Find: Lightest I Beam fy=50,000 [lb/in2] unfactored axial

Find: Lightest I Beam fy=50,000 [lb/in2] unfactored axial
tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 Find the lightest I beam. [pause] In this problem, an I beam is subjected to a given dead load, and, --- assume yield failure

tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 live load, which is an axial force, in tension. The yield strength --- assume yield failure

tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 of the steel is provided, and the problem states to assume the I beam will experience --- assume yield failure

tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 a yield failure. [pause] Looking ahead, we’ll first observe our 4 choices --- assume yield failure

tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 of I beams to choose from. We’ll use I beam W 8 by --- assume yield failure

Find: Lightest I Beam fy=50,000 [lb/in2] assume yield failure
unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 58 as an example. Here, the W stands for --- W 8 x 58

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 wide flange, which means this type of I beam will have an increased section modulus, --- wide flange W 8 x 58

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 area moment of inertia, and other paramers related to section geometry. First number after --- wide flange W 8 x 58

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 the W represents the depth of the beam, in inches, which is the distance from the top of the top flange, --- wide flange W 8 x 58 depth [in]

Find: Lightest I Beam fy=50,000 [lb/in2] assume yield failure depth
unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 to the bottom of the bottom flange. And the last number represents ---- wide flange W 8 x 58 depth [in]

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 linear the weight per length, of the beam, in pounds per foot. Therefore, --- wide flange weight [lb/ft] W 8 x 58 depth [in]

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 linear the linear weight of the 4 possible I beams to choose from ranges from --- wide flange weight [lb/ft] W 8 x 58 depth [in]

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 linear 58 pounds per foot, to 68 pounds per foot. Since we’re trying to find --- wide flange weight [lb/ft] W 8 x 58 depth [in]

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 linear the lightest I beam. We’ll choose the beam with the smallest linear weight, which can withstand --- wide flange weight [lb/ft] W 8 x 58 depth [in]

unfactored axial tensile loads: DL=600,000 [lb] LL = 60,000 [lb] A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 linear the axial loading provided in the problem statement. [pause] Using LRFD, the maximum factored load, --- wide flange weight [lb/ft] W 8 x 58 depth [in]

Find: Lightest I Beam γ * Q ≤ φ * R DL=600,000 [lb] LL = 60,000 [lb]
yield failure A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 gamma Q, shall not exceed the design strength of the steel member, ---

Find: Lightest I Beam γ * Q ≤ φ * R DL=600,000 [lb] LL = 60,000 [lb]
factored design load strength yield failure A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 phi R. [pause] The maximum factored tensile load upon the member, ---

Find: Lightest I Beam γ * Q ≤ φ * R γ * Q = max +0.5 * (Lr or S or R)
factored DL=600,000 [lb] load γ * Q ≤ φ * R LL = 60,000 [lb] 1.4 * (D+F) γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) is the maximum computed load, from various load combinations. In these equations, D equals --- …

factored DL=600,000 [lb] dead load γ * Q ≤ φ * R load LL = 60,000 [lb] 1.4 * (D+F) live load γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) the dead load, and L equals the live load. None of the other loads --- …

Find: Lightest I Beam … γ * Q ≤ φ * R γ * Q = max
factored DL=600,000 [lb] dead load γ * Q ≤ φ * R load LL = 60,000 [lb] fluid 1.4 * (D+F) live load load γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) soil are mentioned in the problem statement. Although there are 5 other --- load … rain roof snow load live load load

factored DL=600,000 [lb] dead load γ * Q ≤ φ * R load LL = 60,000 [lb] 1.4 * (D+F) live load γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) load combination equations, we only have to consider the first 2 because they are the most conservative --- 1.2 * D +1.6 *(Lr or S or R) +(f1 * L or 0.8 * W) 1.2 * D * E + f1*L + f2*S

factored DL=600,000 [lb] load γ * Q ≤ φ * R LL = 60,000 [lb] 1.4 * (D+F) γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) when only dead loads and live loads are considered. After plugging in these loads, --- 1.2 * D +1.6 *(Lr or S or R) +(f1 * L or 0.8 * W) 1.2 * D * E + f1*L + f2*S

factored DL=600,000 [lb] load γ * Q ≤ φ * R LL = 60,000 [lb] 1.4 * (D+F) γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) for D and L, the factored load equals the maximum of ---

Find: Lightest I Beam γ * Q ≤ φ * R γ * Q = max γ * Q = max
factored DL=600,000 [lb] load γ * Q ≤ φ * R LL = 60,000 [lb] 1.4 * (D+F) γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) 840,000 pounds and 816,000 pounds, which is, --- 840,000 [lb] γ * Q = max 816,000 [lb]

Find: Lightest I Beam γ * Q ≤ φ * R γ * Q = max γ * Q = max
factored DL=600,000 [lb] load γ * Q ≤ φ * R LL = 60,000 [lb] 1.4 * (D+F) γ * Q = max 1.2 * (D+F+T)+1.6 * (L+H) +0.5 * (Lr or S or R) 840,000 pounds. [pause] The problem states to assume --- 840,000 [lb] γ * Q = max 816,000 [lb] γ * Q = 840,000 [lb]

Find: Lightest I Beam γ * Q ≤ φ * R factored DL=600,000 [lb] load
LL = 60,000 [lb] 840,000 [lb] design fy=50,000 [lb/in2] strength yield failure A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 a yield-type failure, which means the design strength, equals ---

Find: Lightest I Beam γ * Q ≤ φ * R 0.9 factored DL=600,000 [lb] load
LL = 60,000 [lb] resistance 840,000 [lb] fy=50,000 [lb/in2] yield failure A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 0.9 for phi, and the resistance term, R, equals, ---

LL = 60,000 [lb] 840,000 [lb] fy=50,000 [lb/in2] fy * Agross yield failure A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 the yield strength of the steel, f y, times the gross area of the steel beam, ---

LL = 60,000 [lb] 840,000 [lb] fy=50,000 [lb/in2] fy * Agross yield failure yield gross strength area A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 A gross. From the problem statement, we know the yield stress of the steel, equals, ---

LL = 60,000 [lb] 840,000 [lb] fy=50,000 [lb/in2] fy * Agross yield failure yield gross strength area A) W 8 x 58 B) W10x60 C) W12x65 D) W10x68 50,000 pounds per square inch. Therefore, if we simplify this inequality, ---

LL = 60,000 [lb] 840,000 [lb] fy=50,000 [lb/in2] fy * Agross yield failure yield gross strength area and solve for A gross, we learn that the gross area of the I beam, --- 840,000 [lb] ≤0.9 * 50,000 [lb/in2] * Agross

LL = 60,000 [lb] 840,000 [lb] fy=50,000 [lb/in2] fy * Agross yield failure yield gross strength area must be at least 18.7 inches squared. [pause] Looking back at --- 840,000 [lb] ≤0.9 * 50,000 [lb/in2] * Agross 18.7 [in2] ≤ Agross

Find: Lightest I Beam DL=600,000 [lb] A) W 8 x 58 B) W10x60
C) W12x65 D) W10x68 LL = 60,000 [lb] fy=50,000 [lb/in2] yield failure the 4 possible solutions, we can look up the gross area of each I beam, --- 840,000 [lb] ≤0.9 * 50,000 [lb/in2] * Agross 18.7 [in2] ≤ Agross

Find: Lightest I Beam Agross= 17.1 [in2] A) W 8 x 58 B) W10x60
C) W12x65 D) W10x68 Agross= 17.6 [in2] Agross= 19.1 [in2] Agross= 20.0 [in2] and determine the lightest I beam with a gross area at least 18.7 inches squared, is --- 840,000 [lb] ≤0.9 * 50,000 [lb/in2] * Agross 18.7 [in2] ≤ Agross

C) W12x65 D) W10x68 Agross= 17.6 [in2] Agross= 19.1 [in2] Agross= 20.0 [in2] beam W 12 by 65. [pause] Therefore --- 840,000 [lb] ≤0.9 * 50,000 [lb/in2] * Agross 18.7 [in2] ≤ Agross

C) W12x65 D) W10x68 Agross= 17.6 [in2] Agross= 19.1 [in2] Agross= 20.0 [in2] the answer is C. 840,000 [lb] ≤0.9 * 50,000 [lb/in2] * Agross 18.7 [in2] ≤ Agross answerC

Find: Lightest I Beam fy=50,000 [lb/in2] unfactored axial

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Find: Lightest I Beam fy=50,000 [lb/in2] unfactored axial

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Presentation on theme: "Find: Lightest I Beam fy=50,000 [lb/in2] unfactored axial"— Presentation transcript:

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