1. Unit 4. Day 5.

2. Please get out paper for today’s lesson
Name
Date
Period
Topic: Continue Slope … meet intercepts
Understand the connections between proportional relationships, lines, and linear equations.

3. Q: Which variable is independent?𝑥 𝑦= 𝑥
Q: What is slope?
The steepness of a line
𝑚= 𝑟𝑖𝑠𝑒 𝑟𝑢𝑛
Q: How do we measure slope?
Q: What is the x-intercept?
Point where the graph crosses the x-axis
Q: What is the y-intercept?
Point where the graph crosses the y-axis
Q: What is the relationship between the linear equation and the slope of the line/y-intercept? A:
This is the point of today’s lesson

4. Example A: 𝑦=−2𝑥+4 𝑟𝑖𝑠𝑒 −6 𝑚= =−2 𝑟𝑢𝑛 3 𝑥 𝑦 𝑦=−2 +4 𝑦=−2 +4 𝑦= +4 𝑦= 6
𝑥−𝑖𝑛𝑡: , 2
𝑦=−
𝑦=−
𝑦−𝑖𝑛𝑡: , 4 𝑦= +4 𝑦= 6
+ 4
𝑦=4 4 𝑥
𝑦=10 10 𝑥 𝑦 −3 −3
𝑦=− 𝑦= −4
+ 4 2 2
𝑦=0

5. Example B: 𝑦= 2 3 𝑥+6 = 2 3 𝑟𝑖𝑠𝑒 4 𝑚= 𝑟𝑢𝑛 6 𝑥 𝑦 𝑦= +6 𝑦= −2 + 6 𝑦=6 6𝑦= 𝑦=
𝑥−𝑖𝑛𝑡: , −9
𝑦−𝑖𝑛𝑡: , 6 𝑦= +6 𝑦= −2
+ 6
𝑦=6 6 𝑥
𝑦=4 4 𝑥 𝑦 𝑦= −3 −3 𝑦= 2 +6 3 3
𝑦=8 8

6. Example C: 4𝑦+3𝑥=24 24 −3𝑥 −3𝑥 −3𝑥 −3 =− 3 4 𝑟𝑖𝑠𝑒 𝑚= + 𝑟𝑢𝑛 4 4𝑦 ∙ = 4
𝑦=− 3 4 𝑥+6
−3𝑥
−3𝑥
−3𝑥 −3
=− 3 4
𝑟𝑖𝑠𝑒 𝑚= +
𝑟𝑢𝑛 4 4𝑦 ∙ = 4 4
𝑥−𝑖𝑛𝑡: , 8
𝑦=−
𝑦−𝑖𝑛𝑡: , 6 𝑦= 9 3
+ 6 𝑥
𝑦=− 𝑥 𝑦 𝑦= 6 −4
+ 6 −4
𝑦=− 4 4 𝑦= 3 −3
+ 6

7. 1) A) B) C) 4𝑦+3𝑥=24 𝑦=− 3 4 𝑥+6 𝑥−𝑖𝑛𝑡 𝑦−𝑖𝑛𝑡 𝑦= 1 4 𝑥+2 𝑚= 1 4 −8 ,0
0 ,2
𝑚= −2 1 A)
𝑦=−2𝑥+4
2 ,0
0 ,4
𝑦= 2 3 𝑥+6
𝑚= 2 3
−9 ,0
0 ,6 B)
𝑚=− 3 4 C)
4𝑦+3𝑥=24
8 ,0
0 ,6
𝑦=− 3 4 𝑥+6
𝑚:𝑠𝑙𝑜𝑝𝑒 𝑦= 𝑚𝑥
+ 𝑏
𝑦−𝑖𝑛𝑡:(0, 𝑏)

8. 𝑦
Example D:
𝑦=− 1 3 𝑥+2
− 1 3 2 𝑚= 𝑥
𝑥−𝑖𝑛𝑡: , 6
𝑦−𝑖𝑛𝑡: ,

9. 𝑦
Example E:
𝑦=4𝑥−8 −8
4 1 𝑚= 𝑥
𝑥−𝑖𝑛𝑡: , 2
𝑦−𝑖𝑛𝑡: ,

10. Today’s Assignment: Graph, find slope, find intercepts
𝑦=3𝑥−4
𝑦= 1 2 𝑥+5
2𝑦−5𝑥=8
−3𝑦+7𝑥=9
St. Francis in Ecstasy (1480)