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Le Châtelier’s Principle
When a system is at equilibrium: If any stress is placed on the system, equilibrium will shift to overcome the stress. Stressors can be: Adding products Adding reactants Changing temperature Etc.
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Le Châtelier’s Principle
To predict the shift, look at which side has gained something from the initial stress. The reaction shifts to the side opposite the side that gained from the stress.
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Le Châtelier’s Principle
How do you predict changes? After the change, determine which side has more substance. The reaction shifts to the opposite side.
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Le Châtelier’s Principle
To shift a reaction to the reactant side (): Add products Remove reactants If exothermic: Raise temperature If endothermic: Lower temperature
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Le Châtelier’s Principle
To shift a reaction to the product side (): Add reactants Remove products If endothermic: Raise temperature If exothermic: Lower temperature
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Le Châtelier’s Principle
2SO2(g) + O2(g) ⇄ 2SO3(g) ∆H = -198 kJ Predict how this reaction shifts when the following variables are changed: Add O2 Add SO3 Raise the temperature Shifts to the products Shifts to the reactants
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Special Note about Temperature Changes
Temperature changes also affect Keq values. If a temperature change shifts the equilibrium to the right (), then Keq will INCREASE. If a temperature change shifts the equilibrium to the left (), then Keq will DECREASE.
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Le Châtelier’s Principle
Special Scenario for gases: If pressure increases, the equilibrium shifts to the side with less total moles of gas. If pressure decreases, the equilibrium shifts to the side with more total moles of gas.
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Adding a Catalyst No affect on equilibrium
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Le Châtelier’s Principle
2SO2(g) + O2(g) ⇄ 2SO3(g) ∆H = -198 kJ Predict how this reaction shifts when the following variables are changed: Cool down the system Increase the pressure Remove SO3 Shifts to the products Shifts to the products Shifts to the products
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Review 2SO2(g) + O2(g) ⇄ 2SO3(g) ∆H = -198 kJ
How does the reaction shift when: SO2 is added The temperature is raised The volume is increased A catalyst is added Shifts to the products Shifts to the reactants Shifts to the reactants No effect
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Predicting Shift At Non-Equilibrium Conditions
If concentrations are not at equilibrium, the equilibrium constant is labeled as Q. Compare the Kc value to the Q value to predict shift: If Kc > Q, the equilibrium shifts to the product side. If Kc < Q, the equilibrium shifts to the reactant side. If Kc = Q, the system is at equilibrium.
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Q & A The reaction 2A + B ⇄ 3C has an equilibrium constant value of Kc = If you add the following solutions to a flask, which way will the reaction shift to reach equilibrium? [A] = M [B] = M [C] = M [C]3 Q = [A]2 [B] [0.200 M]3 Q = [0.100 M]2 [0.200 M] Q = 4.00 Because Kc > Q, the reaction shifts to the products side.
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More Q &A H2(g) + F2(g) ⇄ 2 HF(g) Kc = 115
What is the value of Kc for the reverse reaction? If the equation was written as 2H2(g) + 2F2(g) ⇄ 4 HF(g) what would the value of Kc be? [HF]2 [H2] [F2] 1 If 115 = Then = = 8.70 10-3 [H2] [F2] [HF]2 115 [HF]2 [HF]4 If 115 = Then = (115)2 = 13200 [H2] [F2] [H2]2 [F2]2
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