1. The steps in determining empirical formula

2. The steps in performing this process
Step One- Divide by the mass
Step Two- Divide by the lowest numbers of mols
Step Three-
Decimal Formed After Simplifying
Multiplier
Whole Number Formed .5 2 1
.25 4
.75 3
.33
.99 or 1
.66
1.98 or 2

3. Multiplier is 2 based on the 2.5
Analysis of a g sample of a compound known to contain only phosphorus and oxygen indicates a phosphorus content of a 4.433g. What is the empirical formula of this compound. ( =5.717 gr)
Step # gr P gr O
Step # mols mols
Step #3 1 atom P atom O
(X 2) P2O (X 2)
Multiplier is 2 based on the 2.5

4. Step #3 2 atom Na 1 atom S 3 atoms O
A compound is found to contain 36.48% Na, 25.41% S, and 38.11% O. Find its empirical formula.
Step # gr Na gr S gr O
Step # mols mols mols
Step #3 2 atom Na atom S atoms O
Na2SO3
There are no multipliers

5. Multiplier is 2 based on the 1.501
Find the empirical formula of a compound that contains 53.70% iron and 46.30% sulfur.
Step # gr Fe gr S
Step # mols mols
Step #3 1 atom Fe atom S
(X 2) Fe2S (X 2)
Multiplier is 2 based on the 1.501

6. No multipliers!!!!!!!!!! Step #1 8.83 gr Na 6.17 gr S 22.9897 32.066
A 15.0g sample of a compound is found to contain 8.83g sodium and 6.17g sulfur. Calculate the empirical formula of this compound.
Step # gr Na gr S
Step # mols mols
Step #3 2 atoms Na 1 atom S
Na2S
No multipliers!!!!!!!!!!

7. FeS There is no multiplier Step #1 63.52 gr Fe 36.48 gr S
A compound is found to contain 63.52% iron and 36.48% sulfur. Find its empirical formula.
Step # gr Fe gr S
Step # mols mols
Step #3 1 atom Fe atom S
FeS
There is no multiplier

8. Step #3 1.989 atom Na 1 atom S 3.97 atoms O
Qualitative analysis shows that a compound contains 32.38% sodium, 22.65% sulfur, and 44.99% oxygen. Find the empirical formula of this compound.
Step # gr Na gr S gr O
Step # mols mols mols
Step # atom Na 1 atom S atoms O
Na2SO4
There are no multipliers

9. Step #3 1 atom K 1 atom Cr 3.49 atoms O
Find the empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium and the remainder oxygen. ( =38.03% O)
Step # gr K gr Cr gr O
Step # mols mols mols
Step #3 1 atom K atom Cr atoms O
K2Cr2O7
The multiplier for 3.5 is 2. K-1X2, Cr 1X2 and Cr 3.5 X2

10. A 60.00g sample of tetraethyl lead, a gasoline additive, is found to contain 38.43g lead, 17.83g carbon, and 3.74g hydrogen. Find its empirical formula.
Step # gr Pb gr C gr H
Step # mols mols mols
Step #3
1 atom Pb atom C atoms H
PbC8H20

11. CaBr2 There is no multiplier Step #1 4.0 gr Ca 16.00 gr Br
Analysis of a 20.0g sample of a compound containing only calcium and bromine indicates that 4.00g of calcium are present. What is the empirical formula of the compound formed? ( =16.0 gr Br).
Step # gr Ca gr Br
Step # mols mols
Step #3 1 atom Ca atom Br
CaBr2
There is no multiplier

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