Presentation is loading. Please wait.

Presentation is loading. Please wait.

HKN ECE 310 Exam Review Session

Similar presentations


Presentation on theme: "HKN ECE 310 Exam Review Session"β€” Presentation transcript:

1 HKN ECE 310 Exam Review Session
Corey Snyder Steven Chan Ningdong Wang

2 Topics LSIC Systems and BIBO Stability
Impulse Response and Convolution Z-Transform DTFT and Frequency Response

3 LSIC Systems Linearity Shift Invariance Causality
Satisfy Homogeneity and Additivity Can be summarized by Superposition If π‘₯ 1 𝑛 β†’ 𝑦 1 𝑛 and π‘₯ 2 𝑛 β†’ 𝑦 2 𝑛 , then π‘Ž π‘₯ 1 𝑛 +𝑏 π‘₯ 2 𝑛 β†’π‘Ž 𝑦 1 𝑛 +𝑏 𝑦 2 [𝑛] Shift Invariance If π‘₯ 𝑛 →𝑦 𝑛 , then π‘₯ π‘›βˆ’ 𝑛 0 →𝑦 π‘›βˆ’ 𝑛 0 βˆ€ 𝑛 0 and π‘₯[𝑛] Causality Output cannot depend on future input values

4 BIBO Stability Three ways to check for BIBO Stability:
Pole-Zero Plot (more on this later) Absolute summability of the impulse response Given π‘₯ 𝑛 < Ξ±, 𝑖𝑓 𝑦 𝑛 < Ξ²< ∞, then the system is BIBO stable A bounded input π‘₯[𝑛] yields a bounded output 𝑦[𝑛] Ex: 𝑦 𝑛 = π‘₯ 5 𝑛 +3 vs. 𝑦 𝑛 =π‘₯ 𝑛 βˆ—π‘’[𝑛] Absolute Summability 𝑛=βˆ’βˆž ∞ β„Ž 𝑛 < ∞

5 Impulse Response 𝑦 𝑛 =π‘₯ 𝑛 βˆ—β„Ž[𝑛] System output to an π‘₯ 𝑛 =𝛿[𝑛] input
β„Ž[𝑛] is the impulse response System output to an π‘₯ 𝑛 =𝛿[𝑛] input β„Ž 𝑛 =𝛿 𝑛 βˆ—β„Ž[𝑛] π‘Œ 𝑧 =𝐻 𝑧 𝑋(𝑧) Convolution in the time/sample domain is multiplication in the transformed domain, both the z-domain and frequency domain.

6 Convolution 𝑦 𝑛 = π‘š=βˆ’βˆž ∞ π‘₯ π‘š β„Ž π‘›βˆ’π‘š = π‘š=βˆ’βˆž ∞ β„Ž π‘š π‘₯ π‘›βˆ’π‘š System must be:
𝑦 𝑛 = π‘š=βˆ’βˆž ∞ π‘₯ π‘š β„Ž π‘›βˆ’π‘š = π‘š=βˆ’βˆž ∞ β„Ž π‘š π‘₯ π‘›βˆ’π‘š System must be: Linear Shift Invariant If π‘₯ is of length 𝐿 and β„Ž is of length 𝑀, 𝑦 must be of length 𝐿+π‘€βˆ’1. Popularly done graphically Can also be done algebraically

7 Z-Transform 𝑋 𝑧 = 𝑛=βˆ’βˆž ∞ π‘₯[𝑛] 𝑧 βˆ’π‘›
𝑋 𝑧 = 𝑛=βˆ’βˆž ∞ π‘₯[𝑛] 𝑧 βˆ’π‘› Typically perform inverse z-transform by inspection or by Partial Fraction Decomposition Important properties: Multiplication by n: 𝑛π‘₯ 𝑛 β†”βˆ’π‘§( 𝑑𝑋 𝑧 𝑑𝑧 ) Delay Property #1: 𝑦 π‘›βˆ’π‘˜ 𝑒 π‘›βˆ’π‘˜ ↔ 𝑧 βˆ’π‘˜ π‘Œ(𝑧) Make sure to note the Region of Convergence (ROC) for your transforms! More in the next slide! DTFT is only defined if the ROC contains the unit circle

8 BIBO Stability Revisited: Pole-Zero Plots
For an LSI system: if the ROC contains the unit circle, this system is BIBO stable The ROC is anything greater than the outermost pole if the system/signal is causal or β€œright-handed” The ROC is anything less than the innermost pole if the system/signal is anti-causal or β€œleft-handed” If we sum multiple signals, the ROC is the intersection of each signal’s ROC What if the ROC is 𝑧 >1 or 𝑧 <1? This is marginally stable, but unstable for ECE 310 purposes For unstable systems, you are commonly asked to find a bounded input that yields an unbounded output. Few ways to do this: Pick an input that excites the poles of the system. If the system’s impulse response β„Ž[𝑛] is not absolutely summable, u[𝑛] will work 𝛿 𝑛 frequently works too, like when β„Ž[𝑛] is unbounded, e.g. β„Ž 𝑛 = 2 𝑛 𝑒[𝑛]

9 Discrete Time Fourier Transform
𝑋 𝑑 πœ” = 𝑛=βˆ’βˆž ∞ π‘₯[𝑛] 𝑒 βˆ’π‘—πœ”π‘› π‘₯ 𝑛 = 1 2πœ‹ βˆ’πœ‹ πœ‹ 𝑋 𝑑 πœ” 𝑒 π‘—πœ”π‘› π‘‘πœ” Important Properties: Periodicity! Linearity Symmetries (Magnitude, angle, real part, imaginary part) Time shift and modulation Product of signals and convolution Parseval’s Relation Know your geometric series sums!

10 Frequency Response For any stable LSI system: 𝐻 𝑑 Ο‰ =𝐻(𝑧) | 𝑧= 𝑒 𝑗ω
What is the physical interpretation of this? The DTFT is simply the z-transform evaluated along the unit circle! It makes sense that the system must be stable and LSI since the ROC will contain the unit circle, thus ensuring that the DTFT is well defined Why is the frequency response nice to use in addition to the z-transform? 𝑒 𝑗ω is an eigenfunction of LSI systems β„Ž 𝑛 βˆ—π΄ 𝑒 𝑗 πœ” 0 =πœ†π΄ 𝑒 𝑗 πœ” 0 =𝐴 𝐻 𝑑 πœ” 0 𝑒 𝑗 πœ” 0 By extension for real-valued systems: π‘₯ 𝑛 = cos (Ο‰ 0 𝑛+πœƒ) →𝑦 𝑛 =| 𝐻 𝑑 Ο‰ 0 | cos (Ο‰ 0 𝑛+πœƒ+∠ 𝐻 𝑑 ( Ο‰ 0 ))

11 Magnitude and Phase Response
Very similar to ECE 210 Frequency response, and all DTFTs for that matter, are 2πœ‹ periodic Magnitude response is fairly straightforward Take the magnitude of the frequency response, remembering that |𝑒 𝑗ω | = 1 For phase response: Phase is β€œcontained” in 𝑒 𝑗ω terms Remember that cosine and sine introduce sign changes in the phase Limit your domain from βˆ’πœ‹ to πœ‹. For real-valued systems: Magnitude response is even-symmetric Phase response is odd-symmetric

12 LSIC Examples For the following systems, determine whether it is linear, shift-invariant, causal and stable 𝑦 𝑛 =𝑦 𝑛+1 +π‘₯[ 𝑛 ] 𝑦 𝑛 = 3 sin π‘₯ 𝑛 π‘₯ 0 𝑦 𝑛 = 3 βˆ’ 𝑛 log π‘₯ 𝑛 +1

13 Impulse Response and Convolution Examples
Given π‘₯ 𝑛 =[6 ,12, βˆ’3, 0, 15, 3, βˆ’9, 0] and β„Ž 𝑛 = 1 3 , 1 3 , 1 3 , compute the system output. What does this filter do? Suppose we have a digital filter β„Ž[𝑛] with an unknown impulse response. We do know the system output to the follow two input signals. Determine the impulse response in terms of the two system outputs. π‘₯ 1 𝑛 = 2, 4, 2, 4 β†’ 𝑦 1 𝑛 π‘₯ 2 𝑛 = 0, 2, 1, 2 β†’ 𝑦 2 𝑛

14 BIBO Stability Example
Suppose we have a system response given by 𝐻 𝑧 = 1 1+ 𝑧 βˆ’2 . Which of the following bounded inputs would cause this system to have an unbounded output? cos πœ‹ 2 𝑛 𝛿[𝑛] 𝑒[𝑛] 𝑒 𝑗 πœ‹ 2 𝑛 𝑒[𝑛]


Download ppt "HKN ECE 310 Exam Review Session"

Similar presentations


Ads by Google