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Activating Prior Knowledge
M7:LSN19 Lesson 19: Cones and Spheres Activating Prior Knowledge Find the area of the following right triangle: Bh 2 6(2) 2 = 6mm 2 Tie to LO
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Learning Objective Today, we will use the Pythagorean Theorem to find unknown sides of cylinders and cones, and use formulas to find the volumes of cones and spheres. CFU
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Formulas CFU Concept Development Lesson 19: Cones and Spheres
M7:LSN19 Lesson 19: Cones and Spheres Concept Development Formulas Volume of Cylinder : π½=π©π ππ π½= π
π π π Volume of a Cone: π½= π π π©π or V = π π π
π π π Volume of a Cube: π½=π(π)(π) Volume of a Pyramid: π½= π π π(π)(π) Volume of a Sphere: π½= π π π
π π CFU
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CFU Concept Development Lesson 19: Cones and Spheres
M7:LSN19 Lesson 19: Cones and Spheres Concept Development 1. Determine the volume for each figure below. a. Write an expression that shows volume in terms of the area of the base, π©, and the height of the figure. Explain the meaning of the expression, and then use it to determine the volume of the figure. π½= π
π π π π½=π
(π) π ππ =ππππ
The volume of the cylinder is ππππ
π’ π§ π . The expression π½=π©π means that the volume of the cylinder is found by multiplying the area of the base by the height. The base is a circle whose area can be found by squaring the radius, π π’π§., and then multiplying by π
. The volume is found by multiplying that area by the height of ππ. CFU
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CFU Concept Development Lesson 19: Cones and Shperes
M7:LSN19 Lesson 19: Cones and Shperes Concept Development Write an expression that shows volume in terms of the area of the base, π©, and the height of the figure. Explain the meaning of the expression, and then use it to determine the volume of the figure V = π π π
π π π π½= π π π
π π ππ = πππ π π
=πππ π
The volume of the cone is ππππ
π’ π§ π . The expression π½= π π π©π means that the volume of the cone is found by multiplying the area of the base by the height and then taking one-third of that product. The base is a circle whose area can be found by squaring the radius, π π’π§., and then multiplying by π
. The volume is found by multiplying that area by the height of ππ π’π§. and then taking one-third of that product. CFU
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CFU Concept Development Lesson 19: Cones and Spheres π½=π(π)(π)
M7:LSN19 Lesson 19: Cones and Spheres MP.7 & MP.8 MP.7 & MP.8 Concept Development Write an expression that shows volume in terms of the area of the base, π©, and the height of the figure. Explain the meaning of the expression, and then use it to determine the volume of the figure. π½=π(π)(π) π½=ππ ππ ππ =π,πππ The volume of the prism is π,πππ π’ π§ π The expression π½=π©π means that the volume of the prism is found by multiplying the area of the base by the height. The base is a square whose area can be found by multiplying ππΓππ. The volume is found by multiplying that area, πππ, by the height of ππ. CFU
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CFU Concept Development Lesson 19: Cones and Spheres
M7:LSN19 Lesson 19: Cones and Spheres Concept Development The volume of the square pyramid shown below is πππ π’ π§ π . What might be a reasonable guess for the formula for the volume of a pyramid? What makes you suggest your particular guess? Since πππ= ππππ π , the formula to find the volume of a pyramid is likely π π π©π, where π© is the area of the base. This is similar to the volume of a cone compared to the volume of a cylinder with the same base and height. The volume of a square pyramid is π π of the volume of the rectangular prism with the same base and height. CFU
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CFU Concept Development Lesson 19: Cones and Spheres Exercise 7
M7:LSN19 Lesson 19: Cones and Spheres Concept Development Exercise 7 What is the length of the chord of the sphere shown below? Give an exact answer using a square root. Chord π π π +π π π = π π πππ+πππ= π π πππ= π π πππ = π π π π π Γπ =π ππ π =π The length of the chord is πππ ππ¦, or ππ π ππ¦. CFU
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CFU Concept Development Lesson 19: Cones and Spheres Exercise 8
M7:LSN19 Lesson 19: Cones and Spheres Concept Development Exercise 8 What is the length of the chord of the sphere shown below? Give an exact answer using a square root. π π + π π = π π ππ+ππ= π π ππ= π π ππ = π π π π Γπ =π π π =π The length of the chord is ππ π’π§., or π π π’π§. CFU
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CFU Concept Development Lesson 19: Cones and Spheres Exercise 9
M7:LSN19 Lesson 19: Cones and Spheres Concept Development Exercise 9 What is the volume of the sphere shown below? Give an exact answer using a square root. Let π ππ¦ represent the radius of the sphere π π + π π =π π π π π π =πππ π π =πππ π π = πππ π= πππ π= π π π Γπ π=ππ π CFU
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CFU Exercise 9 Continued Cones and Spheres π½= π π π
π π = π π π
ππ π π
M7:LSN19 Cones and Spheres Exercise 9 Continued π½= π π π
π π = π π π
ππ π π = π π π
π π π π π = π π π
(ππππ) π = π π π
(ππππ) π π Γπ = π π π
(ππππ) π π = ππππ π π π
CFU
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CFU LESSON SUMMARY Lesson 19: Cones and Spheres M7:LSN19
The volume formula for a right square pyramid is π½= π π π©π, where π© is the area of the square base. The lateral length of a cone, sometimes referred to as the slant height, is the side π, shown in the diagram below. Given the lateral length and the length of the radius, the Pythagorean theorem can be used to determine the height of the cone. Let πΆ be the center of a circle, and let π· and πΈ be two points on the circle. Then π·πΈ is called a chord of the circle. The segments πΆπ· and πΆπΈ are equal in length because both represent the radius of the circle. If the angle formed by π·πΆπΈ is a right angle, then the Pythagorean theorem can be used to determine the length of the radius when given the length of the chord, or the length of the chord can be determined if given the length of the radius. CFU
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Closure Homework β Module 7 page 102-104 Problem Set #1-5 CFU
What did we learn today? How do you find the distance between two vertical or horizontal points on a coordinate plane? 3. How do you find the distance between two points on a coordinate plan that are not vertical or horizontal? Homework β Module 7 page Problem Set #1-5 CFU
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