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Published byNorma Nanni Modified over 6 years ago
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Hn is the number of moves to solve.
n = 1, Hn = 1 n = 2, Hn = 3 n = 3, Hn = 7 Hn = 2Hn-1 + 1
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Hn = 2Hn-1 + 1 = 2(2Hn-2 + 1) + 1 = 22Hn … = 2n-1H1 + 2n-2 + 2n-3 + … = 2n-1 + 2n-2 + … = 2n - 1
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Proof: r2 – c1r – c2 = 0 Roots: r12 = c1r1 + c2 r22 = c1r2 + c2 c1an-1 + c2an-2 = c1(α1r1n-1 + α2r2n-1) + c2(α1r1n-2 + α2r2n-2) = α1r1n-2(c1r1 + c2) + α2r2n-2(c1r2 + c2) = α1r1n-2r12 + α2r2n-2r22 = α1r1n + α2r2n = an
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Suppose: a0 = C0, a1 = C1 C0 = α1 + α2 C1 = α1r1 + α2r2 α2 = C0 – α1 C1 = α1r1 + (C0 – α1)r2 = α1(r1 – r2) + C0r2 α1 = (C1 – C0r2)/(r1 – r2) α2 = C0 – α1 = C0 – (C1 – C0r2)/(r1 – r2) = (C0r1 – C1)/(r1 – r2) where r1 ≠ r2
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