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Solubility Lesson 8 Review Notes.

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Presentation on theme: "Solubility Lesson 8 Review Notes."— Presentation transcript:

1 Solubility Lesson 8 Review Notes

2 Adding a Solid to a Saturated Solution
Consider the saturated solution- the rate of crystallizing equals the rate of dissolving More solid AgCl is added The solution is full so the ion concentrations remain constant Ag+ Cl- The rate of dissolving and rate of crystallizing both increase by the same amount.

3 Describe the change in each of the following when more solid AgCl is added to a saturated solution.
Constant 1. [Ag+] 2. [Cl-] Constant Cl- Ag+ 3. Rate of dissolving Increases 4. Rate of crystallizing Increases

4 5. The ions in hard water are Mg2+ and Ca2+
Na2CO3 can be added to water to remove these ions

5 6. Calculate the total ion concentration of 1.0 M AlCl3
AlCl3  Al Cl- 1.0 M 1.0 M 3.0 M Total 4.0 M

6 7. What is the molar solubility of CaC2O4?
Ksp = s2 2.3 x = s2 4.8 x M

7 8. The solubility is 7.1 x 10-5 M. The compound is:
A. CaSO4 Ksp = s2 = x 10-9 B. CaCO3

8 9. A solution of AgNO3 is added slowly to each of the following 0.10 M solutions. Which forms a precipitate first? A. NaCl ksp = x B. NaIO3 ksp = x 10-8

9 10. Small amounts of AgNO3 are added to three solutions. One solution
a precipitate, which one is it? does not form A. NaCl ksp = x B. NaIO3 ksp = x 10-8 C. NaBr ksp = x

10 11. Which solution has the greatest conductivity?
A. 1.0 M NaCl B. 1.0 M CaCO3 D. 1.0 M CaCl2 1.0 M M = M C. 1.0 M AlCl3  Al Cl-  Ca Cl- 1.0 M M = M

11 12. Calculate the maximum number of grams BaCl2 that will dissolve in
0.50 L of 0.20 M AgNO3 solution. AgCl(s) ⇄ Ag Cl- 0.20 M Ksp = [Ag+][Cl-] 1.8 x = [0.20][Cl-] [Cl-] = x M BaCl2(s) ⇄ Ba Cl- 4.5 x M 9.0 x M 0.50 L x x mole x g = x g 1 L 1 mole


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