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Mole Relations in Chemical Equations

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Presentation on theme: "Mole Relations in Chemical Equations"— Presentation transcript:

1 Mole Relations in Chemical Equations
Students will learn how to predict the mass of products expected in a chemical reaction

2 Review: Finding the moles from the grams
7.0 grams Na2SO4 = __________ moles 30.0 grams KMnO4 = __________ moles 17.0 grams PCl3= __________ moles

3 Review: Finding the grams from the moles
1.5 mole NaCl = __________ grams .0165 mole K2SO4 = _________ grams 1.25 mole Cu(NO3)2 = ________ grams

4 Hydrogen and Oxygen React. How much water will be produced?
The reaction between hydrogen and oxygen can be read a couple different ways. 2H2 + O2  2H2O Two molecules of hydrogen react with one molecule of oxygen Two moles of hydrogen react with one mole of oxygen

5 N2 + 3H2  2NH3

6 2H2 + O2  2H2O How many moles of oxygen do you need in the examples below? 12 mol of hydrogen ____________ 25 mol of hydrogen ____________

7 Balance the equation (NH4)2Cr2O7  Cr2O3 + N2 + H2O
So this means that: 1.00 mole (NH4)2Cr2O7 produces ___ mole H2O 0.50 mole (NH4)2Cr2O7 produces ___ mole H2O

8 Video Click here for video

9 Calculations (NH4)2Cr2O7  Cr2O3 + N2 + 4H2O 25.2 g ↓ g g g
252 g/mol g/mol g/mol g/mol (NH4)2Cr2O7  Cr2O N H2O 25.2 g ↓ g g g mole mol mol mol

10 H2O2  H2O + O2 34 g/mol 18 g/mol 32 g/mol H2O2  H2O + O2 68 grams
mol mol mol

11 Fe + Cl2  FeCl3 55.8g/mol 71.0 g/mol 162.3 g/mol Fe + Cl2  FeCl3
3.0 ____ _____ ____ ____ _____


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