1. Calorimetry

2. Calorimetry Background
The thermal energy (q) transferred when an object is heated or cooled can be calculated from the following equation:
(1) q = m x c x DT
heat transferred (in joules)
mass of substance (in grams)
specific heat capacity of substance (J/gºC)
temperature change (in ºC) DT = Tf - Ti

3. Calorimetry Background
When two objects such as hot metal and cold water are brought into contact, the heat lost by the hotter object is equal to the heat gained by the cooler object.
(2) qmetal = qwater
The minus sign is necessary since heat loss is an exothermic process (q is negative) while heat gain is an endothermic process (q is positive).

4. Calorimetry Background
Substituting Eqn (1) into Eqn (2) leads to an equation that allows us to calculate the specific heat capacity of a metal by making a few simple temperature measurements.
(3) - (mmetal x Cmetal x DTmetal) = mwater x Cwater x DTwater
Rearranging Eqn (3) leads to:
- mwater x Cwater x DTwater
mmetal x DTmetal
Cmetal =
(4)

5. Calorimetry Drop a hot piece of metal into water
Heat lost by hot metal = heat gained by cold water
TOC

6. Calorimetry Tips
Final temperature of the water and the metal are the same (it reached equilibrium)
If a metal is placed in boiling water, the initial temperature of the metal is 100°C
Water has a special property; 1 : 1 ratio of mass to volume (ie. If I have 10 g of water I have 10 mL of water)
One of the specific heats will always be given to you (either in the problem or in your CRM)
q of the system = q of the surroundings (just opposite charges)

7. 1. A 10. 0 g piece aluminum with an initial temperature of 500
 1. A 10.0 g piece aluminum with an initial temperature of 500.0°C is dropped into a calorimeter with g of water. After reaching equilibrium, the temperature of the water is 50.0°C.
a. How much heat did the aluminum release? Caluminum = J/g°C
b. What was the original temperature of the water? Cwater = J/g°C

8. Problem 2
Calorimetry
A 10.0 g piece of aluminum was placed into 150°C hot water bath for a few minutes. It was then placed into a calorimeter containing mL of 24.15°C water and the temperature increased to 26.20°C. What is the specific heat of the metal?
(remember: Water has a special property of 1:1 mass to volume ratio)