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The Multivariate Normal Distribution, Part 2
BMTRY 726 5/22/2018
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More Properties of MVN Last lecture we discussed:
The form of the MVN distribution Contours of constant density obtained by taking a slice of the MVN distribution as some set height Some of the properties of the MVN distribution Impact of linear combinations of X Partitions of X Conditions for Independence of vectors in X We will continue this discussion with some additional useful properties
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Conditional Distributions
Result 4.6: Suppose Then the conditional distribution of X1 given that X2 = x2 is a normal distribution Note the covariance matrix does not depend on the value of x2
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Proof of Result 4.6
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Proof of Result 4.6
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Proof of Result 4.6
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Example Consider Find the conditional distribution of the 1st and 3rd components
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Example
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Example
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Results 4.6 & Multiple Regression
Consider The conditional distribution of Y|X=x is univariate normal with
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Result 4.7: If and S is positive definite, then
Proof:
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Result 4.7: If and S is positive definite, then
Proof cont’d:
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Result 4.8: If are mutually independent with
And c1, c2, …,cn are n constants. Then Additionally if we have and which are r x p matrices of constants we can also say
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Sample Data Let’s say that X1, X2, …, Xn are i.i.d. random vectors
If the data vectors are sampled from a MVN distribution then
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Multivariate Normal Likelihood
We can also look at the joint likelihood of our random sample
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Some needed Results (1) Given A > 0 and are eigenvalues of A (a)
(b) (c) (2) From (c) we can show that:
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Some needed Results (2) Proof that:
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Some needed Results (2) Proof that:
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Some needed Results (2) Proof that:
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Some needed Results (1) Given A > 0 and are eigenvalues of A (a)
(b) (c) (2) From (c) we can show that: (3) Given Spxp > 0, Bpxp > 0 and scalar b > 0
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MLE’s for
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MLE’s for
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MLE’s for
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MLE’s for
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A Few Notes About The MLE’s for Variance
As in the univariate setting, the MLE for the variance matrix is biased Thus we generally use an alternative to the MLE…
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Sampling Distributions
So we’ve discussed that we can estimate the mean vector, m, and the covariance matrix, S, using and S But we need to understand how these are distributed..
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Sample Mean Vector We can estimate a sample mean for X1, X2, …, Xn
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Sample Mean Vector Now we can estimate the mean of our sample
But what about the properties of ? It is an unbiased estimate of the mean It is a sufficient statistic Also, the sampling distribution is:
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Sample Covariance And the sample covariance for X1, X2, …, Xn
Sample variance Sample Covariance
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Sample Mean Vector So we can also estimate the variance of our sample
And like , S also has some nice properties It is an unbiased estimate of the variance It is also a sufficient statistic It is also independent of But what about the sampling distribution of S?
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Wishart Distribution Given , the distribution of is called a Wishart distribution with n degrees of freedom. has a Wishart distribution with n -1 degrees of freedom The density function is where A and S are positive definite
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Wishart cont’d The Wishart distribution is the multivariate analog of the central chi-squared distribution. If are independent then If then CAC’ is distributed The distribution of the (i, i) element of A is
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Large Sample Behavior Let X1, X2, …, Xn be a random sample from a population with mean and variance (not necessarily normally distributed) Then and S are consistent estimators for m and S. This means
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Large Sample Behavior If we have a random sample X1, X2, …, Xn a population with mean and variance, we can apply the multivariate central limit theorem as well The multivariate CLT says
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Next Time Checking Normality
How can we check MVN and what do we do if our data don’t appear MVN? SAS and R Begin our discussion of statistical inference for MV vectors
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