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7.4 Solving factored polynomials

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Presentation on theme: "7.4 Solving factored polynomials"β€” Presentation transcript:

1 7.4 Solving factored polynomials

2 What We Will Learn Use Zero Product Property
Factor using Greatest Common Factor (GCF) Solve by factoring story problems

3 Needed Vocab. Factored form: when polynomial written as a product of its factors Zero Product Property: setting factors of a polynomial equal to zero to solve Roots: solution to a polynomial equation Repeated roots: when two or more answers are the same

4 Exs. 1 and 2 Solve using Zero Product Property
2π‘₯(π‘₯ βˆ’ 4) = 0 2π‘₯=0 2π‘₯ 2 = 0 2 π‘₯=0 π‘₯βˆ’4=0 +4 +4 π‘₯=4 Answers then 0 and 4 Set each factor = to 0 2π‘₯+7 2π‘₯βˆ’7 =0 2π‘₯+7= π‘₯βˆ’7=0 βˆ’7 βˆ’ 2π‘₯=βˆ’7 2π‘₯=7 2π‘₯ 2 = βˆ’ π‘₯ 7 = 7 2 π‘₯= βˆ’7 2 π‘₯= 7 2

5 Exs. 1 and 2 Cont. Your Practice π‘₯+1 2 π‘₯βˆ’3 2π‘₯βˆ’2
π‘₯βˆ’1 2 =0 π‘₯βˆ’1 2 means π‘₯βˆ’1 π‘₯βˆ’1 π‘₯βˆ’1=0 π‘₯βˆ’1=0 π‘₯= π‘₯=1 Repeated root Your Practice π‘₯ π‘₯βˆ’3 2π‘₯βˆ’2 π‘Žπ‘›π‘ π‘€π‘’π‘Ÿπ‘  π‘Žπ‘Ÿπ‘’ βˆ’1, βˆ’1, 3, 1 or -1, 3, 1

6 Ex. 3 Taking Out Greatest Common Factor
4π‘₯ π‘₯ 3 GCF: 4π‘₯ 3 4π‘₯ 4 4π‘₯ π‘₯ 3 4π‘₯ 3 4π‘₯ 3 π‘₯+6 8𝑦 2 βˆ’24𝑦 GCF: 8𝑦 8𝑦 2 8𝑦 βˆ’ 24𝑦 8𝑦 8𝑦 π‘¦βˆ’3 GCF: biggest number, letter, or combination of both that all terms have in common To find: 1. look for biggest number if there is one 2. look for same variable(s) if there is one Use lowest exponent for GCF To factor out: 1. Put GCF in front of ( ) 2. divide all terms by GCF and put answer in ( )

7 Ex. 3 cont. Factor: 5𝑧 2 +12𝑧 GCF: 𝑧 Your Practice Factor:
5𝑧 2 𝑧 + 12𝑧 𝑧 𝑧 5𝑧+12 6π‘₯ 3 +18 GCF: 6 6π‘₯ 6 π‘₯ 3 +3 Your Practice Factor: 20π‘₯ π‘₯ 2 GCF: 10π‘₯ 2 20π‘₯ π‘₯ π‘₯ π‘₯ 2 10π‘₯ 2 2π‘₯+3

8 Ex. 4 Solve by Factoring 2π‘₯ 2 =βˆ’8π‘₯ +8π‘₯ +8π‘₯ Steps 2π‘₯ 2 +8π‘₯=0
+8π‘₯ +8π‘₯ 2π‘₯ 2 +8π‘₯=0 GCF: 2π‘₯ 2π‘₯ 2 2π‘₯ + 8π‘₯ 2π‘₯ 2π‘₯ π‘₯+4 =0 2π‘₯=0 π‘₯+4=0 π‘₯= βˆ’4 βˆ’4 π‘₯=0 π‘Žπ‘›π‘‘ π‘₯=βˆ’4 Steps 1. get = to zero 2. find GCF 3. take out GCF 4. set factors = to zero 5. solve

9 Your Practice 3𝑛=0 3𝑛 3 = 0 3 𝑛=0 Solve 2π‘›βˆ’5=0 6𝑛 2 =15𝑛 +5 +5
2𝑛=5 2𝑛 2 = 5 2 𝑛= 5 2 So answers are 0 and 5/2 or 2.5 Solve 6𝑛 2 =15𝑛 βˆ’15𝑛 βˆ’15𝑛 6𝑛 2 βˆ’15𝑛=0 GCF: 3𝑛 6𝑛 2 3𝑛 βˆ’ 15𝑛 3𝑛 3𝑛 2π‘›βˆ’5 =0


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