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7.4 Solving factored polynomials
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What We Will Learn Use Zero Product Property
Factor using Greatest Common Factor (GCF) Solve by factoring story problems
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Needed Vocab. Factored form: when polynomial written as a product of its factors Zero Product Property: setting factors of a polynomial equal to zero to solve Roots: solution to a polynomial equation Repeated roots: when two or more answers are the same
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Exs. 1 and 2 Solve using Zero Product Property
2π₯(π₯ β 4) = 0 2π₯=0 2π₯ 2 = 0 2 π₯=0 π₯β4=0 +4 +4 π₯=4 Answers then 0 and 4 Set each factor = to 0 2π₯+7 2π₯β7 =0 2π₯+7= π₯β7=0 β7 β 2π₯=β7 2π₯=7 2π₯ 2 = β π₯ 7 = 7 2 π₯= β7 2 π₯= 7 2
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Exs. 1 and 2 Cont. Your Practice π₯+1 2 π₯β3 2π₯β2
π₯β1 2 =0 π₯β1 2 means π₯β1 π₯β1 π₯β1=0 π₯β1=0 π₯= π₯=1 Repeated root Your Practice π₯ π₯β3 2π₯β2 πππ π€πππ πππ β1, β1, 3, 1 or -1, 3, 1
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Ex. 3 Taking Out Greatest Common Factor
4π₯ π₯ 3 GCF: 4π₯ 3 4π₯ 4 4π₯ π₯ 3 4π₯ 3 4π₯ 3 π₯+6 8π¦ 2 β24π¦ GCF: 8π¦ 8π¦ 2 8π¦ β 24π¦ 8π¦ 8π¦ π¦β3 GCF: biggest number, letter, or combination of both that all terms have in common To find: 1. look for biggest number if there is one 2. look for same variable(s) if there is one Use lowest exponent for GCF To factor out: 1. Put GCF in front of ( ) 2. divide all terms by GCF and put answer in ( )
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Ex. 3 cont. Factor: 5π§ 2 +12π§ GCF: π§ Your Practice Factor:
5π§ 2 π§ + 12π§ π§ π§ 5π§+12 6π₯ 3 +18 GCF: 6 6π₯ 6 π₯ 3 +3 Your Practice Factor: 20π₯ π₯ 2 GCF: 10π₯ 2 20π₯ π₯ π₯ π₯ 2 10π₯ 2 2π₯+3
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Ex. 4 Solve by Factoring 2π₯ 2 =β8π₯ +8π₯ +8π₯ Steps 2π₯ 2 +8π₯=0
+8π₯ +8π₯ 2π₯ 2 +8π₯=0 GCF: 2π₯ 2π₯ 2 2π₯ + 8π₯ 2π₯ 2π₯ π₯+4 =0 2π₯=0 π₯+4=0 π₯= β4 β4 π₯=0 πππ π₯=β4 Steps 1. get = to zero 2. find GCF 3. take out GCF 4. set factors = to zero 5. solve
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Your Practice 3π=0 3π 3 = 0 3 π=0 Solve 2πβ5=0 6π 2 =15π +5 +5
2π=5 2π 2 = 5 2 π= 5 2 So answers are 0 and 5/2 or 2.5 Solve 6π 2 =15π β15π β15π 6π 2 β15π=0 GCF: 3π 6π 2 3π β 15π 3π 3π 2πβ5 =0
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