cell. We define Since n and F are positive, if G > 0 then E < 0.
10
Examples – Balance, and calculate E°cell and ΔG° for each reaction:
Mg (s) + Au3+ Mg2+ + Au (s) Al (s) + Ag+ Al3+ + Ag (s) Cu2+ + Na (s) Cu (s) + Na+
11
Cell EMF and Chemical Equilibrium
A system is at equilibrium when G = 0. From the Nernst equation, at equilibrium and 298 K (E = 0 V and Q = Keq):
12
Batteries A battery is a self-contained electrochemical power source with one or more voltaic cell. When the cells are connected in series, greater emfs can be achieved.
13
Cathode: PbO2 on a metal grid in sulfuric acid:
Lead-Acid Battery A 12 V car battery consists of 6 cathode/anode pairs each producing 2 V. Cathode: PbO2 on a metal grid in sulfuric acid: PbO2(s) + SO42-(aq) + 4H+(aq) + 2e- PbSO4(s) + 2H2O(l) Anode: Pb: Pb(s) + SO42-(aq) PbSO4(s) + 2e-
15
The overall electrochemical reaction is
PbO2(s) + Pb(s) + 2SO42-(aq) + 4H+(aq) 2PbSO4(s) + 2H2O(l) for which Ecell = Ered(cathode) + Eox (anode) = ( V) + (0.356 V) = V. Wood or glass-fiber spacers are used to prevent the electrodes from touching.
16
2NH4+(aq) + 2MnO2(s) + 2e- Mn2O3(s) + 2NH3(aq) + 2H2O(l)
Alkaline Battery Anode: Zn cap: Zn(s) Zn2+(aq) + 2e- Cathode: MnO2, NH4Cl and C paste: 2NH4+(aq) + 2MnO2(s) + 2e- Mn2O3(s) + 2NH3(aq) + 2H2O(l) The graphite rod in the center is an inert cathode. For an alkaline battery, NH4Cl is replaced with KOH.
17
Anode: Zn powder mixed in a gel:
Zn(s) Zn2+(aq) + 2e- Cathode: reduction of MnO2.
19
Direct production of electricity from fuels occurs in a fuel cell.
Fuel Cells Direct production of electricity from fuels occurs in a fuel cell. On Apollo moon flights, the H2-O2 fuel cell was the primary source of electricity. Cathode: reduction of oxygen: 2H2O(l) + O2(g) + 4e- 4OH-(aq) Anode: 2H2(g) + 4OH-(aq) 4H2O(l) + 4e-
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.