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Chapter 19 Gas Stoichiometry
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A chemist collects 23. 6g of an unknown gas from the air
A chemist collects 23.6g of an unknown gas from the air. It occupies a volume of 12.0 L at standard temperature and pressure. What common gas do you think the chemist has collected?
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 119g KBr
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 119g KBr 2 mol KBr
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 119g KBr 2 mol KBr 1 mol Br2
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 1000 cm3 119g KBr 2 mol KBr 1 mol Br2 1 dm3
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If an excess of chlorine gas reacts with a solution containing 20
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm3 of bromine gas can be produced at STP? 2KBr + Cl2 → Br2 + 2KCl 20.0g KBr mol KBr 1 mol Br2 22.4 dm3 1000 cm3 119g KBr 2 mol KBr 1 mol Br2 1 dm3 = 1880 cm3
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In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3
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In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2
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In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 22.4 dm3
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In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 22.4 dm3 3 mol O2
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In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 27.0 g 22.4 dm3 3 mol O2 mol Al
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In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm3 of oxygen at STP? 4Al + 3O2 → 2Al2O3 5.00 dm3 O2 mol O2 4 mol Al 27.0 g = 8.04 g 22.4 dm3 3 mol O2 mol Al
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How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl
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H2 + Cl2 → 2HCl This is a volume – volume calculation.
How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations. 50.0 cm3 HCl
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H2 + Cl2 → 2HCl This is a volume – volume calculation.
How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP? H2 + Cl2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations. 1 cm3 Cl2 50.0 cm3 HCl = 25.0 cm3 2 cm3 HCl
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Homework Worksheet: Ideal Gas Equation (due tomorrow).
Worksheet: Gas Stoichiometry (due in two days). Lab Summary: “Molecular Mass of a Gas” (due in two days). Study Guide Chapter 19 (due in two days). Gas Laws Lab (due today).
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