1. Chapter 12 Geometry
Homework Answers

2. Sec 12.1
0.1405
11.57
30.86
62.08
sin A = s/t, cos A = r/t, tan A = s/r
sin θ = ⅘, cos θ = ⅗, tan θ = 4/3
sin A = 7/25, cos A = 24/25, tan A = 7/24, sin B = 24/25, cos B = 7/25, tan B = 24/7
30°
53°
24°
a≈ 35 cm
b ≈ 15 cm
c ≈ 105 yd
d ≈ 40°
e ≈ 50 cm
f ≈ 33°
g ≈ 18 in.
≈ 237 m
x ≈ 121

3. Sec 12.2
≈ 655 m °
≈ 101 m °
≈ 65 m °
≈ 188 m a ; b. 2.05; c ; d
≈ 227 m x = 3.5, y = 9 1/7 ≈ 9.14
a. ≈ 974 m
b. ≈ 1007 m
c. Yes, the height of the balloon would be 1 m less because you don’t have to account for the tripod. The distance to a point under the balloon would not change.
≈ 1621 m
9 cm
64°
7 cm
2 m
22 in.
49°
127°
30°
64 cm

4. Sec 12.3 329 cm² 4 cm² 11,839 cm² 407 cm² 35 cm 17 cm 30 cm 56° 45°
66°
a. ≈ 2200 m
b. ≈ 1600 m
c. ≈ 1400 m
The other two walls were 300 ft and approximately 413 ft. The area was approximately 45,000 ft².
≈ 48 m
2366 cm; ≈ 41° 5°
(9π√3)/8 cm³ or approximately 6 cm³
AC = 60 cm, AE = cm, AF ≈ 117 cm
Box 1

5. Sec 12.4 32 cm 47 cm 341 cm 74° 64° 85° ≈ 43 cm ≈ 30° ≈ 116° and 64°
≈ 6 min
≈ 143 m
a. decreases
b. increases then decreases

6. Sec 12.5 ≈ 12.7 m ≈ 142 mi/hr ≈ 51 km ≈ 5.9 m a. ≈ 9.1 km b. 255°
≈ 42 ft
They must dig at an angle of between 71° and 72° and dig for at least 25 m.

7. Ch 12 Review
0.8387
0.9877
sin A = a/b, cos A = c/b, tan A = a/c
sin B = 8/17, cos B = 15/17, tan B = 8/15
sin φ = s, cos φ = t, tan φ = s/t
33°
86°
71°
1823 cm²
15,116 cm³
approximately 52 km
approximately 7.3°
approximately 22 ft
approximately m
393 cm²

8. Ch 12 Review cont’d 30 cm 78° 105 cm 51° 759 cm² approximately 25 cm
approximately 10.1 km/hr at an approximate bearing of 24.5°