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Solution Concentration (Molarity) Topic 1.5
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Solutions Solutions are homogenous mixtures formed when one substance disperses completely into another. Solvent: substance in the solution found in a greater amount Solute: substance dissolved into the solvent
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Parts of a Solution solute – the part of a solution that is being dissolved (usually the lesser amount) solvent – the part of a solution that dissolves the solute (usually the greater amount) solution = solute + solvent Solute Solvent Solution Si Al metal alloy salt water salt water CO2 carbonated water O N air
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Saturation and Solubility
Terminology: 1. Dissolving: the process of surrounding solute particles with solvent particles. 2. Crystallization: The process of solute particles attaching to each other
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Saturation Saturated: a solution in equilibrium with undissolved solute. Unsaturated: less solute is dissolved than is required for a saturated solution. Supersaturated: more solute is dissolved than needed for a saturated solution. Only possible under the right environmental conditions
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Solutions and Stoichiometry
Many times the reactants and/or products of chemical reactions are aqueous solutions. In these cases the concentration of the solution must be determined in order to determine amounts of reactants or products The concentration of a solution is a measure of the amount of solute that is dissolved in a given amount of solution *
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Units of Concentration
Parts per million (ppm): grams of solute per million grams of solution Typically used for expressing acceptable amounts of toxic substances in the environment Mass/volume ratio (density): Mole/unit of solvent ratio (molarity, molality, mole fraction)
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Molarity The most common concentration unit is Molarity Molarity (M) =
Moles of solute dm3 of solution *
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Molarity = Molarity moles solute dm3 of solution
The number of moles of solute dissolved in cubic decimeters of solution Molarity = moles solute dm3 of solution
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1. 0 dm3 of water was used to make 1. 0 dm3 of solution
1.0 dm3 of water was used to make 1.0 dm3 of solution. Notice the water left over dm3 of water would be too much.
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Making a known molar solution
top off to 1 liter
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What is the concentration of 2 moles of HCl in 4 dm3?
2 mol / 4 dm3 = 0.5 M
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Step 1: Calculate moles of NiCl2• 6H2O in 5 g of NiCl2• 6H2O
PROBLEM: Dissolve 5.00 g of NiCl2•6 H2O in enough water to make 250 mL of solution. Calculate the Molarity. Step 1: Calculate moles of NiCl2• 6H2O in 5 g of NiCl2• 6H2O 1.0 L = 1000 mL .25 L = 250 mL Step 2: Calculate Molarity
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M = moles/V moles = M•V USING MOLARITY
What mass of oxalic acid, H2C2O4, is required to make 250 mL of a M solution? M = moles/V moles = M•V Step 1: Change mL to L. 250 mL/1000 = L Step 2: Calculate. moles = ( M) (0.250 L) = moles H2C2O4 Step 3: Convert moles to grams. ( mol H2C2O4) (90.00 g) = g 1 mol H2C2O4
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Learning Check How many grams of NaOH are required to prepare 400 mL of 3.0 M NaOH solution? 1) 12 g 2) 48 g 3) 300 g
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Molarity Calculations
How many grams of NaOH are required to prepare 250 cm3 of M solution? Molar Mass of NaOH = = 40.0 g/mol 250 cm3 = dm3 (0.500 mol) x (40.0 g) x (0.250 dm3 ) = 5.00 g ( dm ) x ( mol ) *
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Molarity Calculations
Calculate the concentration of a NaCl solution that contains 24.5 g of NaCl in 250 cm3 of solution. Molar mass of NaCl = = 58.5 (24.5 g NaCl) X 1 = 1.67 M (58.5 g mol-1 ) (0.250 dm3 ) *
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Stoichiometry Calculations Involving Solutions 1
15.0 cm3 of a M AgNO3 solution is required to precipitate the sodium chloride in 10 cm3 of a salt solution. What is the concentration of the solution? AgNO3 (aq) + NaCl (aq) →AgCl (s) +KNO3 (aq) Molar Mass NaCl = = 58.5 g/mol 0.500 mol AgNO3 X dm3 x 1 mol NaCl X 58.5 g mol NaCl dm3 1 mol AgNO3 = g of NaCl 0.439 g of NaCl x 58.5 g mol dm3 = mol dm-3 or 0.75 M *
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Stoichiometry Calculations Involving Solutions 2
Copper metal reacts with nitric acid according to the following reaction: 8 HNO3 (aq) Cu → 3 Cu(NO3)2 (aq) H2O (l) NO (g) What volume of M HNO3 would be required to consume a copper penny whose mass is 3.08 grams? (3.08 g Cu ) (8 mol HNO3) (1 dm3) ( 1000 cm3) (63.55 g mol-1 Cu ) (3 mol Cu) = 16.2 cm3 *
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Molality which is mass/volume
grams/liters or IB says g dm-3 What is the concentration of 15 g of NaCl dissolved in 500 ml of water 15g/.5L = 30 g dm-3
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