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Warm-Up Find the inverse of each function. f(x) = x + 10 g(x) = 3x
10.2 Logarithmic Functions Find the inverse of each function. f(x) = x + 10 g(x) = 3x h(x) = 5x + 3 j(x) = ¼x + 2
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Logarithmic Functions
Write equivalent forms for exponential and logarithmic equations. Use the definitions of exponential and logarithmic functions to solve equations.
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Rules and Properties Equivalent Exponential and Logarithmic Forms
10.2 Logarithmic Functions Rules and Properties Equivalent Exponential and Logarithmic Forms For any positive base b, where b 1: bx = y if and only if x = logb y. Exponential form Logarithmic form
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Example 1 a) Write 27 = 128 in logarithmic form. log2 128 = 7
6.3 Logarithmic Functions a) Write 27 = 128 in logarithmic form. log2 128 = 7 b) Write log = 4 in exponential form. 64 = 1296
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Example 2 a. Solve x = log2 8 for x. 2x = 8 x = 3 b. logx 25 = 2
6.3 Logarithmic Functions a. Solve x = log2 8 for x. 2x = 8 x = 3 b. logx 25 = 2 x2 = 25 x = 5
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Practice c. Solve log2 x = 4 for x. 24 = x x = 16
6.3 Logarithmic Functions c. Solve log2 x = 4 for x. 24 = x x = 16
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Example 3 6.3 Logarithmic Functions a. Solve 10x = for x. Round your answer to the nearest tenth. log = x x = 1.161
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Rules and Properties One-to-One Property of Exponential Functions
6.3 Logarithmic Functions One-to-One Property of Exponential Functions If bx = by, then x = y.
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Example 4 Find the value of the variable in each equation:
6.3 Logarithmic Functions Find the value of the variable in each equation: a) log2 1 = r b) log7 D= 3 2r = 1 73 = D 20 = 1 D = 343 r = 0
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Practice Find the value of the variable in each equation:
6.3 Logarithmic Functions Find the value of the variable in each equation: 1) log4 64 = v 2) logv 25 = 2 3) 6 = log3 v
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Practice Solve each equation for x. Round your answers to the nearest hundredth. 1) 10x = 1.498 2) 10x = Find the value of x in each equation. 3) x = log4 1 4) ½ = log9 x
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Properties of Logarithmic Functions
Objectives: Simplify and evaluate expressions involving logarithms Solve equations involving logarithms
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Properties of Logarithms
For m > 0, n > 0, b > 0, and b 1: Product Property logb (mn) = logb m + logb n
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Example 1 given: log5 12 1.5440 log5 10 1.4307 log5 120 =
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Properties of Logarithms
For m > 0, n > 0, b > 0, and b 1: Quotient Property logb = logb m – logb n m n
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Example 2 given: log5 12 1.5440 log5 10 1.4307 12 log5 1.2 = log5
–
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Properties of Logarithms
For m > 0, n > 0, b > 0, and any real number p: Power Property logb mp = p logb m
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Example 3 given: log5 12 1.5440 log5 10 1.4307 log5 1254
53 = 125 = 4 3 x = 3 = 12
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Practice Write each expression as a single logarithm.
1) log2 14 – log2 7 2) log3 x + log3 4 – log3 2 3) 7 log3 y – 4 log3 x
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4 minutes Warm-Up Write each expression as a single logarithm. Then simplify, if possible. 1) log6 6 + log6 30 – log6 5 2) log6 5x + 3(log6 x – log6 y)
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Properties of Logarithms
For b > 0 and b 1: Exponential-Logarithmic Inverse Property logb bx = x and b logbx = x for x > 0
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Example 1 Evaluate each expression. a) b)
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Practice Evaluate each expression. 1) 7log711 – log3 81
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Properties of Logarithms
For b > 0 and b 1: One-to-One Property of Logarithms If logb x = logb y, then x = y
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Example 2 Solve log2(2x2 + 8x – 11) = log2(2x + 9) for x.
2x2 + 8x – 11 = 2x + 9 2x2 + 6x – 20 = 0 2(x2 + 3x – 10) = 0 2(x – 2)(x + 5) = 0 x = -5,2 Check: log2(2x2 + 8x – 11) = log2(2x + 9) log2 (–1) = log2 (-1) undefined log2 13 = log2 13 true
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Practice Solve for x. 1) log5 (3x2 – 1) = log5 2x
2) logb (x2 – 2) + 2 logb 6 = logb 6x
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Exponential Growth and Decay
Objectives: Determine the multiplier for exponential growth and decay Write and evaluate exponential expressions to model growth and decay situations
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Modeling Bacteria Growth
Time (hr) 1 2 3 4 5 6 Population 25 50 100 200 400 800 1600 Write an algebraic expression that represents the population of bacteria after n hours. The expression is called an exponential expression because the exponent, n is a variable and the base, 2, is a fixed number. The base of an exponential expression is commonly referred to as the multiplier.
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Example 1 Find the multiplier for each rate of exponential growth or decay. a) 9% growth 100% + 9% = 109% = 1.09 b) 0.08% growth 100% + 0.08% = % = c) 2% decay 100% - 2% = 98% = 0.98 d) 8.2% decay 100% - 8.2% = 91.8% = 0.918
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Example 2 Suppose that you invested $1000 in a company’s stock at the end of 1999 and that the value of the stock increased at a rate of about 15% per year. Predict the value of the stock, to the nearest cent, at the end of the years 2004 and 2009. Since the value of the stock is increasing at a rate of 15%, the multiplier will be 115%, or 1.15 = $ = $
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Example 3 Suppose that you buy a car for $15,000 and that its value decreases at a rate of about 8% per year. Predict the value of the car after 4 years and after 7 years. Since the value of the car is decreasing at a rate of 8%, the multiplier will be 92%, or 0.92 = $10,745.89 = $8,367.70
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Practice A vitamin is eliminated from the bloodstream at a rate of about 20% per hour. The vitamin reaches a peak level in the bloodstream of 300 mg. Predict the amount, to the nearest tenth of a milligram, of the vitamin remaining 2 hours after the peak level and 7 hours after the peak level.
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