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Real Oscillators … constant forces  integrate EOM  parabolic trajectories. … linear restoring force  guess EOM solution  SHM … nonlinear restoring.

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Presentation on theme: "Real Oscillators … constant forces  integrate EOM  parabolic trajectories. … linear restoring force  guess EOM solution  SHM … nonlinear restoring."— Presentation transcript:

1 Real Oscillators … constant forces  integrate EOM  parabolic trajectories. … linear restoring force  guess EOM solution  SHM … nonlinear restoring forces  ? linear spring nonlinear spring? F F x x

2 WTF! The spring of air : use Ideal Gas Law: PV=NRT Patm
chamber volume: V=Ax WTF! (whoa there, fella) m EOM A +x Stable Equilibrium at xeq = NRT / (mg + APatm) P, V

3 Taylor Series Expansions:
Turns a function into a polynomial near x = a Example:

4 Expand around x = -3: 2nd order 0th order 1st order

5 Expand around x = 2: 0th order 1st order 2nd order

6 Expand NRT/x around xeq:
Is it safe to linearize it? Better check a unitless ratio. How about: (Yes, excellent choice Dr. Hafner!)

7 .. Displacement 5% of xeq: 0 .05 .0025 …. Perhaps you would prefer….
SHM with

8 Beware of assumptions and approximations!

9 Clerk = person who derived an approximation
Clouseau = You Clerk = person who derived an approximation Dog = domain of interest Clerk’s dog = domain of his approximation Bite = result of mistaken assumption that you are working within the Clerk’s domain

10 Simple Pendulum: Stable Equilibrium: Length: L Mass: m Q
Displace by Q: mg cosQ T mg cosQ sinQ -x mg cosQ EOM: mg Expand it! mg

11 Derivatives:

12 Now express as a unitless ratio of the dependent variable and some parameter of the system:
Displacement 5% of length: … SHM with

13 The world is not linear. However, one can use a Taylor expansion to linearize an EOM by assuming only small perturbations around a point of stable equilibrium (which may not be the origin).


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